\(\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19}+\frac{2}{19.21}\right)\) ) . 462 - x = 19

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\) . 462 - x  = 19

\(\left(\frac{1}{11}-\frac{1}{21}\right)\) . 462 - x = 19 

... Chúc bạn học tốt !

\(\left(\frac{2}{11\cdot13}+\frac{2}{13\cdot15}+\frac{2}{15\cdot17}+\frac{2}{17\cdot19}+\frac{2}{19\cdot21}\right)\)\(\cdot462-x=19\)

\(\left(\frac{1}{11\cdot13}+\frac{1}{13\cdot15}+\frac{1}{15\cdot17}+\frac{1}{17\cdot19}+\frac{1}{19\cdot21}\right)\)\(\cdot462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\)\(\cdot462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\cdot462-x=19\)

\(\frac{10}{231}\cdot462-x=19\)

\(20-x=19\)

\(x=20-19\)

\(x=1\)

cảm ơn mọi người

a, (x+1)+(x+4)+(x+7)+...+(x+28)=155

=>x.10+(1+4+7+...+28)              =155

=>    x.10+145                            =155

=>           x.10                              = 155-145

=>           x.10                              = 10

=>            x                                  =10:10

=>           x                                    =1

Vậy x= 1

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right).462-\frac{17}{x+1,05}=19.\)

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{21}\right)462-\frac{17}{x+1,05}=19\)

\(\Leftrightarrow20-\frac{17}{x+1,05}=19\)

\(\Leftrightarrow1-\frac{17}{x+1,05}=0\)

\(\Leftrightarrow x+1,05=17\)

\(\Leftrightarrow x=15,95\)

\(19,96+4,19-24,15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=23,15\)

\(24,15-24,15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=23,15\)

\(24,15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=1\)

\(x:\frac{1}{4}-\frac{1}{4}=24,15\)

\(4x=24,4\)

\(x=6,1\)

\(\text{Bài này cx đơn giản thôi!}\)

\(4.19-24.15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=23.15-19.96\)

\(4.19-24.15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=3.19\)

\(24.15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=4.19-3.19\)

\(24.15:\left(x:\frac{1}{4}-\frac{1}{4}\right)=1\)

\(x:\frac{1}{4}-\frac{1}{4}=24.15:1\)

\(x:\frac{1}{4}-\frac{1}{4}=24.15\)

\(x:\frac{1}{4}=24.15+\frac{1}{4}\)

\(x:\frac{1}{4}=24.4\)

\(x=24.4.\frac{1}{4}\)

\(x=6.1\)

24,15:(x:1/4 -1/4) =23.15-19.96-4.19

24,15:(x:1/4 -1/4) = -1

x:1/4 -1/4 =-24,15

x:1/4=-24,15+1/4=24,15+0.25

x:1/4=24,4

x=24,4 *1/4

x=122/5 *1/4

x=61/10=6.1

1. \(\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19}+\frac{2}{19.21}\right)\times462-x=19\)

\(\left(\frac{13-11}{11.13}+\frac{15-13}{13.15}+\frac{17-15}{15.17}+\frac{19-17}{17.19}+\frac{21-19}{19.21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)

\(\frac{10}{231}\times462-x=19\)

\(20-x=19\)

\(x=20-19\)

\(x=1\)

2.b \(187-[[497-(8\times x+11)\div x]\div3-78]=150\)

​​\(187-[[497-(\frac{8\times x}{x}+\frac{11}{x})]:3-78]=150\)

\(187-[(497-8-\frac{11}{x}):3-78]=150\)

\(187-[(489-\frac{11}{x}):3-78]=150\)

\(187-[\frac{489}{3}-\frac{33}{x}-78]=150\)

\(187-[163-\frac{33}{x}-78]=150\)

\(187-85+\frac{33}{x}=150\)

\(102+\frac{33}{x}=150\)

\(\frac{33}{x}=150-102\)

\(\frac{33}{x}=48\)

\(x=\frac{48}{33}=\frac{16}{11}\)