(\(x+2\))[\(x+1\)] = 2626020

(\(x+2\))[\(x+1\)] = 1621 x 1620

\(x+1\) = 1620

\(x=1620-1\)

\(x\) = 1619

Vậy \(x=1619\)

a: =11/4+5/4-9/8

=4-9/8=32/8-9/8=23/8

b: \(=\dfrac{6}{7}\cdot\dfrac{7}{4}+\dfrac{5}{3}=\dfrac{3}{2}+\dfrac{5}{3}=\dfrac{9+10}{6}=\dfrac{19}{6}\)

c: \(=\dfrac{13}{18}\cdot\dfrac{9}{5}-1=\dfrac{13}{10}-1=\dfrac{3}{10}\)

d: \(=3+\dfrac{9}{4}\cdot\dfrac{5}{3}=3+\dfrac{45}{12}=\dfrac{81}{12}=\dfrac{27}{4}\)

`a)11/4+5/4-9/8=4-9/8=32/8-9/8=23/8`

`b)6/7 xx 7/4+5/3=3/2+5/3=9/6+10/6=19/6`

`c)13/18xx9/5−1=13/10−1=3/10`

`d)3+9/4xx5/3=3+45/12=27/4`

[6: 3/5 - 7/6 x 6/7] : [ 21/5 x 10/11 + 57/11]

= 9 : 9

= 1 

\(\left(6:\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}\right):\left(\frac{21}{5}\times\frac{10}{11}+\frac{57}{11}\right)\)

\(=\left(10-1\right):\left(\frac{42}{11}+\frac{57}{11}\right)\)

\(=9:9\)

\(=1\)

\(\left(6\div\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}\right)\div\left(\frac{21}{5}\times\frac{10}{11}+\frac{57}{11}\right)\)

\(=\left(6\times\frac{5}{3}-1\right)\div\left(\frac{42}{11}+\frac{57}{11}\right)\)

\(=\frac{13}{5}\div9\)

\(=\frac{13}{45}\)

ket qua la 96

19 bn nha

19 chuổn luôn thể 

1. \(x^2+2y^2+2xy-2y+1=0\)

\(\left(x+y\right)^2+y^2-2y+1=0\)

\(\left(x+y\right)^2+\left(y-1\right)^2=0\)

Có: \(\left(x+y\right)^2\ge0;\left(y-1\right)^2\ge0\)

Mà theo bài ra: \(\left(x+y\right)^2+\left(y-1\right)^2=0\)

\(\Rightarrow\hept{\begin{cases}\left(x+y\right)^2=0\\\left(y-1\right)^2=0\end{cases}}\Rightarrow\hept{\begin{cases}x+y=0\\y-1=0\end{cases}}\Rightarrow\hept{\begin{cases}x+y=0\\y=1\end{cases}}\Rightarrow\hept{\begin{cases}x=-1\\y=1\end{cases}}\)

TL:

2x = 7/8 : 3/4

2x = 7/6

x = 7/6 : 2

x = 7/12

~ HT ~

Xx(\(\frac{3}{4}\)+1)=\(\frac{7}{8}\)

Xx\(\frac{7}{4}\)=\(\frac{7}{8}\)

X           =\(\frac{7}{8}\):\(\frac{7}{4}\)

X           =\(\frac{7}{8}\)x\(\frac{4}{7}\)

X           =\(\frac{1}{2}\)

TL ;

x = 7/12 nha

HT

a) 305 - 5x = 290

5.(61-x) = 290

61-x = 58

x = 3

b) (3x - 2⁴) .2⁵ = 2⁶

3x - 2⁴ = 2

3x = 18

x=6

c) 8 + 3.(x-5)² = 35

3.(x-5)² = 27

(x-5)² = 9 = 3² = (-3)²

=> x - 5 = 3 => x = 8

x-5 = - 3 => x = 2

KL:>.

d) 21 chia hết cho x - 2 

\(\Rightarrow x-2\inƯ_{\left(21\right)}=\left\{\pm1;\pm3;\pm7;\pm21\right\}.\)

..

rùi bn tự lập bảng xét giá trị nhé