=2093

-4.3634111e+18

HT

@acquybemon

\(a,\dfrac{2}{7}+\dfrac{5}{7}.\dfrac{7}{10}-\dfrac{1}{14}\)

\(=\dfrac{1}{7}.2+\dfrac{1}{7}.5.\dfrac{7}{10}-\dfrac{1}{7}.\dfrac{1}{2}\)

\(=\dfrac{1}{7}.\left(2+\dfrac{35}{10}-\dfrac{1}{2}\right)\)

\(=\dfrac{1}{7}.\left(\dfrac{4}{2}+\dfrac{7}{2}-\dfrac{1}{2}\right)\)

\(=\dfrac{1}{7}.5=\dfrac{5}{7}\)

\(b,\left(3\dfrac{1}{2}-\dfrac{2}{3}\right).\dfrac{7}{34}-\dfrac{5}{34}\)

\(=\left(\dfrac{7}{2}-\dfrac{2}{3}\right).\dfrac{7}{34}-\dfrac{7}{34}.\dfrac{5}{7}\)

\(=\dfrac{7}{34}.\left(\dfrac{17}{6}-\dfrac{5}{7}\right)\)

\(=\dfrac{7}{34}.\dfrac{89}{42}=\dfrac{89}{204}\)

a: =2/7-1/14+5/10

=2/7-1/14+1/2

=4/14-1/14+7/14

=10/14=5/7

b: =(7/2-2/3)*7/34-5/34

\(=\dfrac{21-4}{6}\cdot\dfrac{7}{34}-\dfrac{5}{34}\)

\(=\dfrac{7}{6}\cdot\dfrac{1}{2}-\dfrac{5}{34}=\dfrac{7}{12}-\dfrac{5}{34}=\dfrac{89}{204}\)

Hôm qua lúc 14:50

ai chơi bang bang 2 kết bạn với mình

1+1+1+1+1+1+1+1+1+1+! =11 vì ! là giai thừa của 1

1+2+3+4+5 = 15

16+18 = 34

2+34 = 36

32+34-13 = 53

87+18-34-12-3 = 53

1111-1111 = 0

143-32 = 111 

1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 = 10

1 + 2 + 3 + 4 + 5 = 15

16 + 18 = 24

2 + 34 = 36

32 + 34 - 13 = 53

87 + 18 - 34 - 12 - 3 = 56

1111 - 1111 = 0

143 - 32 = 111

đề??

a) \(\dfrac{4}{5}-\left(\dfrac{1}{5}+\dfrac{1}{3}\right)=\dfrac{4}{5}-\left(\dfrac{3}{15}+\dfrac{5}{15}\right)=\dfrac{4}{5}-\dfrac{8}{15}=\dfrac{12}{15}-\dfrac{8}{15}=\dfrac{4}{15}\)

b) \(\dfrac{12}{7}-\left(\dfrac{3}{14}-1\right)=\dfrac{12}{7}-\left(-\dfrac{11}{14}\right)=\dfrac{12}{7}+\dfrac{11}{14}=\dfrac{5}{2}\)

c) \(\dfrac{11}{2}-9\cdot\left(\dfrac{7}{5}-\dfrac{1}{2}\right)=\dfrac{11}{2}-9\cdot\dfrac{9}{10}=\dfrac{11}{2}-\dfrac{81}{10}=\dfrac{55}{10}-\dfrac{81}{10}=-\dfrac{13}{5}\)

d) \(3\times9\left(\dfrac{4}{7}+\dfrac{3}{5}\right)=27\times\dfrac{41}{35}=\dfrac{1107}{35}\)

e) \(\left(\dfrac{1}{3}-\dfrac{1}{5}\right):2=\left(\dfrac{5}{15}-\dfrac{3}{15}\right):2=\dfrac{2}{15}:2=\dfrac{2}{15}\times\dfrac{1}{2}=\dfrac{1}{15}\)

f) \(\dfrac{123}{34}:\dfrac{1}{17}-\dfrac{21}{34}:\dfrac{1}{17}=\left(\dfrac{123}{34}-\dfrac{21}{34}\right):\dfrac{1}{17}=3:\dfrac{1}{17}=3\times17=51\)

`15/34+7/21+9/34-1 15/17+2/3`

`=(15/34+9/34)+(7/21+2/3)-32/17`

`=12/17+1-32/17`

`=(12/17-32/17)+1`

`=-20/17+1`

`=-3/17`

\(\dfrac{15}{34}+\dfrac{7}{21}+\dfrac{9}{34}-1\dfrac{15}{17}+\dfrac{2}{3}\)
\(=\left(\dfrac{15}{34}+\dfrac{9}{34}-\dfrac{32}{17}\right)+\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=-\dfrac{25}{17}+1=-\dfrac{8}{17}\)

\(3-\left(x-1\right)=2-2\left(x-3\right)\)

\(3-x+1=2-2x+6\)

\(4-x=8-2x\)

\(4-x-8+2x=0\)

\(x-4=0\)

\(x=4\)

3-(x-1)=2-2(x-3)=>3-2=x-1-2(x-3)=>1=x-1-2x+6

=>1=-x+5=>-x=1-5=-4=>x=4

Chúc bạn học tốt nhớ k cho mik nha.

\(3-\left(x-1\right)=2-2\left(x-3\right)\)

\(3-x+1=2-2x+6\)

\(4-x=8-2x\)

\(4-x-8+2x=0\)

\(x-4=0\)

\(x=4\)

1.\(=56+47-56+53-40\)
\(=\left(56-56\right)+\left(47+53\right)-40\)
\(=0+100-40=60\)
2.\(34+59-34+41+100\)
\(=\left(34-34\right)+\left(59+41\right)+100\)
\(=0+100+100=200\)
3.\(=109+34-109+66-10\)
\(=\left(109-109\right)+\left(34+66\right)-10\)
\(=0+100-10=90\)

3^x+1-3^x-2=702

3^x.3¹-3^x:3²=702

3^x.3^1-3^x.1/9=702

3^x(3-1/9)=702

3^x.26/9=702

3^x=702:26/9

3^x=243

3^x=3^5

suy ra  x=5

Dễ thấy 1 + 1 = 2

1 + 2 = 3 

3 + 5 = 8

8 + 13 = 21

13 + 21  =34

21 + 34 = 55

Theo dãy Fibonacci gì đó 

Vậy tử số của phân số tiếp theo là 34  + 55 = 89

Mẫu số là 55 + 89 = 144

Phân số cần tìm là 89/144 

Thấy: 1 + 1 = 2

1 + 2 = 3

2 + 3 = 5

3 + 8 = 8

8 + 13 = 21

13 + 21 = 34

21 + 34 = 55

Tử số của phân số tiếp theo là: 34 + 55 = 89

Mẫu số là: 55 + 89 = 144

Phân số cần tìm là 89/144

\(\frac{89}{144}\) nhớ tick nhé bạn