Tính nhanh:
a. \(134^2-68.134+34^2\)
b. \(9^8.2^8-\left(18^4-1\right)\left(18^4+1\right)\)
c. \(100^2-99^2+98^2-97^2+...+2^2-1\)
Bài 1: Tính nhanh:
a) \(127^2+146.127+73^2\)
b) \(9^8.2^8-\left(18^4-1\right)\left(18^4+1\right)\)
c) \(100^2-99^2+98^2-97^2+...+2^2-1\)
d) \(\dfrac{780^2-220^2}{125^2+150.125+75^2}\)
Bài 2 : So sánh:
a) \(A=\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)và \(B=2^{32}\)
b) \(C=\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\)và \(D=3^{32}-1\)
Bài 1:
a,\(127^2+146.127+73^2=127^2+2.127.73+73^2\)\(=\left(127+73\right)^2=200^2=40000\)
b,\(9^8.2^8-\left(18^4-1\right)\left(18^4+1\right)\)
\(18^8-\left(18^8-1\right)=1\)
\(c,100^2-99^2+98^2-97^2+...+2^2-1\)
\(=\left(100-99\right)\left(100+99\right)+\left(98-97\right)\left(98+97\right)+...+\left(2-1\right)\left(2+1\right)\)\(=199+195+...+3\)
áp dụng công thức Gauss ta đc đáp án là:10100
d, mk khỏi ghi đề dài dòng:
\(\dfrac{\left(780-220\right)\left(780+220\right)}{\left(125+75\right)^2}=\dfrac{560000}{40000}=14\)Bài 2:
\(A=\left(2-1\right)\left(2+1\right)\)\(\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)
\(A=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\left(2^{16}+1\right)\)Cứ tiếp tục ta đc \(A=2^{32}-1< B=2^{32}\)
\(\left(3-1\right)C=\left(3-1\right)\left(3+1\right)\left(3^2+1\right)...\left(3^2+16\right)\)giải như câu a đc:\(\left(3-1\right)C=3^{32}-1\)
\(\Rightarrow C=\dfrac{3^{32}-1}{3-1}=\dfrac{3^{32}-1}{2}< D=3^{32}-1\)
1c,
\(=100^2-99^2+98^2-97^2+...+2^2-1^2\\ =\left(100+99\right)\left(100-99\right)+\left(98+97\right)\left(98-97\right)+...+\left(2+1\right)\left(2-1\right)\\ =\left(100+99\right)\cdot1+\left(98+97\right)\cdot1+...+\left(2+1\right)\cdot1\\ =100+99+98+97+...+2+1\\ =\dfrac{100\cdot101}{2}=5050\)
\(I\)Tính nhanh
\(a.127^2+146.127+73^2\)
\(b.9^8.2^8\left(18^4-1\right)\left(18^4+1\right)\)
\(c.100^2-99^2+98^2-97^2+...+2^2-1^2\)
\(d.\frac{780^2-220^2}{125^2+150.125+75^2}\)
\(II.\)Rút gọn các biểu thức
\(x^2\left(x+4\right)\left(x-4\right)-\left(x^2+1\right)\left(x^2-1\right)\)
\(\left(y-3\right)\left(y+3\right)\left(y^2+9\right)-\left(y^2+2\right)\left(y^2-2\right)\)
\(5\left(2x-1\right)^2+4\left(x-1\right)\left(x+3\right)-2\left(5-3x\right)^2\)
1272 + 146.127 + 732
= 1272 + 2 . 73 .127 + 732
= (127 + 73 ) 2
= 200 2
Tính nhanh giá trị các biểu thức sau
a. \(127^2+146\times127+73^2\)
