x^3+x^2-2x-8

= (x-2)(x^2+3x+4)

nah bạn chúc bạn học tốt nha 

     x³ + x² - 2x - 8

=  ( x³ - 8 ) + ( x² - 2x )

=  ( x - 2 ) . ( x² + 2x + 4 ) + x ( x - 2 )

= ( x - 2 ) .( x² + 2x + 4 + x )

= ( x-2 ) . ( x² + 3x + 4 ) 

x^3+x^2-2x-8

= (  x^3 - 8) + ( x^2 - 2x )

= (  x - 2)( x^2 + 2x + 4) + x( x - 2 )  

=(  x - 2)( x^2 + 2x + 4 + x)  

=(  x - 2)( x^2 + 3x + 4 )  

\(x^3-8+2x\left(x-2\right)\\ =\left(x-2\right)\left(x^2+2x+4\right)+2x\left(x-2\right)\\ =\left(x-2\right)\left(x^2+2x+4+2x\right)=\left(x-2\right)\left(x^2+4x+4\right)\\ =\left(x-2\right)\left(x+2\right)^2\)

=\(\left(x-2\right)\left(x^2+2x+4\right)+2x\left(x-2\right)\)

=\(\left(x-2\right)\left(x^2+4x+4\right)\)

=\(\left(x-2\right)\left(x+2\right)^2\)

x^2+2x-8

=x^2+2x+1-9

=(x+1)^2-9

=(x+1-3)(x+1+3)

=(x-2)(x+4)

a: \(x^4-2x^3+x^2-2x\)

\(=\left(x^4-2x^3\right)+\left(x^2-2x\right)\)

\(=x^3\left(x-2\right)+x\left(x-2\right)\)

\(=x\left(x-2\right)\left(x^2+1\right)\)

b: \(x^4+x^3-8x-8\)

\(=\left(x^4+x^3\right)-\left(8x+8\right)\)

\(=x^3\left(x+1\right)-8\left(x+1\right)\)

\(=\left(x+1\right)\left(x^3-8\right)\)

\(=\left(x+1\right)\left(x-2\right)\left(x^2+2x+4\right)\)

Bài 1 :

\(x^2-6x+8=x^2-2x-4x+8=x\left(x-2\right)-4\left(x-2\right)=\left(x-4\right)\left(x-2\right)\)

Bài 2 :

 \(x^8+x^7+1=x^8+x^7+x^6+x^5+x^4+x^3+x^2+x+1-x^6-x^5-x^4-x^3-x^2-x\)

\(=x^6\left(x^2+x+1\right)+x^3\left(x^2+x+1\right)+x^2+x+1-x^4\left(x^2+x+1\right)-x\left(x^2+x+1\right)\)

=\(\left(x^2+x+1\right)\left(x^6+x^3+1-x^4-x\right)\)

Tick đúng nha 

X^2-6+8

\(x^3+x^2+2x+8\)

\(=x^3+2x^2-x^2-2x+4x+8\)

\(=x^2\left(x+2\right)-x\left(x+2\right)+4\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2-x+4\right)\)

a: \(x^4+x^2+2x+6\)

\(=x^4-2x^3+3x^2+2x^3-4x^2+6x+2x^2-4x+6\)

\(=\left(x^2-2x+3\right)\left(x^2+2x+2\right)\)