a: =>2x^3=58-4=54

=>x^3=27

=>x=3

b; =>(5-x)^5=2^5

=>5-x=2

=>x=3

c: =>(5x-6)^3=4^3

=>5x-6=4

=>5x=10

=>x=2

d: (3x)^3=(2x+1)^3

=>3x=2x+1

=>x=1

1=>2x³=54
=>x³=27  =>x=3
2=>(5-x)⁵=2⁵
=>5-x=2
=>x=3
3=>(5x-6)³=4³
=>5x-6=4
=>5x=10=>x=2
4=>3x=2x+1
=>x=1

\(2x-10,01=19,01-3\\ \Rightarrow2x-10,01=16,01\\ \Rightarrow2x=16,01+10,01\\ \Leftrightarrow2x=26,02\\ \Leftrightarrow x=26,02:2=13,01\)

2x-10,01=19,01-3

=> 2x-10,01= 16,01

=> 2x= 16,01+10,01

=>2x= 26,02

=> x= 26,02: 2= 13,01

\(2x-10,01=19,01-3\\ 2x-10,01=16,01\\ 2x=16,01+10,01\\ 2x=26,02\\ x=26,02:2\\ x=13,01\)

Ta có: 2x + 2x + 3 = 144

=> 2x + 2x.23 = 144

=> 2x.(1 + 8) = 144

=> 2x.9 = 144

=> 2x = 144 : 9 = 16 = 24

=> x = 4.

Vậy x= 4

x= 4

2^x + 2^x+3 = 144

\(\Leftrightarrow\)2^x. (1 + 2³) = 144

\(\Leftrightarrow\)2^x. 9 =144

\(\Leftrightarrow\)2^x=16

\(\Leftrightarrow\)2^x = 2⁴

\(\Leftrightarrow\)x = 4

vậy x = 4

ủng hộ nha!

Ta có: 2^x + 2^{x + 3} = 144

=> 2^x + 2^x . 2³ = 144

=> 2^x .(1 + 2³) = 144

=> 2^x = 16

=> 2^x = 2⁴

=> x = 4 

   Vậy x = 4

\(2^x+2^{x+3}=144\)

\(2^x+2^x.2^3=144\)

\(2^x\left(1+8\right)=144\)

\(2^x.9=144\)

\(2^x=16\)

\(\Rightarrow x=4\)

\(a,2^x+2^{x+3}=144\\ 2^x.\left(1+2^3\right)=144\\ 2^x.9=144\\ 2^x=144:9\\ 2^x=16=2^4\\ vậy:x=4\)

\(b,\left(x-5\right)^{2022}=\left(x-5\right)^{2021}\\ Vì:\left[{}\begin{matrix}0^{2022}=0^{2021}\\1^{2022}=1^{2021}\end{matrix}\right.\\ Vậy:\left[{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)

\(c,\\ \left(2x+1\right)^3=9.81\\ \left(2x+1\right)^3=3^2.3^4\\ \left(2x+1\right)^3=3^6\\ \left(2x+1\right)^3=\left(3^2\right)^3=9^3\\ Vậy:2x+1=9\\ 2x=9-1\\ 2x=8\\ x=\dfrac{8}{2}\\ x=4\)

Tham khảo:Tìm x thuộc N , biết:a)  2x + 2x+3  =144b) (4x -1)2 =25 x 9  - Hoc24

a/ 2^x+2 + 2^x = 144

=> 2^x (2² + 1) = 144

=> 2^x = 144/5

=> k có giá trị nào của x thỏa biểu thức trên

b/ (2x + 1)³ = 243

=> đề sai