cm: f(x)+f(x-1)=1

=>A=55

55

mk ko bít làm bn ak?

nếu muốn bn đợi mk 2 năm nữa

123456

chtt

k 

nhé 

bn

9849/100 nhé, đáp án chuẩn 100%, nếu bạn cần có cách làm thì nhắn tin cho mik nghe

Ta có:\(f\left(x\right)-1=\left(x-1\right)^3\)

\(=>A+\frac{1}{2}=\left(\frac{1}{112}-1\right)^3+\left(\frac{2}{112}-1\right)^3+\left(\frac{3}{112}-1\right)^3+...\left(\frac{111}{112}-1\right)^3\)

\(A+\frac{1}{2}=-\frac{1^3+2^3+3^3+...+111^3}{112^3}=-\frac{\frac{111^2\left(111+1\right)^2}{4}}{112^3}=-\frac{111^2}{4\cdot112}=-\frac{12321}{448}\)

\(A=-\frac{12321}{448}-\frac{1}{2}=-\frac{12545}{448}\)

à nhầm :v

cho \(a\)và \(1-a\), ta có:

\(f\left(1-a\right)=\frac{\left(1-a\right)^3}{3\left(1-a\right)^2-3\left(1-a\right)+1}=\frac{\left(1-a-1\right)^3}{3-6a+a^2-3+3a+1}+1=1-\frac{a^3}{3a^3-3a+1}=1-f\left(a\right)\)

hay \(f\left(a\right)+f\left(1-a\right)=1\)

\(=>A=f\left(\frac{1}{112}\right)+f\left(\frac{111}{112}\right)+f\left(\frac{2}{112}\right)+f\left(\frac{110}{112}\right)+...+f\left(\frac{55}{112}\right)+f\left(\frac{57}{112}\right)+f\left(\frac{56}{112}\right)-\frac{1}{2}\)

\(=>A=55+f\left(\frac{1}{2}\right)-\frac{1}{2}=55\) vì  \(f\left(\frac{1}{2}\right)+f\left(\frac{1}{2}\right)=2f\left(\frac{1}{2}\right)=1\)nên \(f\left(\frac{1}{2}\right)=\frac{1}{2}\)

Vậy \(A=55\)

112(56+46-2)=112 x 100 = 11200

112 x 56 + 112 x 46 - 112 x 2

122 x ( 56 + 46 - 2 )

122 x 100

12200

= 112 x ( 56 + 46 - 2 )

= 112 x 100

= 11200

Tìm x?

ukm

`2^(x-1) + 2^x +2^(x+1)  = 112 `

`=> 2^(x-1) + 2^(x-1) xx 2 +2^(x-1) xx 2^2  = 112 `

`=> 2^(x-1) . (1 + 2 + 2^2)   = 112 `

`=> 2^(x-1) . 7   = 112 `

`=> 2^(x-1) = 16`

`=>  2^(x-1) = 2^4`

`=> x - 1 = 4`

`=> x = 5`

đề yêu cầu gì vậy ạ?

112+(3x+1)⁵=12²

112+(3x+1)⁵= 144

(3x+1)⁵=144-112

(3x-1)⁵=32

suy ra ( 3x-1)⁵=2⁵

3x-1=2

3x=2+1

3x=3

suy ra x=1

vậy x=1