0,5x-2/3x=7/12

=>(1/2-2/3).x=7/12

=>-1/6x=7/12

=>x=7/12:1/6

=>x=7/2

b, x:4 1/3=-2,5

=>x:13/3=-2,5

=>x=-5/2x13/3

=>x=-13

c,5,5x=13/15

=>11/2x=13/15

=>x=13/15:11/2

=>x=26/165

d,(3x/7+1):-4=-1/28

=>3x/7+1=-1/28x(-4)

=>3x/7+1=-1/7

=>3x/7=-1/7-1

=>3x/7=-8/7

=>3x=-8/7x7

=>3x=8

=>x=8:3

=>x=8/3

\(0,5x-\frac{2}{3}x=\frac{7}{12}\)

\(\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)

\(\left(\frac{1}{2}-\frac{2}{3}\right)x=\frac{7}{12}\)

\(\frac{-1}{6}x=\frac{7}{12}\)

\(x=-21\)

b,c,d tương tự

câu trả lời b kết qua bằng -65/6

a) \(\left(0,5-\frac{2}{3}\right)\cdot x=\frac{7}{12}\)

\(\left(\frac{1}{2}-\frac{2}{3}\right)\cdot x=\frac{7}{12}\)

\(\frac{-1}{6}\cdot x=\frac{7}{12}\)

\(x=\frac{7}{12}:\frac{-1}{6}\)

\(x=\frac{7}{12}\cdot\frac{-6}{1}\)

\(x=\frac{-7}{2}\)

a)x(1/2-2/3)=7/12

 x.(-1/6)=7/12

 x=7/12 / (-1/6)

x=-7/2

b)x=13/15 / 5,5

x=26/165

c)3x/7 + 1=-1/28.(-4)

3x/7 + 1=1/7

3x/7=1/7-1=-6/7

3x=-6/7.7=-6

x=-6:3=-2

a. \(0,5x-\frac{2}{3}x=\frac{7}{12}\)

=>\(\left(0,5-\frac{2}{3}\right).x=\frac{7}{12}\)

=>\(-\frac{1}{6}.x=\frac{7}{12}\)

=>\(x=\frac{7}{12}:-\frac{1}{6}=-\frac{7}{2}\)

_Hok tốt_

b.\(x:4\frac{1}{3}=-2,5\)

=>\(x:\frac{13}{3}=-2,5\)

=>\(x=-2,5.\frac{13}{3}=-\frac{65}{6}\)

_Hok tốt_

c.\(5,5x=\frac{13}{15}\)

=>\(x=\frac{13}{15}:5,5=\frac{26}{165}\)

_Hok tốt_

b) \(\left(5x-1\right)\left(2x-\frac{1}{3}\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}5x-1=0\\2x-\frac{1}{3}=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}5x=1\\2x=\frac{1}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{1}{5}\\x=\frac{1}{6}\end{matrix}\right.\)

e, \(-\frac{3}{4}-\left|\frac{4}{5}-x\right|=-1\)

\(\Leftrightarrow\left|\frac{4}{5}-x\right|=-\frac{3}{4}-\left(-1\right)\)

\(\Leftrightarrow\left|\frac{4}{5}-x\right|=\frac{1}{4}\)

\(\Leftrightarrow\left[{}\begin{matrix}\frac{4}{5}-x=\frac{1}{4}\\\frac{4}{5}-x=-\frac{1}{4}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{7}{15}\\x=1,05\end{matrix}\right.\)

Vậy ....

a) Ta có: \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)

\(\Leftrightarrow\left(3x+2\right)\left(5x+1\right)=\left(5x+7\right)\left(3x-1\right)\)

\(\Leftrightarrow3x\left(5x+1\right)+2\left(5x+1\right)=5x\left(3x-1\right)+7\left(3x-1\right)\)

\(\Leftrightarrow15x^2+3x+10x+2=15x^2-5x+21x-7\)

\(\Leftrightarrow15x^2-15x^2+3x+10x+5x-21x=-7-2\)

\(\Leftrightarrow-3x=-9\)

\(\Leftrightarrow x=3\)

Vậy x = 3

b) Ta có: \(\frac{x+1}{2x+1}=\frac{0,5x+2}{x+3}\Leftrightarrow\left(x+1\right)\left(x+3\right)=\left(2x+1\right)\left(0,5x+2\right)\)

                            \(\Leftrightarrow x\left(x+3\right)+\left(x+3\right)=2x\left(0,5x+2\right)+\left(0,5x+2\right)\)

                             \(\Leftrightarrow x^2+3x+x+3=x^2+4x+0,5x+2\)

                              \(\Leftrightarrow x^2-x^2+3x+x-4x-0,5x=2-3\)

                             \(\Leftrightarrow-0,5x=-1\Leftrightarrow x=2\)

Vậy x = 2

bài này sử dụng tích chéo nha bạn

z cau lamđi

Đây là những bài cơ bản mà bạn!

\(\frac{5x-2}{3}=\frac{5-3x}{2}\)

\(< =>\frac{\left(5x-2\right).2}{6}=\frac{\left(5-3x\right).3}{6}\)

\(< =>\left(5x-2\right).2=\left(5-3x\right).3\)

\(< =>10x-4=15-9x\)

\(< =>10x+9x=15+4\)

\(< =>19x=19< =>x=1\)

\(\frac{10x+3}{12}=1+\frac{6+8x}{9}\)

\(< =>\frac{\left(10x+3\right).3}{36}=\frac{36}{36}+\frac{\left(6+8x\right).4}{36}\)

\(< =>\left(10x+3\right).3=36+\left(6+8x\right).4\)

\(< =>30x+9=36+24+32x\)

\(< =>32x-30x=9-36-24\)

\(< =>2x=9-60=-51< =>x=-\frac{51}{2}\)