\(\left(3x-2\right)^5=-243\)

\(\left(3x-2\right)^5=-3^5\)

\(=>3x-2=-3\)

\(=>3x=-3+2\)

\(=>3x=-1\)

\(=>x=-\frac{1}{3}\)

Vậy \(x=-\frac{1}{3}\)

(3x-2)^5=-243=-3^5

=>3x-2=-3

=>x=-1/3

Tick mik nha Tuấn Chu

Đề trước đó: 

(x-7)(x+1)-(x-3)^2=(3x-5)(3x+5)-(3x+1)^2+(x-2)^2-x

<=>x^2+x-7x-7-x^2+6x-9=9x^2-25-9x^2-6x-1+x^2-4x+4-x

<=>x^2-11x-6=0

<=>x^2-2x. 11/2 + 121/4-145/4=0

<=>(x-11/2)^2=145/4

<=>|x-11/2|=căn(145)/2

<=>x=[11+-căn(145)]/2

a) \(E=|3x-7|+|3x+2|+8\)

\(E=|7-3x|+|3x+2|+8\)

Do : \(|a|\ge a\)

\(\Rightarrow E_{min}\text{=}7-3x+3x+2+8\)

\(\Rightarrow E_{min}\text{=}17\)

Dấu '' = '' xảy ra : \(\Leftrightarrow\dfrac{-2}{3}\le x\le\dfrac{7}{3}\)

đáp án A là đáp án đúng

B là câu trả lời đug đó bạn

Ta có: \(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=\left(x+2\right)-\left(x-5\right)\)

\(\Leftrightarrow6x^2+21x-2x-7-6x^2+5x-6x+5=x+2-x+5\)

\(\Leftrightarrow18x-2=7\)

\(\Leftrightarrow18x=9\)

hay \(x=\dfrac{1}{2}\)

tra gg

Lên  gg

3x 7/10+ 7/10x 5+ 2x 7/10 = 7

(x + 2)² - (3x - 1)²

= (x + 2 - 3x + 1)(x + 2 + 3x - 1)

= (-2x + 3)(4x + 1)