HOC24
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m=4kg; v0=0;F=10N; \(\mu\)=0,3; g=10m/s2; t=4s
Fms=\(\mu.N=\mu.m.g\)=12N
Fhl=\(\left|F_k-F_{ms}\right|\)=2N
Theo DL 2 niutuon: a=\(\dfrac{F_{hl}}{m}\)=0,5m/s2
S=v0t+\(\dfrac{at^2}{2}\)=4m
v=v0+at=2m/s
m=2500N; t=60s; v0=0; v=15m/s; \(\mu\)=0,02; g=10m/s2
a, a=\(\dfrac{v-v_0}{t}\)=0,25m/s2
S=v0t+\(\dfrac{at^2}{2}\)=450m
b, Fk=\(\mu\).N=\(\mu\).m.g=500N
l0=0,4m; l=0,45m; m=0,5kg; g=10m/s2
Vi vat treo thang dung
Co: P=Fdh\(\Leftrightarrow\)mg=K.\(\left|l-l_0\right|\)
\(\Leftrightarrow\)K=100N/m
A: vi am thanh ko the truyen trong moi truong chan ko nen ho phai dung micro va tai nghe
B:khi ho cham vao nhau mu bao ho cua ho vao nhau khi do am thanh co the truyen qua moi truong chat ran cho nen ho co the nghe thay nhau noi
v1=50km/h; v2=36km/h
AD cong thuc: vtb=\(\dfrac{2v_1v_2}{v_1+v_2}\)\(\approx\)41,86km/s\(\approx\)11,63m/s
m=5kg; v0=0; F=30N; \(\mu\)=0,4; g=10m/s2; S=16m
a,Fms=\(\mu.N\)=20N
Fhl=10N
Theo dl 2 niuton: a=\(\dfrac{F_{hl}}{m}\)=2m/s2
b,Co: S= v0t+\(\dfrac{at^2}{2}\)\(\Leftrightarrow\)t=4s
v=v0+at=8m/s
t=1s; g=10m/s2
t=\(\sqrt{\dfrac{2h}{g}}\)\(\Leftrightarrow\)1=\(\sqrt{\dfrac{2h}{10}}\)\(\Rightarrow\)h=5m
Vay khi do cao = 6h
t=\(\sqrt{\dfrac{2h}{g}}\)=\(\sqrt{\dfrac{6\times5}{10}}\)=\(\sqrt{3}\)\(\approx\)1,73s
v0=0; h=125m; g=10m/s2
a, t=\(\sqrt{\dfrac{2h}{g}}\)=5s
v=\(\sqrt{2gh}\)=50m/s
b,qd trong 3s: s=\(\dfrac{1}{2}\)gt2=45m
qd roi trong giay t3: s= 25m
c, \(\Delta\)s=h-st-1=(\(\dfrac{1}{2}\)gt2)-(\(\dfrac{1}{2}\)g(t-1)2=45m
F1=m1g=3N
F2=m2g=4,5N
\(\Delta l_1\)=0,02m
\(\Delta l_2\)=\(\dfrac{F_2\Delta l_1}{F_1}\)=0,03m
v0=5m/s; trong giay thu nhat t=1s; s=12m
a, S=vot+\(\dfrac{at^2}{2}\)\(\Leftrightarrow\)a=14m/s2
b, S=v0t+\(\dfrac{at^2}{2}\)=750m