a. -20+5=-15 

b. 7

c. 35 + (-4)= 31 

d. -129-37+29-63= -100-100 = -200 

e. 217 -315-117+215 =100-100=0 

f. 15:(-3)+24:2 = -5 + 12 = 7 

g. (-5).(-7)-3.(14)= 35 - 42 = -7 

H. (-15)x(-129+29) = -15 x -100 =1500 

i. 13 x (-125+25) =13 x -100 = -1300 

k. 37(-135+35) = 37 x -100 = -3700

3/25 x ( 15/7 - 2/7 ) + 3/7 x 1/25 

= 3/25 x 13/7 + 3/7 x 1/25 

= (3 x 13/7 + 3/7 ) x 1/25 

= 42/7 x 1/25 

= 6 x 1/25 

= 6/25

\(\dfrac{3}{25}\times\dfrac{15}{7}+\dfrac{3}{7}\times\dfrac{1}{25}-\dfrac{2}{7}\times\dfrac{3}{25}\)

\(=\dfrac{3}{25}\times\left(\dfrac{15}{7}-\dfrac{2}{7}\right)+\dfrac{3}{7}\times\dfrac{1}{25}\)

\(=\dfrac{3}{25}\times\dfrac{13}{7}+\dfrac{3}{7}\times\dfrac{1}{25}\)

\(=\dfrac{3\times13}{25\times7}+\dfrac{3\times1}{7\times25}\)

\(=\dfrac{39}{175}+\dfrac{3}{175}\)

\(=\dfrac{39+3}{175}\)

\(=\dfrac{42}{175}\)

\(=\dfrac{6}{25}\)

A = \(\dfrac{3}{25}\) \(\times\) \(\dfrac{15}{7}\) + \(\dfrac{3}{25}\) \(\times\) \(\dfrac{1}{7}\) - \(\dfrac{2}{7}\times\) \(\dfrac{3}{25}\)

A = \(\dfrac{3}{25}\) \(\times\)( \(\dfrac{15}{7}\) + \(\dfrac{1}{7}-\dfrac{2}{7}\))

A = \(\dfrac{3}{25}\) \(\times\) \(\dfrac{14}{7}\)

A = \(\dfrac{6}{25}\)

a,sửa đề : đk x khác -2;  2 

 \(x^2+x-2+5x-10=12+x^2-4\)

\(\Leftrightarrow6x-20=0\Leftrightarrow x=\dfrac{10}{3}\left(tm\right)\)

b, \(3x-12+5+5x=105\Leftrightarrow8x=112\Leftrightarrow x=14\)

c, \(3x^2+14x-49=-\left(x^2+2x-15\right)\)

\(\Leftrightarrow4x^2+16x-34=0\Leftrightarrow x=\dfrac{-4\pm5\sqrt{2}}{2}\)

a. ko hỉu đề lắm :v

b.\(\dfrac{x-4}{5}+\dfrac{1+x}{3}=7\)

\(\Leftrightarrow\dfrac{3\left(x-4\right)+5\left(1+x\right)}{15}=\dfrac{105}{15}\)

\(\Leftrightarrow3\left(x-4\right)+5\left(1+x\right)=105\)

\(\Leftrightarrow3x-12+5+5x-105=0\)

\(\Leftrightarrow8x-112=0\)

\(\Leftrightarrow8x=112\)

\(\Leftrightarrow x=14\)

c.\(\left(3x-7\right)\left(x+7\right)=\left(5+x\right)\left(3-x\right)\)

\(\Leftrightarrow3x^2+21x-7x-49=15-5x+3x-x^2\)

\(\Leftrightarrow4x^2+16x-64=0\)

Nghiệm xấu lắm bạn

=> 72 - 20x - 36x - 84 = 30x - 240 - 6x + 84

=> (72 - 84 )  - (20x + 36x ) = (30x - 6x ) - 240 + 84

=> -12 - 56x = 24x - 156

=> -12 + 156 = 24x + 56x 

=> 144 = 80x

=> x = 144  : 80

=> x = 9/5

=> 72 - 20x - 36x - 84 = 30x - 240 - 6x + 84

=> (72 - 84 )  - (20x + 36x ) = (30x - 6x ) - 240 + 84

=> -12 - 56x = 24x - 156

=> -12 + 156 = 24x + 56x 

=> 144 = 80x

=> x = 144  : 80

=> x = 9/5

de bai co noi tinh = cách nào ko .

