\(\dfrac{22}{5}\times\dfrac{6}{121}\times\dfrac{11}{4}\times\dfrac{3}{5}\times\dfrac{1}{3}\times\dfrac{5}{4}\)

\(=\left(\dfrac{22}{5}\times\dfrac{5}{4}\right)\times\left(\dfrac{6}{121}\times\dfrac{11}{4}\right)\times\left(\dfrac{3}{5}\times\dfrac{1}{3}\right)\)

\(=\dfrac{11}{2}\times\dfrac{3}{22}\times\dfrac{1}{5}\)

\(=\dfrac{3}{20}\)

\(=\dfrac{22\times6\times11\times3\times1\times5}{5\times121\times4\times5\times3\times4}=\dfrac{11\times2\times6\times11\times1}{11\times11\times4\times5\times4}=\dfrac{2\times6\times1}{4\times5\times4}=\dfrac{18}{100}=\dfrac{9}{50}\)

\(318-5\left(x-64\right)=103\)

\(\Rightarrow5\left(x-64\right)=318-103\)

\(\Rightarrow5\left(x-64\right)=215\)

\(\Rightarrow x-64=43\)

\(\Rightarrow x=43+64\)

\(\Rightarrow x=107\)

_____________

\(4^x\cdot5+216=296\)

\(\Rightarrow4^x\cdot5=296-216\)

\(\Rightarrow4^x\cdot5-80\)

\(\Rightarrow4^x=16\)

\(\Rightarrow4^x=4^2\)

\(\Rightarrow x=2\)

___________

\(376-6^x:3=364\)

\(\Rightarrow6^x:3=376-364\)

\(\Rightarrow6^x:3=12\)

\(\Rightarrow6^x=36\)

\(\Rightarrow6^x=6^2\)

\(\Rightarrow x=2\)

___________

\(\left(4x-1\right)^2=121\)

\(\Rightarrow\left(4x-1\right)^2=11^2\)

\(\Rightarrow\left[{}\begin{matrix}4x-1=11\\4x-1=-11\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}4x=12\\4x=-10\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-\dfrac{5}{2}\end{matrix}\right.\)

107

2

2

TH1: 3; TH2: -5/2

`#3107.101107`

a)

\(x+x+\dfrac{1}{2}\times\dfrac{2}{5}+x+\dfrac{8}{10}=121\\3x+\dfrac{1}{5}+\dfrac{4}{5}=121\\ 3x+1=121\\ 3x=121-1\\ 3x=120\\ x=40 \)

Vậy, `x = 40`

b)

\(\dfrac{12+x}{42}=\dfrac{5}{6}\\ \dfrac{12+x}{42}=\dfrac{35}{42}\\ \dfrac{12+x}{42}-\dfrac{35}{42}=0\\ \dfrac{12+x-35}{42}=0\\ \dfrac{x-\left(35-12\right)}{42}=0\\ \dfrac{x-23}{42}=0\\ x-23=0\\ x=23\)

Vậy,` x = 23.`

a: \(x+x+\dfrac{1}{2}\cdot\dfrac{2}{5}+x+\dfrac{8}{10}=121\)

=>\(3x+\dfrac{1}{5}+\dfrac{4}{5}=121\)

=>3x+1=121

=>3x=120

=>x=40

b: \(\dfrac{x+12}{42}=\dfrac{5}{6}\)

=>\(x+12=42\cdot\dfrac{5}{6}=35\)

=>x=35-12=23

\(x-\frac{10}{3}=\frac{7}{15}.\frac{3}{5}\)

\(x-\frac{10}{3}=\frac{7}{25}\)

\(x=\frac{7}{25}+\frac{10}{3}=\frac{271}{75}\)

Vậy x = 271/75

\(x-\frac{10}{3}\)\(=\)\(\frac{7}{15}\)\(.\)\(\frac{3}{5}\)

\(x-\frac{10}{3}\)\(=\)  \(\frac{7}{25}\)

\(x\)             \(=\)\(\frac{7}{25}\)\(+\)\(\frac{10}{3}\)

\(x\)                 \(=\)    \(\frac{271}{75}\)

Trả lời:

x-10/3=7/15.3/5

x-10/3=7/25

x=10/3+7/25

x=271/75

x+3/22=27/121.11/9

x+3/22=3/11

x=3/11-3/22

x=3/22

1/5:x=1/2

x=1/5:1/2

x=1/5.2

x=2/5

3/5+2/5.x=1

2/5.x=1-3/5

2/5.x=2/5

x=2/5:2/5

x=1

0,0140...

\(B=\left(11^2-1^2\right)×...×\left(11^2-11^2\right)×...×\left(11^2-29^2\right)\)

\(B=0\)

a)1+3+5+...+X=121

(X-1):2+1=121

(X-1):2    =121-1(TÌM SỐ HẠNG) 

(X-1 ):2   =120

X-1          =120x2( TÌM SỐ BỊ CHIA )

X-1          =240

X              =240+1(TÌM SỐ BỊ TRỪ)

X               =241        

a) Số số hạng là: ( x - 1) : 2 + 1= x+1:2

( x +1) . ( x +1)    = 121 . 4

( x + 1 ) . ( x + 1) = 22.22

( x+ 1)                 = 22

Suy ra x = 21

mình chỉ biết làm câu a thôi còn câu b mình ko biết làm

b)1+5+10+....+ X=141

1+(5+10+.......+ X)=141

5+10+.....+ X=141-1(TÌM SỐ HẠNG)

5+10+.....+X=140

(X-5):5+1=140

(X-5):5    =140-1(TÌM SỐ HẠNG)

(X-5):5    =139

X-5          =139x5( TÌM SỐ BỊ CHIA )

X-5          =695

X             =695 +5(TÌM SỐ BỊ TRỪ )

X             =700  

= ( x + x + .... + x ) + ( 1 + 5 + 9 + 121 ) = 2015

= 31. x + 1891 = 2015

= 31.x =2015 - 1891

= 31.x = 124

x = 124 : 31

x = 4