b.\(9^8\times2^8-\left(18^4-1\right)\times\left(18^4+1\right)\)
c.\(100^2-99^2+98^2-97^2+...+2^2-1^2\)
d. \(\left(20^2+18^2+16^2+...+4^2+2^2\right)-\left(19^2+17^2+15^2+...+3^2+1^2\right)\)
e. \(\dfrac{780^2-220^2}{125^2+150\times125+75^2}\)
a) \(127^2+146.127+73^2=127^2+2.73.127+73^2=\left(127+73\right)^2=40000\)b) \(9^8.2^8-\left(18^4-1\right)\left(18^4+1\right)=18^8-\left(18^8-1\right)=1\)
c) \(100^2-99^2+98^2-97^2+...+2^2-1^2\)
\(=\left(100-99\right)\left(100+99\right)+\left(98-97\right)\left(98+97\right)+...+\left(2-1\right)\left(2+1\right)\)\(=100+99+98+97+...+2+1\)
\(=\dfrac{100\left(100+1\right)}{2}=5050\)
d) \(\left(20^2+18^2+16^2+...+4^2+2^2\right)-\left(19^2+17^2+15^2+...+3^2+1^2\right)\) \(=20^2-19^2+18^2-17^2+16^2-15^2+...+4^2-3^2+2^2-1^2\)
\(=\left(20-19\right)\left(20+19\right)+\left(18-17\right)\left(18+17\right)+...+\left(2-1\right)\left(2+1\right)\)\(=20+19+18+17+...+2+1\)
\(=\dfrac{20\left(20+1\right)}{2}=210\)
e) \(\dfrac{780^2-220^2}{125^2+150.125+75^2}\)
\(=\dfrac{\left(780-220\right)\left(780+220\right)}{\left(125+75\right)^2}=\dfrac{560.1000}{200}=2800\)
Thực hiện phép tính;
A=\(150-\left(100-99+98-97+...-3+2-1\right)\)
B=\(\frac{5\left(2.3\right)^9.\left(2^2\right)^6-2\left(2^2.3\right)^{14}.3^4}{5.2^{28}.3^{18}-7.2^{29}.3^{18}}\)
Mk lm đc câu a thôi nhé !
A= 150-(100-99+98-97+...-3+2-1)
từ 1-100 có 100 SH. Ta nhóm 4 số vs nhau như sau : (100-00+98-87)+(...)+(4-3+2-1)
Có tất cả số nhóm là : 100:4=25 nhóm. Mà mỗi nhóm ta tính có kết quả là 2, vậy tao có
A=150-(2.25)
A=150-50
A=100
Tính nhanh
a,\(A=100^2-99^2+98^2-97^2+...+2^2-1^2\)
b,\(B=\left(20^2+18^2+...+2^2\right)-\left(19^2+17^2+....+3^2+1^2\right)\)
c,\(C=\frac{780^2-220^2}{125^2+150.125+75^2}\)
d,\(D=2.\left(a+5\right).\left(a+4\right)-\left(a+5\right)^2-\left(a^2-9a-17\right)\)với a=99
a/ A = 1002 - 992 + 982 -...+22 - 12
= (1002 - 992) + (982 - 972) +...+ (22 - 12)
= 199 + 195 + 191 + ... + 1
= (\(\frac{199-1}{4}+1\))(\(\frac{199+1}{2}\)) = 5050
b/ Y chang câu a luôn nha
c/ \(C=\frac{780^2-220^2}{125^2+150.125+75^2}=\frac{\left(780-220\right)\left(780+220\right)}{\left(125+75\right)^2}\)
\(=\frac{560.1000}{200^2}=14\)
d/ 2(a + 4)(a + 5) - (a + 5)2 - (a2 - 9a - 17)
= 17a + 32 = 17(a + 1) + 15 = 1700 + 15 = 1715
Tính
a) \(100^2-99^2+98^2-97^2+...+2^2-1^2\)
b)\(\left(20^2+18^2+16^2+...+2^2\right)-\left(19^2+17^2+15^2+...+1^2\right)\)
