3x^2-3x-6

=3(x^2-x-2)

=3(x-2)(x+1)

???giải ròi mà:

x²+5x-6

= x²-x+6x-6

= x(x-1)+6(x-1)

= (x-1).(x+6)

1: Đa thức này ko phân tích được nha bạn

2: \(x^2+8x+7\)

\(=x^2+x+7x+7\)

\(=x\left(x+1\right)+7\left(x+1\right)\)

\(=\left(x+1\right)\left(x+7\right)\)

3: \(x^2-6x-16\)

\(=x^2-8x+2x-16\)

\(=x\left(x-8\right)+2\left(x-8\right)\)

\(=\left(x-8\right)\left(x+2\right)\)

4: \(4x^2-8x+3\)

\(=4x^2-2x-6x+3\)

\(=2x\left(2x-1\right)-3\left(2x-1\right)\)

\(=\left(2x-1\right)\left(2x-3\right)\)

5: \(3x^2-11x+6\)

\(=3x^2-9x-2x+6\)

\(=3x\left(x-3\right)-2\left(x-3\right)\)

\(=\left(x-3\right)\left(3x-2\right)\)

Ta có:\(x^3+9x^2+11x-21\)

\(=x^3-x^2+10x^2-10x+21x-21=x^2\left(x-1\right)+10x\left(x-1\right)+21\left(x-1\right)\)

\(=\left(x^2+10x+21\right)\left(x-1\right)=\left(x^2+3x+7x+21\right)\left(x-1\right)\)

\(=\left[x\left(x+3\right)+7\left(x+3\right)\right]\left(x-1\right)\)

\(=\left(x+3\right)\left(x+7\right)\left(x-1\right)\)

x^3+9x^2+11x-21=x^3-x^2+10x^2-10x+21x-21=(x^3-x^2)+(10x^2-10x)+(21x-21)

=x^2(x-1)+10x(x-1)+21(x-1)=(x-1)(x^2+10x+21)=(x-1)(x^2+3x+7x+21)=(x-1)[(x^2+3x)+(7x+21)]

=(x-1)(x+7)(x+3)

\(x^3+9x^2+11x-21\)

\(=x^3-x^2+10x^2-10x+21x-21\)

\(=\left(x^3-x^2\right)+\left(10x^2-10x\right)+\left(21x-21\right)\)

\(=x^2\left(x-1\right)+10x\left(x-1\right)+21\left(x-1\right)\)

\(=\left(x^2+10x+21\right)\left(x-1\right)\)

\(=\left(x^2+10x+25-4\right)\left(x-1\right)\)

\(=\left[\left(x-5\right)^2-4\right]\left(x-1\right)\)

\(=\left(x-7\right)\left(x-3\right)\left(x-1\right)\)

ko chắc phần sau lắm nhé

\(x^3+6x^2+11x+6=\left(x+1\right)\left(x+2\right)\left(x+3\right)\)

x³+6x²-11x+6=(x+1)(x+2)(x+3)

\(=\left(3x+y+5\right)\left(x+7y+2\right)\)

ai giải thích chi tiết hơn con này hộ mình được k ạ :))

\(=3x^2+21xy+xy+6x+5x+2y+35y+7y^2+10\)

\(=\left(3x^2+21xy+6x\right)+\left(xy+7y^2+2y\right)+\left(5x+35y+10\right)\)

\(=3x\left(x+7y+2\right)+y\left(x+7y+2\right)+5\left(x+7y+2\right)=\left(3x+y+5\right)\left(x+7y+2\right)\)

5 x² - 5xy+2x−2y = 2x ( x - y) + 2( x - y) = 2( x + 1)( x - y)

= \(x^4-2x^3-6x^3+12x^2-x^2+2x+6x-12\)

= \(x^3\left(x-2\right)-6x^2\left(x-2\right)-x\left(x-2\right)+6\left(x-2\right)\)

= \(\left(x-2\right)\left(x^3-6x^2-x+6\right)\)

= \(\left(x-2\right)\left(x^2\left(x-6\right)-\left(x-6\right)\right)\)

= \(\left(x-2\right)\left(x-6\right)\left(x-1\right)\left(x+1\right)\)

x⁴ - 8x³ + 11x² + 8x - 12

= (x³ - 7x² + 4x + 12)(x - 1)

= (x³ - 8x + 12)(x + 1)(x - 1)

= (x - 6)(x - 2)(x + 1)(x - 1)