a) 2 x 53 x 12 + 4 x 6 x 83 - 3 x 8 + 40

= (2 x 12) x 53 + ( 4 x 6 ) x 83 - ( 3 x 8 ) + 40

= 24 x 53 + 24 x 83 - 24 + 40

= 1272 + 1992 - 64

= 3264 - 64 = 3200

=

bài b = 420 và bài c = 38400 tớ đang vội hôm sau tớ sẽ trình bày lời giải

`@` `\text {Ans}`

`\downarrow`

`(8x-3)(3x+2)-(4x+7)(x+4)=(2x+1)(5x-1)-33`

`\Leftrightarrow 8x(3x+2) -3(3x+2) - 4x(x+4) + 7(x+4) = 2x(5x-1) + 5x-1 - 33`

`\Leftrightarrow 24x^2 + 16x - 9x - 6 - 4x^2 - 16x - 7x - 28 = 10x^2 - 2x + 5x - 1 - 33`

`\Leftrightarrow 20x^2 -16x - 34 = 10x^2 + 3x - 34`

`\Leftrightarrow 20x^2 - 16x - 34 - 10x^2 - 3x + 34 = 0`

`\Leftrightarrow 10x^2 - 19x = 0`

`\Leftrightarrow x(10x - 19)=0`

`\Leftrightarrow `\(\left[{}\begin{matrix}x=0\\10x-19=0\end{matrix}\right.\)

`\Leftrightarrow `\(\left[{}\begin{matrix}x=0\\10x=19\end{matrix}\right.\)

`\Leftrightarrow `\(\left[{}\begin{matrix}x=0\\x=\dfrac{19}{10}\end{matrix}\right.\)

Vậy, `x={0; 19/10}.`

Với bài này bn áp dụng bài phần tử của tập hợp nhé! 

(8-4):6=129

Gọi 129 là x

X-7=59

Gọi  59 làc

Vậy phần bài này là phần tử

Đs 78/9

\(\left(8x-3\right)\left(3x+2\right)-\left(4x+7\right)\left(x+4\right)=\left(2x+1\right)\left(5x-1\right)-33\)

\(\Leftrightarrow24x^2+16x-9x-6-4x^2-16x-7x-28=10x^2-2x+5x-1-33\)

\(\Leftrightarrow10x^2-19x=0\)

\(\Leftrightarrow x\left(10x-19\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\10x-19=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{19}{10}\end{matrix}\right.\)

1)` 2/9 + -3/4 + 5/30= (40+(-135) + 30 )/180 = -65/180 = -13/36`

2) `-7/12 - 11/18=(-21)/36 - 22/36 = -43/36 `

3) `7/8 - (-5)/16=14/16- (-5)/16 = 19/16 `

4) `3/8 - (-9)/10 - 5/16= (30- (-72) -25)/80=77/80`

1)\(\dfrac{2}{9}+\dfrac{-3}{4}+\dfrac{5}{30}\)

\(=\dfrac{2.20}{9.20}+\dfrac{-3.45}{4.45}+\dfrac{5.6}{30.6}\)

\(=\dfrac{40}{180}+\dfrac{-135}{180}+\dfrac{30}{180}\)

\(=\dfrac{40+\left(-135\right)+30}{180}\)

\(=\dfrac{-65}{180}\)

\(=\dfrac{-13}{36}\)

2)\(\dfrac{-7}{12}-\dfrac{11}{18}\)

\(=\dfrac{-7.3}{12.3}-\dfrac{11.2}{18.2}\)

\(=\dfrac{-21}{36}-\dfrac{22}{36}\)

\(=\dfrac{-21-22}{36}\)

\(=\dfrac{-43}{36}\)

3)\(\dfrac{7}{8}-\dfrac{-5}{16}\)

\(=\dfrac{7.2}{8.2}-\dfrac{-5}{16}\)

