Ta có : \(\frac{2^7.3^4}{3^3.2^5}=\frac{2^2.3}{1.1}=4.3=12\)

k cho mk nha!

Ta lập biểu thức:

\(\frac{\left(2^7.3^4\right)}{3^3.2^5}=\frac{128.81}{27.32}=\frac{10368}{864}=12\)

Vì khi ta lập biểu thức ra và tính nó sẽ được vậy chứ khong có lí do nha bạn ~~

\(=\frac{2^7\cdot3^4}{3^3\cdot2^5}=\frac{2^2\cdot3}{1\cdot1}=12\)

bằng 0 đún ko

823543 nhé

I don't now

or no I don't

..................

sorry

a)\(\left(\frac{1}{5}\right)^{10}.5^{20}=\left(\frac{1}{5}\right)^{10}.5^{10.2}=\left(\frac{1}{5}\right)^{10}.25^{10}=\left(\frac{1}{5}.5\right)^{10}=1^{10}=1\)

b)\(5^2.3^5.\left(\frac{3}{5}\right)^2=\left(\frac{3}{5}.5\right)^2.3^5=3^2.3^5=3^7\)

c)\(\left(\frac{1}{16}\right)^3:\left(\frac{1}{8}\right)^2=\left(\frac{1}{8}\right)^{2.3}:\left(\frac{1}{8}\right)^2=\left(\frac{1}{8}\right)^{6+2}=\left(\frac{1}{8}\right)^8\)

\(a.\left(\frac{1}{5}\right)^{10}.5^{20}=\left(\frac{1}{5}\right)^{10}.5^{10.2}=\left(\frac{1}{5}\right)^{10}.\left(5^2\right)^{10}=\left(\frac{1}{5}\right)^{10}.25^{10}=\left(\frac{1}{5}.25\right)^{10}=5^{10}.\)

\(b.5^2.3^5.\left(\frac{3}{5}\right)^2=\left[5^2.\left(\frac{3}{5}\right)^2\right].3^5=\left(5.\frac{3}{5}\right)^2.3^5=3^2.3^5=3^7\)\(c.\left(\frac{1}{16}\right)^3:\left(\frac{1}{8}\right)^2=\left[\left(\frac{1}{4}\right)^2\right]^3:\left[\left(\frac{1}{2}\right)^3\right]^2=\left(\frac{1}{4}\right)^6:\left(\frac{1}{2}\right)^6=\left(\frac{1}{4}:\frac{1}{2}\right)^6=\left(\frac{1}{2}\right)^6\)

Hì hì xin lỗi trả lời muộn thông cảm

Ta có; \(\frac{\left(2^3.3^4\right)}{\left(2^2.3^3.5\right)}\Leftrightarrow\frac{\left(2^2.2^1.3^3.3^1\right)}{2^2.3^3.5}\Leftrightarrow\frac{\left(2.3\right)}{5}=\frac{6}{5}\)

Đs: \(\frac{6}{5}\)

k bt lm tự mà làm

rút gọn

mk lớp 5

a,( 3⁹³+3⁹⁰) : (3¹⁷. 3⁷³)

= (3³+1). 3⁹⁰ : 3⁹⁰

= 3³+1

=27+1

=28

b,(5⁵⁶+5⁷) : (5⁴⁹+1)

=5⁷. (5⁴⁹+1) : (5⁴⁹+1)

=5⁷= 78125

c,(7²²+7²¹+7²⁰) ; (2⁵+2⁴+3²)

= 7²⁰. (7²+7¹+1) : [2⁴. (2+1)+3² ]

= 7²⁰. 57 : [ 2⁴. 3 +3² ]

= 7²⁰. 57 :  ( 2⁴+3) . 3

= 7²⁰. 57 :  19 . 3

= 7²⁰. 57 : 57

= 7²⁰