\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\dfrac{3^2.\left(2^2\right)^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\) 

\(=\dfrac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\) 

\(=\dfrac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\) 

\(=\dfrac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\) 

\(=\dfrac{3^2.2^{36}}{2^{35}.9}\) 

\(=\dfrac{3^2.2^{36}}{2^{35}.3^2}\) 

\(=2\)

(3.4.2^16)^2/11.2^13.4^11-16^9

=3^2.4^2.(2^16)^2/11.2^13.(2^2)^11-(2^4)^9

=3^2.(2^2)^2.2^32/11.2^13.2^12-2^36

=3^2.2^4.2^32/11.2^13.2^12-2^36

=3^2.2^32+4/11.2^13+12-2^36

=3^2.2^36/11.2^35-2^36

=3^2.2^35.2/11.2^35-2^35.2

=3^2.2^35.2/2^35.(11-2)

=3^2.2^35.2/2^35.9

=3^2.2/9

=9.2/9

=2

goi y nhe ket qua bang 2

mau mau lay k nao

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)\(=\frac{3^2.4^2.2^{32}}{11.2^{12}.2^{22}-2^{36}}\)\(=\frac{3^2.2^4.2^{32}}{11.2^{34}-2^{34}.2^2}\)\(=\frac{3^2.2^{34}.2^2}{2^{34}.\left(11-2^2\right)}\)\(=\frac{2^{34}.36}{2^{34}.7}=\frac{36}{7}\)

\(\frac{1}{2}\)

tích nha nha nha nha

Làm ơn đi

bạn sai rồi

Oh

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)

\(=\frac{3^2.3^{36}}{2^{35}.\left(11-2\right)}\)

\(=\frac{9.2}{9}=2\)

\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(A=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)

\(A=\frac{3^2.2^4.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(A=\frac{3^2.2^{36}}{11.2^{13}.2^{22}-2^{36}}\)

\(A=\frac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)

\(A=\frac{3^2.2^{36}}{\left(11-2\right).2^{35}}\)

\(A=\frac{3^2.2}{9}=\frac{18}{9}=2\)

\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)

\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)

\(=\frac{9.2}{2}=2\)