\(=\dfrac{14}{16}-\dfrac{-5}{16}\)

\(=\dfrac{14-\left(-5\right)}{16}\)

\(=\dfrac{19}{16}\)

4)\(\dfrac{3}{8}-\dfrac{-9}{10}-\dfrac{5}{16}\)

\(=\dfrac{3.10}{8.10}-\dfrac{-9.8}{10.8}-\dfrac{5.5}{16.5}\)

\(=\dfrac{30}{80}-\dfrac{-72}{80}-\dfrac{25}{80}\)

\(=\dfrac{30-\left(-72\right)-25}{80}\)

\(=\dfrac{77}{80}\)

2/3.x + 1/4 = 7/12

2/3.x           = 7/12 - 1/4

2/3.x           = 1/3

x                 = 1/3 : 2/3

x                 = 1/2

Bài làm

\(\frac{2}{3}x+\frac{1}{4}=\frac{7}{12}\)

\(\frac{2}{3}x=\frac{7}{12}-\frac{1}{4}\)

\(\frac{2}{3}x=\frac{7}{12}-\frac{3}{12}\)

\(\frac{2}{3}x=\frac{4}{12}\)

\(\frac{2}{3}x=\frac{1}{3}\)

\(x=\frac{1}{3}:\frac{2}{3}\)

\(x=\frac{1}{3}.\frac{3}{2}\)

\(x=\frac{1}{2}\)

Vậy \(x=\frac{1}{2}\)

2/3 .x + 1/4 = 7/12

2/3 .x         = 7/12 - 1/4

2/3.x          = 1/3

x                = 1/3 : 2/3

x                = 1/2

Câu 1:

a) 2(x-3)-3(x-5)=4(3-x)-18

<=> 3x-6-3x+15-12+4x+18=0

<=> 4x+15=0

<=> 4x=-15

<=> x=-15/4

b) -2(2x-8)+3(4-2x)=-57-5(3x-7)

<=> -4x+16+12-6x+57+15x-35=0

<=> -5x+50=0

<=> -5x=-50

<=> x=10

c) 3|2x²-7|=33

<=> |2x²-7|=11

<=> \(\orbr{\begin{cases}2x^2-7=11\\2x^2-7=-11\end{cases}\Leftrightarrow\orbr{\begin{cases}2x^2=18\\2x^2=-4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x^2=9\\x^2=-2\end{cases}\Leftrightarrow}x=\pm3}\)

d) có 9x+17=3(3x+2)+11

=> 11 chia hết cho 3x+2

=> 3x+2 thuộc Ư (11)={-11;-1;1;11}

ta có bảng

Câu 2:

xy-5x+y=17

<=> x(y-5)+(y-5)=12

<=> (y-5)(x+5)=12

=> y-5; x+5 \(\inƯ\left(12\right)=\left\{-12;-6;-4;-3;-2;-1;1;2;3;4;6;12\right\}\)

lập bảng tương tự câu 1

Câu 1

a,b,sorry bạn mk ko bít

c,3.|2x² - 7|=33

=>|2x² - 7|=11

=>2x² -7=11 hoặc 2x² - 7= -11

=>2x² =18 hoặc 2x²= -4

=>x²=9 hoặc x²= -2

=>x²=3² 

Vậy x=3

d,9x+17 chia hết cho 3x+2

=>3(3x+2)-6+17 chia hết cho 3x+2

=>3(3x+2)+11 chia hết cho 3x+2

=>11 chia hết cho 3x+2

=>3x+2 thuộc Ư(11)={11;1;-1;-11}

=>3x thuộc {9;-1;-3;-13}

=.x = {3; -0,33333 ;-1; -4,3333}   (nếu đề bài cho x thuộc Z thì x = {3;-1} )

Câu 2

       xy-5x+y=17

<=> x(y-5) +y=17

<=> x(y-5)+1(y-5)=17-5

<=>(y-5).(x+1)=12

 Vì 12=1.12= -1.(-12)=2.6= -2.(-6)=3.4= -3.(-4) nên 

Ta có bảng sau

Còn lại chắc bạn tự làm đc

Nếu ko thì mk sẽ làm tiếp cho