(9x+1)-(96-33)=10
Tìm x
Tìm số tự nhiên x biết :
a) 541 + ( 281 - x ) =735
b) 5.(x+35) = 515
c) 96 - 3.( 9x+1) =42
d) 12x - 33 = 3 mũ 2 . 3 mũ 3
a) 541 + ( 281 - x ) =735
=>281-x=735-541
=>281-x=194
=>x=87
b)5.(x+35) = 515
=>x+35=515:5
=>x+35=103
=>x=68
c)96 - 3.( 9x+1) =42
=>3(9x+1)=96-42
=>3(9x+1)=54
=>9x+1=18
=>9x=17
=>x=17/9
d)12x-33=32*33
=>12x-33=9*27
=>12x-33=243
=>12x=276
=>x=23
a) \(541+\left(281-x\right)=735\)
\(\Rightarrow281-x=735-541\)
\(\Rightarrow x=281-194\)
\(\Rightarrow x=87\)
b) \(5\cdot\left(x+35\right)=515\)
\(\Rightarrow x+35=515:5\)
\(\Rightarrow x=103-35\)
\(\Rightarrow x=68\)
c) \(96-3\cdot\left(9x+1\right)=42\)
\(\Rightarrow3\cdot\left(9x+1\right)=96-42\)
\(\Rightarrow9x+1=54:3\)
\(\Rightarrow9x=18-1\)
\(\Rightarrow x=17:9\)
\(\Rightarrow x=\frac{17}{9}\)
d) \(12x-33=3^2\cdot3^3\)
\(=12x-33=243\)
\(\Rightarrow12x=243+33\)
\(\Rightarrow x=276:12\)
\(\Rightarrow x=23\)
Tìm số nguyên x, biết:
a) 5x - 14 = x-34
b) x-3-(3x+2)=-15
c) 2(x-12)+19=x+(-34)
d) 2(x-33) - 3(x-43) =96 - 115
e) 2x+3-9x = -11
f) -(x+3-84)=(x+70-71) - 6
a) 5x - 14 = x - 34
5x - x = -34 + 14
4x = -20
x = -20 : 4
x = -5
b) x - 3 - (3x + 2) = -15
x - 3 - 3x - 2 = -15
x - 3x = -15 + 3 + 2
-2x = -10
x = (-10) : (-2)
x = 5
c) 2(x - 12) + 19 = x + (-34)
2x - 24 + 19 = x + (-34)
2x - x = -34 + 24 - 19
x = -29
d) 2(x - 33) - 3(x - 43) = 96 - 115
2x - 66 - 3x + 129 = 96 - 115
2x - 3x = 96 - 115 + 66 - 129
-x = -82
x = 82
e) 2x + 3 - 9x = -11
2x - 9x = -11 - 3
-7x = -14
x = (-14) : (-7)
x = 2
f) -(x + 3 - 84) = (x + 70 - 71) - 6
-x - 3 + 84 = x + 70 - 71 - 6
-x - x = 70 - 71 - 6 - 84
-2x = -91
x = (-91) : (-2)
x = 45,5
Tìm số tự nhiên x biết:
a) 25 + 7x = 144
b) 33 - 12x = 9
c) 128 - 3(x + 4) = 23
d) 71 + (726 - 3x).5 = 2246
e) 720 : [41 - (2x + 5)] = 40
f) (10 - 4x) + 120 : 8 = 16 + 1
g) x + 9x + 7x + 5x = 2244
h) (x + 1) + (x + 2) + (x + 3) +...+ (x + 100) = 5750
i) 1 + 2 + 3 +...+ x = 500500
j) 51 + 52 + 53 +...+ x = 18825
a: Ta có: \(7x+25=144\)
\(\Leftrightarrow7x=119\)
hay x=17
b: Ta có: \(33-12x=9\)
\(\Leftrightarrow12x=24\)
hay x=2
c: Ta có: \(128-3\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=105\)
\(\Leftrightarrow x+4=35\)
hay x=31
d: Ta có: \(71+\left(726-3x\right)\cdot5=2246\)
\(\Leftrightarrow5\left(726-3x\right)=2175\)
\(\Leftrightarrow726-3x=435\)
\(\Leftrightarrow3x=291\)
hay x=97
e: Ta có: \(720:\left[41-\left(2x+5\right)\right]=40\)
\(\Leftrightarrow41-\left(2x+5\right)=18\)
\(\Leftrightarrow2x+5=23\)
\(\Leftrightarrow2x=18\)
hay x=9
