164-4x-5=5.4^2
tìm số tự nhiên x
9x+5.4=200 4x-20=25:22 2.(x-5)3=250 2.3x-5=157
9x+5.4 = 200 4x-20 = 2^5:2^2 2.3^x-5=157
9x+ 20 = 200 4x-20 = 2^3 2.3^x=157+5
9x = 200-20 4x-20 = 8 2.3^x=162
9x = 180 4x = 8+20 3^x=162:2
x= 180 : 9 4x = 28 3^x=81
x=2 x = 28:4 mà 3^4=81 => x=4
x = 7
5.4^3 + 2^4 .5
\(=5\cdot2^6+2^4\cdot5=5\cdot2^4\left(2^2+1\right)=80\cdot5=400\)
a, tính:\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
b, tìm x biết:\(1\frac{1}{30}:(24\frac{1}{6}-24\frac{1}{5})-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=(-1\frac{1}{5}):(8\frac{1}{5}-8\frac{1}{3})\)
Giải phương trình:
(4x+2x+18.5-10).3=66.5
15+5.4+3.10+5.3=4.5.x
a) (4x+2x+18.5-10).3=66.5
=>4x+2x+18.5-10=22.5
=>6x+90-10=110
=>6x+80=110
=>6x=110-80
=>6x=30
=>x=30:6
=>x=5
b) 15+5.4+3.10+5.3=4.5.x
=>5(3+4+3.2+3)=4.5.x
=>3+4+3.2+3=4x
=>3+4+6+3=4x
=>16=4x
=>x=16:4
=>x=4
My ơi! Công thức thì chịu khó dùng hàm đi. Làm thế nó chép bài đấy!
phân tích các đa thức sau thành nhân tử
1) x^2+5x+8
2) x^2+8x+7
3) x^2-6x-16
4) 4x^2-8x+3
5) 3x^2-11x+6
1: Đa thức này ko phân tích được nha bạn
2: \(x^2+8x+7\)
\(=x^2+x+7x+7\)
\(=x\left(x+1\right)+7\left(x+1\right)\)
\(=\left(x+1\right)\left(x+7\right)\)
3: \(x^2-6x-16\)
\(=x^2-8x+2x-16\)
\(=x\left(x-8\right)+2\left(x-8\right)\)
\(=\left(x-8\right)\left(x+2\right)\)
4: \(4x^2-8x+3\)
\(=4x^2-2x-6x+3\)
\(=2x\left(2x-1\right)-3\left(2x-1\right)\)
\(=\left(2x-1\right)\left(2x-3\right)\)
5: \(3x^2-11x+6\)
\(=3x^2-9x-2x+6\)
\(=3x\left(x-3\right)-2\left(x-3\right)\)
\(=\left(x-3\right)\left(3x-2\right)\)
\(\dfrac{25^5.4^2}{5^5.\left(-2\right)^5}\)
Có:\(\dfrac{25^5.4^2}{5^5.\left(-2\right)^5}=\dfrac{\left(5^2\right)^5.2^4}{5^5.\left(-2\right)^5}=\dfrac{5^{10}.2^4}{5^5.\left(-2\right)^5}=\dfrac{5^5}{-2}=\dfrac{3125}{2}\)
420 : [ 5. 22 - ( 20 : 5.4 -13 ) +4
420 : [ 5. 22 - (20 : 5.4 - 13) +4]
=420 : [5.4 -(4.4 -13)+4]
=420 : [20 -(16 -13) +4]
=420 : [20-3 +4]
=420: [17+4]
=420 : 21
= 20
420 : [ 5. 22 - ( 20 : 5.4 -13 ) + 4 ]
= 420 : [ 5 . 4 - ( 4 . 4 - 13 ) + 4 ]
= 420 : ( 20 - 3 + 4 )
= 420 : ( 17 + 4 )
= 420 : 21
= 20
(28\3\7-27\5\9).(2^26+5.4^12) =?
5⁶ : 5³ +2³ :2²
3333 : 3 + 225 :15
15.2³ + 4.3² - 5.7
5.4² - 18 :3²
6² : 4.3 +2.5²
80 - ( 4.5² -3.2³)
a: \(5^6:5^3+2^3:2^2\)
\(=5^3+2\)
=125+2
=127
b: \(3333:3+225:15\)
=1111+15
=1126
c: \(15\cdot2^3+4\cdot3^2-5\cdot7\)
\(=15\cdot8+4\cdot9-35\)
=120+36-35
=121
d: \(5\cdot4^2-18:3^2\)
\(=5\cdot16-18:9\)
=80-2=78
e: \(6^2:4\cdot3+2\cdot5^2\)
\(=36:4\cdot3+2\cdot25\)
=27+50
=77
f: \(80-\left(4\cdot5^2-3\cdot2^3\right)\)
=80-(100-24)
=80-76
=4