Tìm x:
194 - ( 3 x X - 9 x 17 ) + 24 : 3 = 30
194-(3*x-9*17)+24:3=30
194-(3*x-9*17)=30-24/3
194-(3*x-9*17)=22
3*x-9*17=194-22
3*x-9*17=171
3*x=171+9*17
3*x=171+153
3*x=324
x=324/3
x=108
Vậy x=108
tìm x thuộc Z biết:
câu a:-12(-x+7).(3-x)=5
câu b:30.(x+2-6).(x-5)-24.x=100.|-9-x|=17
194 - (3.x-9. 17 ) + 8 = 30
các bạn làm diễn giải ra cho mình nhé
Ta có :
194 - ( 3.x - 9.17 ) + 8 = 30
=> ( 3.x - 9.17 ) + 8 = 194 - 30 = 164
3.x - 153 = 164 - 8 = 156
3.x = 156 + 153
3.x = 309
=> x = 309 : 3
x = 103
Đ/s : 103
194-(3.x-9.17)+8=30
=> 194-(3x-9.17)=22
=> 3x-9.17=194-22
=> 3x-9.17=172
=> 3x-9=172:17
=> 3x-9=172/17
=> 3x =172/17+9
=> 3x=325/17
=> x=325/17:3
=> x=325/51
Tìm x biết
d) 32%-0,25:x=-17/5
e)(x+1/5)^2+17/25=26/25
f)-32/27-(3x-7/9)^3=-24/27
g)60%x+0,4x+x:3=2
h)|20/9-x|=1/12+1/20+1/30+1/42+1/56+1/72
i)8/5+(2/7+2/17+2/37/5/7+5/17+5/37).x=16/5
Lưu ý: câu i 2/7+2/17+2/37 phần(vế trên) 5/7+5/17+5/37(vế dưới)
d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)
\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)
hay \(x=\dfrac{25}{372}\)
Vậy: \(x=\dfrac{25}{372}\)
e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)
\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)
f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)
\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)
\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)
\(\Leftrightarrow3x=\dfrac{1}{9}\)
hay \(x=\dfrac{1}{27}\)
g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)
\(\Leftrightarrow\dfrac{4}{3}x=2\)
hay \(x=\dfrac{3}{2}\)
Vậy: \(x=\dfrac{3}{2}\)
h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)
Vậy ...
i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)
Vậy ...
tìm X
194-24:(12:3*X-3)-25=145
194 - 24 : ( 12 : 3 . x - 3 ) - 25 = 145
194 - 24 : ( 4 . x - 3 ) - 25 = 145
194 - 24 : ( 4 . x - 3 ) = 145 + 25
194 - 24 : ( 4 . x - 3 ) = 170
24 : ( 4 . x - 3 ) = 194 - 170
24 : ( 4 . x - 3 ) = 24
4 . x - 3 = 24 : 24
4 . x - 3 = 1
4 . x = 1 + 3
4 . x = 4
x = 4 : 4
x = 1
- Hok t -
194 - 24 : ( 12 : 3 . x - 3 ) - 25 = 145
194 - 24 : ( 12 : 3 . x - 3) = 145 + 25
194 - 24 : ( 12 : 3 . x - 3 ) = 170
24 : ( 12 : 3 . x - 3 ) = 194 - 170
24 : ( 12 : 3 . x - 3 ) = 24
12 : 3 . x - 3 = 24 : 24
12 : 3 . x - 3 = 1
12 : 3 . x = 1 + 3
12 : 3 . x = 4
3 . x = 12 : 4
3 . x = 3
x = 3 : 3
x = 1
-HT-
x-5=-1
x+30=-4
x-(-24)=3
22-(-x)=12
(x+5)+(x-9)=x+2
(x-29)-(17-38)=-9
\(x-5=-1\)
\(x=4\)
\(x+30=-4\)
\(x=-34\)