f: Ta có: \(10-4x+120:8=16+1\)
\(\Leftrightarrow4x=17-25=-8\)
hay x=-2
g: Ta có: \(x+9x+7x+5x=2244\)
\(\Leftrightarrow22x=2244\)
hay x=102
h: Ta có: \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(\Leftrightarrow100x+5050=5750\)
\(\Leftrightarrow100x=700\)
hay x=7
(9x - 2³) : 5=2
3x . [ 8² -2 .( 2⁵-1)]=2022
[ 3⁴ - ( 8² +14) :13] . x=5²+10²
2²: ( 6x - 3²) - 3 = 33
(9\(x\) - 23) : 5 = 2
9\(x\) - 8 = 2 x 5
9\(x\) - 8 = 10
9\(x\) = 18
\(x\) = 2
3\(x\) .(82 - 2.(25 - 1)] = 2022
3\(x\) .(64 - 2.31) = 2022
3\(x\).(64 - 62) = 2022
3\(x\).2 = 2022
\(x\) = 2022 : 2
\(x\) = 1011
[ 34 - (82 + 14):13]. \(x\) = 52 + 102
[81 - 78:13].\(x\) = 125
75.\(x\) = 125
\(x\) = 125: 75
\(x\) = \(\dfrac{5}{3}\)
Tìm các số nguyên x,y thỏa mãn \(\sqrt{9x^2+16x+96}+16y=3x-24\)
\(\Leftrightarrow\sqrt{9x^2+16x+96}=3x-16y-24\)
Vế phải nguyên \(\Rightarrow\) vế trái nguyên
\(\Rightarrow9x^2+16x+96=k^2\)
\(\Rightarrow81x^2+144x+864=\left(3k\right)^2\)
\(\Leftrightarrow\left(9x+8\right)^2+800=\left(3k\right)^2\)
\(\Leftrightarrow\left(3k-9x-8\right)\left(3k+9x+8\right)=800\)
Pt ước số thật kinh dị với số ước của 800
Ta có \(9x^2+16x+96=\left(3x-24-16y\right)^2\)
\(\Leftrightarrow9x^2+16x+96=9x^2-6x\left(16y+24\right)+\left(16y+24\right)^2\)\(\Leftrightarrow16x+96=\left(16y+24\right)\left(16y+24-6x\right)\)
\(\Leftrightarrow8\left(2x+12\right)=4\left(4y+6\right).2\left(8y+12-3x\right)\)
\(\Leftrightarrow2x+12=\left(4y+6\right)\left(8y+12-3x\right)\)\(\Leftrightarrow2x+12=32y^2+48y-12xy+48y+72-18x\)
\(\Leftrightarrow32y^2+96y-12xy-20x+60=0\)\(\Leftrightarrow32y^2+96y+60=12xy+20x\)\(\Leftrightarrow8y^2+24y+15=3xy+5x\)
\(\Leftrightarrow8y^2+24y+15=x\left(3y+5\right)\)\(\Leftrightarrow x=\dfrac{8y^2+24y+15}{3y+5}\)
\(\Leftrightarrow9x=\dfrac{9\left(8y^2+24y+15\right)}{3y+5}=\dfrac{72y^2+216y+135}{3y+5}\)\(=\dfrac{\left(72y^2+120y\right)+\left(96y+160\right)-25}{3y+5}\)\(=24y+32-\dfrac{25}{3y+5}\)
\(\Leftrightarrow24y+32-\dfrac{25}{3y+5}\in Z\)\(\Rightarrow3y+5\in U\left(25\right)=\left\{\pm1,\pm5,\pm25\right\}\)\(\Leftrightarrow3y\in\left\{-4,-6,-10,0,-30,20\right\}\)\(\Rightarrow y\in\left\{-2,-10,0\right\}\)
+) Với y=-2=> x=1
+) với y=-10=> x=-23
Vậy pt cho 2 cặp (x,y) nguyên =(1,-2),(-23,-10)
a 96 - 3 . x +1 = 42
b 15x - 9x + 2x = 72
c 3x+2 + 3x = 10
làm bài đầy đủ
a,\(96-3x+1=42\)
<=> 97-3x=42
<=> 3x=55
<=>x=\(\frac{55}{3}\)
vậy.......
b, 15x-9x+2x=72
<=>8x=72
<=>x=9
vậy.....
c,\(3^{x+2}+3^x=10\)
\(\Leftrightarrow3^x\left(3^2+1\right)=10\)
\(\Leftrightarrow3^x=1\)
\(\Leftrightarrow x=0\)
vậy........
