x +x x 3/4 = 1
chu y chu x thu 3 la dau nhan
bai 1:tim x(chu y dau * la dau nhan)
a)(x+1/4)+(3x-4)+2*(x-3)=1
b)2*(x-3)=3(x+2)-x+1
c)x*(x+3)+x(x-2)=2x*(x-1)
d)(x-1)*3x-2*(x+2)-2x=x(x-1)
a: \(\left(x+\dfrac{1}{4}\right)+\left(3x-4\right)+2\left(x-3\right)=1\)
=>\(x+\dfrac{1}{4}+3x-4+2x-6=1\)
=>\(6x-\dfrac{39}{4}=1\)
=>\(6x=1+\dfrac{39}{4}=\dfrac{43}{4}\)
=>\(x=\dfrac{43}{4}:6=\dfrac{43}{24}\)
b: \(2\left(x-3\right)=3\left(x+2\right)-x+1\)
=>\(2x-6=3x+6-x+1\)
=>2x-6=2x+7
=>-6=7(vô lý)
c: \(x\left(x+3\right)+x\left(x-2\right)=2x\left(x-1\right)\)
=>\(x^2+3x+x^2-2x=2x^2-2x\)
=>3x-2x=-2x
=>3x=0
=>x=0
d: \(\left(x-1\right)\cdot3x-2\left(x+2\right)-2x=x\left(x-1\right)\)
=>\(3x^2-3x-2x-4-2x=x^2-x\)
=>\(3x^2-7x-4-x^2+x=0\)
=>\(2x^2-6x-4=0\)
=>\(x^2-3x-2=0\)
=>\(x=\dfrac{3\pm\sqrt{17}}{2}\)
x + 2 . x +3. x + 4. x + ...+...+ 100.x = 5050
dau cha la dau nhan
x + 2.x + 3.x + 4.x + ... + 100.x = 5050
x.(1 + 2 + 3 + 4 + ... + 100) = 5050
x.(1 + 100).100:2 = 5050
x.101.50 = 5050
x.5050 = 5050
x = 5050 : 5050
x = 1
Vậy x = 1
1/2 * x + 3/5 *(x -2) bang 3/5
giup minh nhe ! thanks
chu thich : * la dau nhan
x x 8,6 = 387( x thu hai có nghia la dau nhan)
9,5 x x = 399 ( x thu hai nay ko phai la dau nhân)
giai hô minh nhe
x x 8,6=387
x= 387: 8,6
x= 45
9,5 x x= 399
x= 399: 9,5
x= 42
tk nhé
tim x , dau cham tuc la dau nhan
5 .x +2 . ( x-3 ) = 36
1. 1,2 : (0,4-x) = 2,5
2. x . 3,6 + x . 6,4 = 18,9
3. 9,4 : x + 5,3 : x = 14
Luu Y : dau "." la dau nhan nha.
1: =>0,5:(0,4-x)=2,5
=>0,4-x=0,5/2,5=0,5
=>x=0,4-0,5=-0,1
2: =>x*(3,6+6,4)=18,9
=>10x=18,9
=>x=1,89
3: =>(9,4+5,3):x=14
=>14,7:x=14
=>x=14,7/14=1,05
[3.x-x]:2=x
tim x [dau. hieu la dau nhan]
tìm x biet
a>0,762/x/0,7=1,2
b>0,24/x=0,34[du 0,002]
c>x/7,2*1,8=0,34
d>13,7/[x*12]=4,56[du 0,02]
chu y:/la dau chia
[..]la dong mo nguoc
* la dau nhan
giúp mình thật good nhe
1/7=8/-x
3x/9=2/6
4/2/5:(-33/10)+x=-1/5/6
(x-2/1/4):(-5/6)=3
-8:(4/1/5x+3/10)=4/4/9
(5,5x-44):(-3/2)=30
(13/10x-15).(-5/14)=3
1/3.(x+5/2)=-2
chu y dau( //)la so tap phan con dau( /) la phan so
\(\frac{4}{\frac{2}{5}}:\left(-\frac{33}{10}\right)+x=-\frac{1}{\frac{5}{6}}\)
\(10:\left(-\frac{33}{10}\right)+x=-\frac{6}{5}\)
\(-\frac{100}{33}+x=-\frac{6}{5}\)
\(x=\frac{302}{165}\)