\(x+24=3\)
\(x=-21\)
\(22-\left(-x\right)=12\)
\(22+x=12\)
\(x=33\)
x - 5 = -1 => x = -1 + 5 = 4
x + 30 = -4 => x = -4 - 30 = -34
x - (-24) = 3 => x + 24 = 3 => x = 3 - 24 => x = -21
22 - (-x) = 12 => 22 + x = 12 => x = 22 - 12 = 10
( x + 5 ) + ( x - 9 ) = x + 2
=> x + 5 + x - 9 = x + 2
=> 2x + 5 - 9 = x + 2
=> 2x = x + 2 + 9 - 5 = x + 6
=> x = 6
bài 1: tìm x thuộc Z
a) 10-x-5=(-5)-7-11
b) (x-3)-(x+17-24)-(25-x)=24-(-30)
c) (7-9x)-(2x-4)=-(5.x+35)-(-27)-(+25)
a: =>5-x=-23
=>x=5+23=28
b: =>x-3-x+7-25+x=54
=>x-21=54
=>x=75
c: =>7-9x-2x+4=-5x-35+27-25=-5x-37
=>-11x+3=-5x-37
=>-6x=-40
=>x=20/3
a) \(10-x-5=\left(-5\right)-7-11\)
\(\Rightarrow5-x=-23\)
\(\Rightarrow x=5+23\)
\(\Rightarrow x=28\)
b) \(\left(x-3\right)-\left(x+17-24\right)-\left(25-x\right)=24-\left(-30\right)\)
\(\Rightarrow x-3-x-17+24-25+x=54\)
\(\Rightarrow x-21=54\)
\(\Rightarrow x=54+21\)
\(\Rightarrow x=75\)
c) \(\left(7-9x\right)-\left(2x-4\right)=-\left(5x+35\right)-\left(-27\right)-25\)
\(\Rightarrow7-9x-2x+4=-5x-35+27-25\)
\(\Rightarrow11-11x=-5x-33\)
\(\Rightarrow-11x+5x=-33-11\)
\(\Rightarrow-6x=-22\)
\(\Rightarrow x=\dfrac{22}{6}=\dfrac{11}{3}\)
a.
10-x-5 = (-5) - 7 -11
=>5-x = 0
=>x=5
b
(x-3) - (x+17-24) - (25-x) = 24 - (-30)
=>x - 3 - x - 17 + 24 - 25 - x = 24 + 30
=>-x - 21 = 54
=>-x = 75
=>x = -75
c
(7 - 9x) - (2x - 4) = - (5x + 35) - (-27) - 25
=>7-9x - 2x + 4 = -5x - 35 + 27 - 35
=>11 - 11x + 5x = -43
=>16x = 11 + 43
=>16x = 54
=>x=4
Tìm x, biết:
a) x + 39 = 51 + 17
b) 41– x = 24 – 9
c) x – 33 = 19 + 10
d) x + 30 = 74 – 32
194-24:(44*x-3)-25=145
x *1/3:2/9-x:5=1 2/5
Trả lời:
\(194-24\div\left(44x-3\right)-25=145\)
\(\Leftrightarrow194-24\div\left(44x-3\right)=170\)
\(\Leftrightarrow24\div\left(44x-3\right)=24\)
\(\Leftrightarrow44x-3=1\)
\(\Leftrightarrow44x=4\)
\(\Leftrightarrow x=\frac{1}{11}\)
Vậy \(x=\frac{1}{11}\)
\(x\times\frac{1}{3}\div\frac{2}{9}-x\div5=1\frac{2}{5}\)
\(\Leftrightarrow x\times\frac{1}{3}\times\frac{9}{2}-x\times\frac{1}{5}=\frac{7}{5}\)
\(\Leftrightarrow x\times\frac{3}{2}-x\times\frac{1}{5}=\frac{7}{5}\)
\(\Leftrightarrow x\times\left(\frac{3}{2}-\frac{1}{5}\right)=\frac{7}{5}\)
\(\Leftrightarrow x\times\frac{13}{10}=\frac{7}{5}\)
\(\Leftrightarrow x=\frac{14}{13}\)
Vậy \(x=\frac{14}{13}\)
lp 5 chua hoc 4x moi chi hoc 44 * x thui nha!
194-24:(44×x-3)=145+25
194-24:(44×x-3)=170
24:(44×x-3)=194-170
24:(44×x-3)=24
(44×x-3)=24:24
(44×x-3)=1
44×x=1+3
44×x=4
x=4:44
x=1/11
vậy x=1/11