Tìm \(x\) biết \(4^{x+1}-2^{2x}-4^{x+2}+5.2^{2x+2}=112\)
Tìm x biết
1. 2(5x-8)-3(4x-5)=4(3x-4)+11
2. (2x+1)2-(4x-1).(x-3)-15=0
3. (3x-1).(2x-7)-(1-3x).(6x-5)=0
1) \(\Rightarrow10x-16-12x+15=12x-16+11\)
\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)
2) \(\Rightarrow4x^2+4x+1-4x^2+13x-3-15=0\)
\(\Rightarrow17x=17\Rightarrow x=1\)
3) \(\Rightarrow\left(3x-1\right)\left(2x-7+6x-5\right)=0\)
\(\Rightarrow\left(2x-3\right)\left(3x-1\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
2: Ta có: \(\left(2x+1\right)^2-\left(4x-1\right)\left(x-3\right)-15=0\)
\(\Leftrightarrow4x^2+4x+1-4x^2+12x+x-3-15=0\)
\(\Leftrightarrow17x=17\)
hay x=1
Bài 2: Tìm x, biết:
a/ 12x(x – 5) – 3x(4x - 10) = 120
b/ 9x(x + 4) – 5x(3x + 2) = 112 - 2x(3x + 1)
c/ 3x(1 – x) - 5x(3x + 7) = 154 + 9x(5 – 2x)
$ a/ 12x(x – 5) – 3x(4x - 10) = 120$
`<=>12x^2-60x-12x^2+30x=120`
`<=>-30x=120`
`<=>x=-4`
Vậy `x=-4`
$b/ 9x(x + 4) – 5x(3x + 2) = 112 - 2x(3x + 1)$
`<=>9x^2+36x-15x^2-10x=112-6x^2-2x`
`<=>-6x^2+26x=112-6x^2-2x`
`<=>28x=112`
`<=>x=4`
Vậy `x=4`
$c/ 3x(1 – x) - 5x(3x + 7) = 154 + 9x(5 – 2x)$
`<=>3x-3x^2-15x^2-35x=154+45x-18x^2`
`<=>-32x-18x^2=154+45x-18x^2`
`<=>77x=-154`
`<=>x=-2`
Vậy `x=-2`
Tìm x biết :1)-2/3(x-1/4)=1/3(2x-1)
2)1/5.2x+1/3.2x+1=1/5.2x+1+1/3.28
1) \(-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2x-1\right)\)
\(-\frac{2}{3}x+\frac{1}{6}=\frac{2}{3}x-\frac{1}{3}\)
\(-\frac{2}{3}x-\frac{2}{3}x=-\frac{1}{3}-\frac{1}{6}\)
\(-\frac{4}{3}x=-\frac{1}{2}\)
\(x=\left(-\frac{1}{2}\right):\left(-\frac{4}{3}\right)\)
\(x=\frac{3}{8}\)
Tìm 3 số x,y,z biết:
a)x/2=y/5=z/4 và 2x-3y+z=-112
b)x/2=y/3;y/4=z/5 và 2x+3y-4z=-16
a) \(\frac{x}{2}=\frac{y}{5}=\frac{z}{4}\)
Áp dụng tính chất dãy tỉ số bằng nhau , ta có:
\(\frac{x}{2}=\frac{y}{5}=\frac{z}{4}=\frac{2x}{4}=\frac{3y}{15}=\frac{z}{4}=\frac{2x-3y+z}{4-15+4}=\frac{112}{7}=16\)
\(\frac{x}{2}=16=>x=32\)
\(\frac{y}{5}=16=>x=80\)
\(\frac{z}{4}=16=>z=64\)
Câu b) tương tự chỉ cần thay số vào nha bạn
a) 156-(x+61)=82 b) (x-35)-120=0 c) 124-(x-118)=217 d) 2x-49=5.3^2 e) 200-(2x+6)=4^3 f) 2(x-51)=2.2^3+20 g) 4(x-3)=7^2-1^10 h) 3^2(x+4)-5^2=5.2^2 i) 9^x-1=9
Tim x
a,-2/3(x-1/4)=1/3(2x-1)
b,1/5.2^x +1/3.2^x+1=1/5.2^7 +1/3.2^8
giup mink ai nhanh tick 3 lan nghia la 1 lan tra loi mot lan noi lam rui mot lan noi cam on
Tìm x: \(4^x+5.2^{2x+1}=176\)
\(4^x+5.2^{2x+1}=176\)
\(4^x+5.4^x.2=176\)
\(4^x.\left(1+10\right)=176\)
\(4^x=176:11\)
\(4^x=16\)
\(4^x=4^2\)
\(=>x=2\)
\(4^x+5.2^{2x+1}=176\)
\(\Rightarrow2^{2x}+5.2^{2x}.2=176\)
\(\Rightarrow2^{2x}\left(1+10\right)=176\)
\(\Rightarrow2^{2x}.11=176\)
\(\Rightarrow2^{2x}=16\)
\(\Rightarrow2^{2x}=2^4\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
\(4^x+5.2^{2x+1}=176\\ 4^x+5.2^{2x}.2=176\\ 4^x+5.4^x.2\\ 4^x+4^x.10=176\\ 4^x.\left(10+1\right)=176\\ 4^x=176:11\\ 4^x=16\\ 4^x=4^2\\ x=2\)
Tìm x;y biết:
\((2x-1)^2+|2y-x|-8=12-5.2^2\)
Ta có :
12 - 5.22 = -8
Lại có :
( 2.x - 1 )2 \(\ge\)0
| 2.y - x | \(\ge\)0
=> A = ( 2.x - 1 )2 + | 2.y - x | - 8 \(\ge\)- 8
Dấu " = " xảy ra khi :
2.x - 1 = 0
2.y - x = 0
=> x = 0.5; y = 0.25
tìm x,biết: 2^3x+5+5.2^x+1.2^2x+3+2^3x=904
-2/3.(x-4)=1/3.(2x-1)
1/5.2x+1/3.2x+1=1/5.27+1/3.28