a 96 - 3 . x +1 = 42
96-3.x= 42-1
96 - 3 . x = 41
3.x= 96-41
3.x= 55
x= 55 : 3
x= \(\frac{55}{3}\)
b, 15x - 9x + 2x = 72
x.( 15-9+2) = 72
x8=72
x=72:8
x=9
c, 3x+2 + 3x = 10
\(\Rightarrow3^x.9+3^x=10\)
\(\Rightarrow3^x.10=10\)
\(\Rightarrow3^x=1\)
\(\Rightarrow x=0\)
a)96-3.x+1=42
3.x+1=96-42
3.x+1=54
x+1=54:3
x+1=18
x=18-1
x=17
Tìm số tự nhiên X, biết:
Câu 1. 96-3(X+1)=42.Tìm X
Câu 2. 12X-33=32.33
96 - 3( x + 1 ) = 42
3( x + 1 ) = 96 - 42
3( x + 1 ) = 54
x + 1 = 54 : 3 = 18
x = 18 - 1
x = 17
cau 1
96-3(x+1)=42
=> 3(x-1)=54
=> x-1=18
=> x=19
cau 2
12x-33=32.33
=> 12x-33=243
=> 12x=276
=> x=23
12x - 33 = 32 . 33
12x - 33 = 35 = 243
12x = 243 + 33
12x = 276
x = 276 : 12
x = 23
Tìm x:
a, 96-3.(x+1)=42
b, 12x-33=32.33
Tìm x:
a, 96 - 3 . ( x + 1 ) = 42
3 . ( x + 1 ) = 96 - 42
3 . ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 -1
x = 17
b, 12x - 33 = 32.33
12x - 33 =9 . 27
12x - 33 = 243
12x = 243 + 33
12x = 276
x=276:12
x=23
a, 96 - 3 . ( x + 1 ) = 42
3 . ( x + 1 ) = 96 - 42
3 . ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 - 1
x = 17
b, 12x - 33 = 32 . 33
12x - 33 = 9 . 27
12x - 33 = 243
12x = 243 + 33
12x = 276
x = 276 : 12
x = 23
a)96-3.(x+1)=42
3.(x+1) = 96 - 42
3 . (x+1) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18-1
x = 17
Tìm x
A 54+(218-x)=735
B 96-3(x+1)=42
C 5(x+35)=515
D 12x-33=3^2.3^2
a) 54 + ( 218 - x ) = 735
218 - x = 735 - 34
218 - x = 701
x = 218 - 701
x = -483
b) 96 - 3 ( x + 1 ) = 42
3 ( x + 1 ) = 96 - 42
3 ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 - 1
x = 17
c) 5 ( x + 35 ) 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
d) 12x - 33 = 32 . 32
12x - 33 = 9.9
12x - 33 = 81
12x = 81 + 33
12x = 114
x = 114 : 12
x = 9,5
a) 54+(218-x)=735
218-x=681
x=-463
b) 96-3(x+1)=42
3(x+1)=54
x+1=18
x=17
c) 5(x+35)=515
x+35=103
x=68
d) 12x-33=3^2.2^2
12x-33=81
12x = 114
x=9,5
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Tìm số tự nhiên x,biết
a 12x - 33 = 3^2 . 3^3 .
b 96 - 3 (x + 1 0 = 42
a)12x-33=32.33
12x-33=243
12x=243+33
12x=276
x=276/12
x=23
a) 12x - 33 = \(3^2.3^3\)
\(\Rightarrow12x-33=3^5\)
\(\Rightarrow12x-33=243\)
\(\Rightarrow12x=243+33\)
\(\Rightarrow12x=276\)
\(\Rightarrow x=276:12\)
\(\Rightarrow x=23\)
b 96 - 3 (x + 10) = 42
\(\Rightarrow3\left(x+10\right)=96-42\)
\(\Rightarrow3\left(x+10\right)=54\)
\(\Rightarrow x+10=54:3\)
\(=>x+10=17\)
\(\Rightarrow x=17-10\)
\(\Rightarrow x=7\)
a) 12x - 33 = 3^2 . 3^3
12x - 33 = 243
12x = 243 + 33
12x = 276
x = 276 : 12
x = 23
b) 96 - 3( x + 10 ) = 42
3( x + 10 ) = 96 - 42
3( x + 10 ) = 54
x + 10 = 54 : 3
x + 10 = 18
x = 18 - 10
x = 8