c)\(\left(-1\right)^n.\left(-1\right)^{2n+1}\left(-1\right)^{n+1}\)
Tính giá trị của :
a) M = \(100^2-99^2+98^2-97^2+...+2^2-1^2\)
b) N = \(\left(20^2+18^2+16^2+...+4^2+2^2\right)-\left(19^2+17^2+15^2+...+3^2+1^2\right)\)
c) P = \(\left(-1\right)^n.\left(-1\right)^{2n+1}.\left(-1\right)^{n+1}\)
a)
Áp dụng công thức (a - b).(a+ b) = a.(a+ b) - b.(a+ b) = a2 + ab - ab - b2 = a2 - b2
Ta có
\(M=100^2-99^2+98^2-97^2+...+2^2-1^2\)
M = (100 - 99)(100 + 99) + (98 - 97).(98 + 97) + ...+ (2 - 1)(2+1)
= 100 + 99 + 98 + 97 + ...+ 2 + 1
= (1+100).100 : 2
= 5050
b)
N = (202 - 192 ) + (182 - 172 ) + ...+ (42 - 32 ) + (22 - 12 )
= (20 - 19).(20 + 19) + (18 - 17)(18 + 17) +...+ (4 -3)(4 +3) + (2-1)(2+1) = 39 + 35 + ...+ 7 + 3
N = (39 + 3).10 : 2 = 210
Tính nhanh:
a) \(100^2-99^2+98^2-97^2+...+2^2-1^2\)
b) \(\left(20^2+18^2+16^2+...+4^2+2^2\right)-\left(19^2+17^2+...+3^2+1^2\right)\)
a) Áp dụng hằng đẳng thức ta đc:
\(=\left(100^2-99^2\right)+\left(98^2-97^2\right)+...+\left(2^2-1^2\right)\)
\(=\left(100+99\right)\left(100-99\right)+\left(98-97\right)\left(98+87\right)+...+\left(2+1\right)\left(2-1\right)\)
\(=199+195+191+...+3\)
\(=\left[\left(199-3\right):4+1\right]\cdot\left(199+3\right):2=50\cdot101=5050\)
a) Áp dụng hằng đẳng thức ta đc:
\(=\left(100^2-99^2\right)+\left(98^2-97^2\right)+...+\left(2^2-1^2\right)\)
\(=\left(100+99\right)\left(100-99\right)+\left(98-97\right)\left(98+87\right)+...+\left(2+1\right)\left(2-1\right)\)
\(=199+195+191+...+3\)
\(=\left[\left(199-3\right):4+1\right]\cdot\left(199+3\right):2=50\cdot101=5050\)
b) mk nghĩ bước đầu tiên là phải bỏ ngoặc:
\(=20^2+18^2+16^2+...4^2+2^2-19^2-17^2-....-3^2-1^2\)
\(=\left(20^2-19^2\right)+\left(18^2-17^2\right)+...+\left(4^2-3^2\right)-1^2\)
\(=\left(20+19\right)\left(20-19\right)+\left(18+17\right)\left(18-17\right)+...+\left(4-3\right)\left(4+3\right)-1\)
\(=\left(39+35+31+...+7\right)-1\)
\(=\left(\left[\left(39-7\right):4+1\right]\cdot\left(39+7\right):2\right)-1=207-1=206\)
Tính nhanh:
a) \(100^2-99^2+98^2-97^2+...+2^2-1^2\)
b) \(\left(20^2+18^2+16^2+...+4^2+2^2\right)-\left(19^2+17^2+...+3^2+1^2\right)\)
a) 1002-992+....+22-12
=(100+99)(100-99)+(98+97)(98-97)+...+(2+1)(2-1)
=100+99+98+...+2+1
b) bieu thuc tren =
202-192+182-172+...+22-12
tinh tuong tu cau a
mình biết nội quy rồi nên đưng đăng nội quy
ai chơi bang bang 2 kết bạn với mình
mình có nick có 54k vàng đang góp mua pika
ai kết bạn mình cho