\(\Leftrightarrow\left[3x+6-23\right]\cdot\left(9-8+20\cdot0\right)=147\)

=>3x=164

hay x=164/3

Quy đồng : \(\dfrac{20}{80}>x>\dfrac{16}{80}\)

Giá trị của x là : \(\dfrac{19}{80};\dfrac{18}{80};\dfrac{17}{80}\)

giúp mình với

a. x + 3/10= 25/8

x = 25/8-3/10

x = 113/40

b. x/35 = 4/5-5/7

x/35 = 3/35

vậy x=3

\(x+\dfrac{3}{10}=4-\dfrac{7}{8}\)

\(x+\dfrac{3}{10}=\dfrac{25}{8}\)

        \(x=\dfrac{25}{8}-\dfrac{3}{10}\)

       \(x=\dfrac{113}{40}\)

\(\dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\)

        \(\dfrac{x}{35}=\dfrac{4}{5}-\dfrac{5}{7}\)

        \(\dfrac{x}{35}=\dfrac{3}{35}\)

    =>x=3

\(\Leftrightarrow\left\{{}\begin{matrix}2x-3>=-5\\2x-3< =5\end{matrix}\right.\Leftrightarrow-1< =x< =4\)

help me , giúp mình với 

7 nha  

HT

Giải:

B=1,4 .15/49 - (4/5+2/3) :2 1/5

B=7/5.15/49 - 22/15 : 11/5

B=3/7 - 2/3

B=-5/21

Chúc bạn học tốt!

77/45

7/6

29/10

\(\dfrac{3}{5}+\dfrac{4}{3}\times\dfrac{5}{6}=\dfrac{3}{5}+\dfrac{10}{9}=\dfrac{27}{45}+\dfrac{50}{45}=\dfrac{77}{45}\)

\(2-\dfrac{7}{6}+\dfrac{1}{3}=\dfrac{12}{6}-\dfrac{7}{6}+\dfrac{2}{6}=\dfrac{7}{6}\)

\(\dfrac{7}{6}\times3-\dfrac{3}{5}=\dfrac{7}{2}-\dfrac{3}{5}=\dfrac{35}{10}-\dfrac{6}{10}=\dfrac{29}{10}\)

giải chi tiết đi

a) \(\dfrac{3}{5}\times x=\dfrac{4}{7}\)

            \(x=\dfrac{4}{7}\div\dfrac{3}{5}\)

            \(x=\dfrac{20}{21}\)

b) \(\dfrac{1}{8}\div x=\dfrac{1}{5}\)

           \(x=\dfrac{1}{8}\div\dfrac{1}{5}\)

          \(x=\dfrac{5}{8}\)

20/21

5/8

20/21

5/8

P=x2−4x+5

  =x2−4x+4+1

  =(x−2)2+1≥1

⇒Pmin=1 khi x=2

giúp mình đi mọi người T.T

a) x = 6/5 - 5/6

    x =  11/30

vậy x =...

b) x = 13/4 - 3/5 

    x = 53/20

vậy x =...

a. x=6/5-5/6=11/30

b.13/4-3/5=53/20