n: =345:(-345)=-1

n, (-15) x (-23) : (-345)

=   345  : (-345)

= -1

o, 36.55 - 185.11 + 121.5

 = 36.11.5 - 5.11.37 + 11.11.5

= 11.5.(36- 37 + 11)

= 11.5.10

= 550

ta có: \(\frac{-13}{-39}=\frac{13}{39}=\frac{1}{3}\left(1\right)\)

\(\frac{121}{363}=\frac{1}{3}\left(2\right)\)

từ (1) và (2) => \(\frac{-13}{-39}=\frac{121}{363}\)

\(\frac{-13}{-39}=\frac{-13.1}{-13.3}=\frac{1}{3}\)

\(\frac{121}{363}=\frac{121.1}{121.3}=\frac{1}{3}\)

\(\text{Vậy }\frac{-13}{-39}=\frac{121}{363}\)

\(\dfrac{11}{10}\)

11/10

11/10?

\(\dfrac{4}{-55}+-\dfrac{2}{-121}\)

\(=\dfrac{4}{-55}+\dfrac{2}{121}\)

\(=\dfrac{-44}{605}+\dfrac{10}{605}\)

\(=\dfrac{-44+10}{605}\)

\(=\dfrac{-34}{605}\)

`@` `\text {Ans}`

`\downarrow`

\(\dfrac{5}{9}\times121\times\dfrac{3}{55}\)

`=`\(\dfrac{605}{9}\times\dfrac{3}{55}=\dfrac{11}{3}\)

5/9 x 121 x 3/55

= 605/9 x 3/55

= 11/3.

 \(\dfrac{5}{9}\)  \(\times\) 121\(\times\) \(\dfrac{3}{55}\)  = \(\dfrac{5\times11\times11\times3}{3\times3\times5\times11}\) = \(\dfrac{11}{3}\) 

8578355

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