\(\left[18\frac{1}{6}-\left(0,06\div7\frac{1}{2}+3\frac{2}{5}\times0,38\right)\right]\div\left(19-2\frac{2}{3}\times4\frac{3}{4}\right)\)
Tinh \(\left\{18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0,38\right)\right\}:\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)
Tính
\(\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{3}.0,38\right)\right]:\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)
\(=\left[\dfrac{109}{6}-\left(\dfrac{3}{50}:\dfrac{15}{2}+\dfrac{11}{3}\cdot\dfrac{38}{100}\right)\right]:\left(19-\dfrac{8}{3}\cdot\dfrac{19}{4}\right)\)
\(=\left[\dfrac{109}{6}-\dfrac{1}{125}-\dfrac{209}{150}\right]:\left[19-\dfrac{38}{3}\right]\)
\(=\dfrac{6287}{375}:\dfrac{19}{3}\simeq2,647\)
Bài 1: Tính
\(\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{3}.0,38\right)\right]:\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)
Bài 2: Tìm x
\(\frac{-15}{12}.x+\frac{3}{7}=\frac{6}{5}.x-\frac{1}{2}\)
Thực hiện phép tính:
a) \(\left(\frac{1}{\sqrt{625}}+\frac{1}{5}+1\right)\) : \(\left(\frac{1}{25}-\frac{1}{\sqrt{25}}-1\right)\)
b) \(\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0,38\right)\right]\): \(\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)
\(a,\left(\frac{1}{\sqrt{625}}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{\sqrt{25}}-1\right)\)
\(=\left(\frac{1}{25}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{5}-1\right)\)
\(=\frac{31}{25}:\left(-\frac{29}{25}\right)\)
\(=\frac{31}{25}.\frac{-25}{29}\)
\(=-\frac{31}{29}\)
\(b,\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0,38\right)\right]:\left(19-2\frac{2}{3}.4\frac{3}{4}\right)\)
\(=\left[\frac{109}{6}-\left(\frac{3}{50}:\frac{15}{2}+\frac{17}{5}.\frac{19}{50}\right)\right]:\left(19-\frac{8}{3}.\frac{19}{4}\right)\)
\(=\left(\frac{109}{6}-\frac{13}{10}\right):\frac{19}{3}\)
\(=\frac{253}{15}.\frac{3}{19}\)
\(=\frac{253}{95}\)
Số to :v
Tính
1) \((\)\(\frac{55}{3}\)\(\div\)15+\(\frac{26}{3}\)\(\times\)\(\frac{7}{2}\)\()\)\(\div\)\([(\)\(\frac{37}{3}+\frac{62}{7})\times\frac{7}{18}]\div\frac{-1704}{445}\)
2) (\(\frac{1771}{25}\div23)\div\frac{77}{10}+11,45-(2,225-\frac{11}{8})]\times\frac{8}{55}\)
3) \([\frac{109}{6}-\left(0,06\div\frac{15}{2}+\frac{17}{5}\times0,38\right)]\div\left(19-\frac{8}{3}\times\frac{19}{4}\right)\)
1) ( \(\frac{55}{3}\): 15 + \(\frac{26}{3}\) . \(\frac{7}{2}\)) : [(\(\frac{37}{3}\) + \(\frac{62}{7}\)) . \(\frac{7}{18}\)] : \(\frac{-1704}{445}\)
= ( \(\frac{55}{3}\). \(\frac{1}{15}\) + \(\frac{91}{3}\)) : [ \(\frac{445}{21}\) . \(\frac{7}{18}\)] . \(\frac{-445}{1704}\)
= ( \(\frac{11}{9}\)+ \(\frac{91}{3}\)) : \(\frac{445}{54}\). \(\frac{-445}{1704}\) = \(\frac{284}{9}\). \(\frac{54}{445}\). \(\frac{-445}{1704}\)= \(\frac{284}{9}\). (\(\frac{54}{445}\). \(\frac{-445}{1704}\))
= \(\frac{284}{8}\). \(\frac{-9}{284}\)
= \(\frac{-9}{8}\)
Tính Giá Trị Của Biểu Thức
\(\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0.38\right)\right]:\left[16-2\frac{2}{3}.4\frac{3}{4}\right]\)
\(\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}\cdot0,38\right)\right]:\left[16-2\frac{2}{3}\cdot4\frac{3}{4}\right]\)
\(< =>\left[18\frac{1}{6}-\left(\frac{1}{125}+\frac{323}{250}\right)\right]:\left[16-\frac{38}{3}\right]\)
\(< =>\left[18\frac{1}{6}-\frac{13}{10}\right]:\frac{10}{3}\)
\(< =>\frac{253}{15}:\frac{10}{3}\)
\(< =>\frac{253}{50}\)
Tính giá trị biểu thức
\(A=\frac{\left(0,6\right)^5}{\left(0,3\right)^6}\) \(B=\frac{-1^3}{3^3+3\times6^2+6^3}\)
\(C=\frac{2\times5^5\times4^5}{20^4\times5^4}\) \(D=\left(\frac{-10}{3}\right)^3\times\left(\frac{-6}{5}\right)^3\)
\(E=2\div\left(\frac{1}{2}-\frac{2}{3}\right)^{^2}\) \(G=\left(\frac{4}{5}-\frac{3}{2}\right)^2\div\left(1-\frac{1}{4}+\frac{2}{3}\right)\)
Tính giá trị biểu thức:
\(\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}.0,85\right)\right]\) \(:\left(16-2\frac{2}{3}:4\frac{3}{4}\right)\)
Bài 1:
\(E=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\cdot230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right)\div\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Bài 2:
\(G=\frac{4,5\div\left[47,375-\left(26\frac{1}{3}-18\cdot0,75\right)\cdot2,4\div0,88\right]}{17,81\div1,37-23\frac{2}{3}\div1\frac{5}{6}}\)