=>|17x-5|=|17x+5|

=>17x-5=17x+5(vô lý) hoặc 17x-5=-17x-5

=>34x=0

hay x=0

\(\left|17x-5\right|=\left|17x+5\right|\)

\(\Leftrightarrow\left[{}\begin{matrix}17x-5=17x+5\\17x-5=-5-17x\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}-5=5\left(loai\right)\\34x=0\end{matrix}\right.\Leftrightarrow x=0\)

\(\Leftrightarrow\left|17x-5\right|=\left|17x+5\right|\)

Xét \(17x-5\ge0\)

\(\Rightarrow17x-5=17x+5\left(voli\right)\)

Xét \(17x-5< 0\)

\(\Rightarrow17x-5=-17x-5\)

\(\Leftrightarrow34x=0\Leftrightarrow x=0\)

Vậy \(S=\left\{0\right\}\)

x=0

x=0.

| 17x-5 | - | 17x+5| = 0

=> | 17x-5 | = 0 +  | 17x+5| 

=> | 17x-5 | = 17x+5

=> ...

Ta có : |17x - 5| - |17x + 5| = 0

=> |17x - 5| = |17x + 5|

Có 2 TH xảy ra :

TH1 : 17x - 5 = 17x + 5

=> 17x - 17x = 5 + 5

=> 0 = 10 (vô lý)

TH2 : 17x - 5 = - (17x + 5)

=> 17x - 5 = - 17x - 5

=> 17x + 17x = -5 + 5

=> 34x = 0

=> x = 0

Đề??.

lười vl , cần gấp k

<=> |17x - 5| = |17x + 5|

=> 17x - 5 = 17x + 5 hoặc 17x - 5 = -17x - 5

=> 0x = 10(loại) hoặc 34x = 0

<=> x = 0.

pt <=> | 17x - 5 | = | 17x + 5 |

\(\Leftrightarrow\orbr{\begin{cases}17x-5=17x+5\left(loai\right)\\17x-5=-17x-5\end{cases}}\)

\(\Leftrightarrow17x=-17x\)

\(\Leftrightarrow x=-x\)

\(\Leftrightarrow x=0\)