Tìm x
(x+2)4+(x+8)4 =272
Tìm x:2+4+6+8+10+...+x=272
\((x+2)^{4}+(x+8)^{4}=272\)
l8 học đặt r đk
đặt t=x+5
=>pt:
\(\left(t-3\right)^4+\left(t+3\right)^4=272\\ \Leftrightarrow t^4-4t^3+54t^2-108t+81+t^4+4t^3+54t^2+108t+81=271\\ \Leftrightarrow2t^4+108t^2-110=0\\ \Leftrightarrow\left(t^2-1\right)\left(2t^2+110\right)=0\\ \Leftrightarrow t^2=1\)
( 2t^2 +110 > 0 mọi x)
\(\Leftrightarrow\left[{}\begin{matrix}t=1\Rightarrow x=-4\\t=-1\Rightarrow x=-6\end{matrix}\right.\)
Tìm x :
(12x-43).83=4.84
(3x-24).73=2.74
2x+2x+4=272
(12x-43).83=4.84
=> 12x-43=4.84:83
=> 12x-64=4.8
=> 12x-64=32
=> 12x=32+64
=> 12x=96
=> x=96:12
=> x=8
(3x-24).73=2.74
=> 3x-24=2.74:73
=> 3x-16=2.7
=> 3x-16=14
=> 3x=14+16
=> 3x=30
=> x=10
2x+2x+4=272
=> 2x.(1+24)=272
=> 2x.(1+16)=272
=> 2x.17=272
=> 2x=16
=> 2x=24
=> x=4
Tìm x:
4x + 4x + 2 = 272
4x + 4x + 2 = 272
\(\Rightarrow\)4x + 4x . 42 = 272
\(\Rightarrow\)4x . ( 16 + 1 ) = 272
\(\Rightarrow\)4x . 17 = 272
\(\Rightarrow\)4x = 272 : 17
\(\Rightarrow\)4x = 16
\(\Rightarrow\)4x = 42
\(\Rightarrow\)x = 2
tìm x
a, ( x + 1 ) * ( x + 2 ) = 272
b, ( x + 2 ) * ( x + 3 ) = 462
c, ( x + 3 ) * ( x + 4 ) = 182
d, ( x + 4 ) * ( x + 5 ) = 552
giúp mình nha !!!
a) \(\left(x+1\right)\left(x+2\right)=272\)
\(\Rightarrow x^2+3x+2=272\)
\(\Rightarrow x^2+3x-270=0\)
\(\Rightarrow x^2+18x-15x-270=0\)
\(\Rightarrow x\left(x+18\right)-15\left(x+18\right)=0\)
\(\Rightarrow\left(x+18\right)\left(x-15\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+18=0\\x-15=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-18\\x=15\end{matrix}\right.\)
d) \(\left(x+4\right)\left(x+5\right)=552\)
\(\Rightarrow x^2+9x+20=552\)
\(\Rightarrow x^2+9x-532=0\)
\(\Rightarrow x^2+28x-19x-532=0\)
\(\Rightarrow x\left(x+28\right)-19\left(x+28\right)=0\)
\(\Rightarrow\left(x+28\right)\left(x-19\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+28=0\\x-19=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-28\\x=19\end{matrix}\right.\)
tìm x biết:
2^x + 2^x + 4= 272
2x + 2x + 4= 272
2x + 2x= 272-4
2x + 2x =268
2.( 2x )=268
2x=268:2
2x=134
2x=đề saI
Tìm x
2x+2x+4=272
2x+2x+4=272
=> 2x.(1+24)=272
=> 2x.(1+16)=272
=> 2x.17=272
=> 2x=272:17
=> 2x=16
=> 2x=24
=> x=4
Tìm x biết :2x+2x+4=272
2x + 2x +4 = 272
(2 + 2)x + 4 = 272
4x + 4 = 272
4x = 272 - 4
4x = 268
24+2x+4=272
Tìm số tự nhiên x
24+2x+4=272
=>16+2x.24=272
=>2x.16=272-16
=>2x.16=256
=>2x=256:16
=>2x=16
=>2x=24
=>x=4