\(=\frac{\left(-1\right)^7}{3^7}.3^7+\left(\frac{1}{8}\right)^3.8^3+\left(\frac{1}{5}\right)^3.\left(2.5\right)^3\)

\(=\left(-1\right)^7+\frac{1^3}{8^3}.8^3+\frac{1^3}{5^3}.2^3.5^3\)

\(=-1+1+2^3=2^3=8\)

2

4

6

ai tích mình mình tích lại cho

2,4.6 nha bạn. Tk mình đi mk vừa tk cho bạn nè

1 + 1 = 2

2 + 2 = 4 

3 + 3 = 6 

hok tốt

= 0,5 ; 0,5 - 0,25 : 0,25 + 0,125 : 0,125 - 0,1 : 0,1

=       1    -        1       +    1                 - 1 

= 0

hahaahahhahahahahhahahaahhhhhhhhhhhhhhhhhhhhhhhhhhhhhhaahahahaahhaahhaahahahahahahaahahhaahahahahahahahahahahahahaahhaahahahh

mình cũng như vậy

a)

\(\begin{array}{l}\frac{{ - 3}}{{10}} - 0,125 + \frac{{ - 7}}{{10}} + 1,125 \\= \left( {\frac{{ - 3}}{{10}} + \frac{{ - 7}}{{10}}} \right) + \left( {1,125 - 0,125} \right)\\ =  - 1 + 1 \\= 0\end{array}\)       

b)

\(\begin{array}{l}\frac{{ - 8}}{3}.\frac{2}{{11}} - \frac{8}{3}:\frac{{11}}{9} \\= \frac{8}{3}.\frac{{ - 2}}{{11}} - \frac{8}{3}.\frac{9}{{11}}\\ = \frac{8}{3}.\left( {\frac{{ - 2}}{{11}} - \frac{9}{{11}}} \right)\\ =\frac{{ - 8}}{3}.\frac{-11}{11}\\= \frac{8}{3}.\left( { - 1} \right) \\= \frac{{ - 8}}{3}\end{array}\)

KBCA11D21

Nhận thấy :

D1ˆ=D2ˆD1^=D2^

Ta có : D1ˆ=90o=B1ˆD1^=90o=B1^

D2ˆ=90o−C1ˆD2^=90o−C1^

→B1ˆ=C1ˆ→B1^=C1^

Xét ΔABKΔABK và ΔACDΔACD

BAKˆ=CADˆ=90oBAK^=CAD^=90o

AB=AC(gt)AB=AC(gt)

B1ˆ=C1ˆB1^=C1^

→ΔABK=ΔACD(g.c.g)→ΔABK=ΔACD(g.c.g)

→AK=AD(đpcm

A)1,1+2,2+3,3+...................+8,8+9,9

=(1,1+9,9)+(2,2+8,8)+..........................+(4,4+6,6)+5,5

= 11+11+11+11+5,5=55+5,5=60,5

b) 1/2:0,5-1/4:0,25+1/8:0,125-1/10:0,1

=1/2 nhân 2-1/4 nhân 4+1/8 nhân  8-1/10 nhân 10

=1-1+1-1=0+0=0

\(a,-\frac{4}{7}+\left(-\frac{2}{3}+\frac{3}{7}\right)=-\frac{4}{7}-\frac{2}{3}+\frac{3}{7}=-\frac{4}{7}+\frac{3}{7}-\frac{2}{3}=-\frac{1}{7}-\frac{2}{3}=-\frac{17}{21}\)

\(b,-\frac{3}{10}\cdot\frac{5}{12}+-\frac{3}{10}\cdot\frac{7}{12}+5\cdot\frac{3}{10}=\frac{3}{10}\cdot-\frac{5}{12}+\frac{3}{10}\cdot-\frac{7}{12}+5\cdot\frac{3}{10}=\frac{3}{10}\cdot\left(-\frac{5}{12}-\frac{7}{12}+5\right)\)

\(=\frac{3}{10}\cdot4=\frac{6}{5}\)

ti ck nha

đúng đó

xin đó

#####

a, -4/7 + (-2/3 + 3/7 )

= -4/7 + (-2/3) + 3/7

= -4/7 + 3/7 + (-2/3)

= -1/7 + -14/21

= -3/21 + -14/21

= -17/21

b, -3/10 . 5/12 + -3/10 . 7/12 + 5. - 3/10

-3/10.(5/12 + 7/12 + 60/12)

-3/10.6

-18/10= -9/5

\(\left(\dfrac{1}{3}-\dfrac{3}{10}\right):\dfrac{3}{5}+\left(\dfrac{2}{3}-\dfrac{7}{10}\right):\dfrac{3}{5}\)
\(=\left(\dfrac{1.10}{3.10}-\dfrac{3.3}{10.3}\right).\dfrac{5}{3}+\left(\dfrac{2.10}{3.10}-\dfrac{7.3}{10.3}\right).\dfrac{5}{3}\)

\(=\left(\dfrac{10}{30}-\dfrac{9}{30}\right).\dfrac{5}{3}+\left(\dfrac{20}{30}-\dfrac{21}{30}\right).\dfrac{5}{3}\)

\(=\dfrac{1}{30}.\dfrac{5}{3}-\dfrac{1}{30}.\dfrac{5}{3}\)

\(=\dfrac{5}{3}.\left(\dfrac{1}{30}-\dfrac{1}{30}\right)\)

\(=\dfrac{5}{3}.0\)

\(=0\)

giúp mik với

0

\(\frac{-4}{7}+\left(\frac{-2}{3}+\frac{4}{7}\right)\)

\(=\frac{-4}{7}+\frac{-2}{3}+\frac{4}{7}\)

\(=\left(\frac{-4}{7}+\frac{4}{7}\right)+\frac{-2}{3}\)

\(=0+\frac{-2}{3}=\frac{-2}{3}\)

~ Hok tốt ~

\(\frac{-3}{10}.\frac{5}{12}+\frac{-3}{10}.\frac{7}{12}+5\frac{3}{10}\)

\(=\frac{-3}{10}.\frac{5}{12}+\frac{-3}{10}.\frac{7}{12}+\frac{53}{10}\)

\(=\frac{-3}{10}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{53}{10}\)

\(=\frac{-3}{10}.1+\frac{53}{10}\)

\(=\frac{-3}{10}+\frac{53}{10}=\frac{50}{10}=5\)

~ Hok tốt ~