(x+1)+(x+4)+(x+7)+(x+10)+(x+13)+(x+16)+(x+19)+(x+22)+(x+25)+(x+28)=155
tim x : (x+1)+(x+4)+(x+7)+(x+10)+(x+13)+...................+(x+28)=155
(x+1)+(x+4)+.....+(x+28)=155 tìm x
(x+x+.....+X)+(1+4+...+28)=155
10 x
10x + 145 =155
10x=10
x=10:10
x=1
Tính hợp lý:
1) 35 x 18 - 5 x 7 x 18
2) 45 - 5 x ( 12 + 9)
3) 24 x ( 16 - 5) - 16 x ( 24 - 5)
4) 29 x ( 19 - 13) - 19 x ( 29 - 13 )
5) 31 x (-18) + 31 x (-81) - 31
6) (-12) x 47 + (-12) x 52 + (-12)
7) 13 x ( 23 + 22 ) - 3 x ( 17 + 28 )
8) -48 + 48 x (-78) + 48 x (-21)
1) = 35 . 18 - 35 . 18 = 0
2) = 45 - 5 . 12 + 5 . 9 = 45 - 60 + 45 = 30
3) = 24 . 16 - 24 . 5 - 16 . 24 - 16 . 5
= (24 . 16 - 16 . 24) - 5 (24 - 16)
= 0 - 5 . 8 = 0 - 40 = -40
4) = 29 . 19 - 29 . 13 - 19 . 29 - 19 . 13
= (29 . 19 - 29 . 19) - 13 (29 - 19)
= 0 - 13 . 10 = 0 - 130 = -130
5) = 31 . (-18) + 31 . (-81) - 31 . 1
= 31 [(-18) + (-81) - 1]
= 31 . (-100) = -3100
6) = (-12) . 47 + (-12) . 52 + (-12). 1
= (-12) . (47 + 52 + 1)
= (-12) . 100 = -1200
7) = 13 . 45 - 3 . 45
= 45 (13 - 3)
= 45 . 10 = 450
8) = (-48) + 48 . (-78) + 48 . (-21)
= (-48) . 1 + 48 . (-78) + 48 . (-21)
= 48 . (-1) + 48 . (-78) + 48 . (-21)
= 48 . [(-1) + (-78) + (-21)]
= 48 . (-100) = -4800
1) 35x18-5x7x18
= 35x18-35x18
= 35x(18-18)
= 35x0=0
3) 24.(16-5)-16.(24-5)
= 24.16-24.5-16.24-16.5
=[24.16-16.24]-[24.5-16.5]
= [ 24. (16-16)]- [(24-16).5]
= [24.0]-[8.5]
= 0-40=-40
4) 29.(19-13)-19.(29-13)
=29.19-29.13-19.29-19.13
=[ 29.19-19.29]-[ 29.13-19.13]
= [ 29.(19-19)]-[(29-19).13]
=[29.0]-[10.13]
= 0-130= -130
5) 31.(-18)+31.(-81)-31
= 31.(-18)+31.(-81)-31.1
= 31.[(-18)+(-81)-1]
=31.(-100)
= -3100
6);7);8 tương tự 4);5);6)
d/ khó lắm đó nha. ai biết minh tích
38/25 + 9/10 - 11/15 + 13/21 - 15/28 + 17/36 - ............. + 197/4851 - 199/4950.
2. ( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ......... + ( x + 28 ) = 155
( x + 1 ) + ( x + 4 ) + ( x + 7 ) + ......... + ( x + 28 ) = 155
<=>(x+x+x...+x)+(1+4+...+28)=155
=>10x+145=155
=>10x=155-145
=>10x=10
=>x=1
Tính nhanh:
a) 78 x 13 +13 x 22
b) 25 x 70 + 28 x 25 + 50
c) ( 45 x 28 x 19 ) : ( 19 x 14 x 15)
d) ( 132 x70 x60 ) : ( 12 x 35 x 20 )
GIÚP MÌNH VỚI Ạ ,MÌNH ĐANG CẦN GẤP
\(a.13.\left(78+22\right)=13.100=1300\)
\(b.25.70+28.25+25.2=25.\left(70+28+2\right)=25.100=2500\)
\(c.\dfrac{15.3.14.2.19}{19.14.15}=6\)
\(d.\dfrac{132.70.60}{12.35.20}=\dfrac{11.12.35.2.20.3}{12.35.20}=66\)
a. ) x-22/8 + x-21/9 + x-20/10 + x-19/11 =4
b -x+12/7 + -x+13/6 = -x+15/4 + -x+16/3
\(a,\frac{x-22}{8}+\frac{x-21}{9}+\frac{x-20}{10}+\frac{x-19}{11}\)
\(a,\frac{x-22}{8}+\frac{x-21}{9}+\frac{x-20}{10}+\frac{x-19}{11}=4\)
\(\Leftrightarrow\frac{x-22}{8}-1+\frac{x-21}{9}-1+\frac{x-20}{10}-1+\frac{x-19}{11}-1=0\)
\(\Leftrightarrow\frac{x-30}{8}+\frac{x-30}{9}+\frac{x-30}{10}+\frac{x-30}{11}=0\)
\(\Leftrightarrow\left(x-30\right)\left(\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}\right)=0\)
\(\Leftrightarrow\left(x-30\right)=0\)
\(\Leftrightarrow x=30\)
\(b,\frac{-x+12}{7}+\frac{-x+13}{6}=\frac{-x+15}{4}+\frac{-x+16}{3}\)
\(\Leftrightarrow\frac{-x+12}{7}+1+\frac{-x+13}{6}+1=\frac{-x+15}{4}+1+\frac{-x+16}{3}+1\)
\(\Leftrightarrow\frac{19-x}{7}+\frac{19-x}{6}-\frac{19-x}{4}-\frac{19-x}{3}=0\)
\(\Leftrightarrow\left(19-x\right)\left(\frac{1}{7}+\frac{1}{6}-\frac{1}{4}-\frac{1}{3}\right)=0\)
\(\Leftrightarrow19-x=0\)
\(\Leftrightarrow x=19\)
Tìm x biết:
a, x+1/10+x+1/11+x+1/12+x+1/13
b,x+10/20+x+8/22=x+6/24+x+3/27
c,x+7/19+x3/15=x+7/16+x+3/15
Bui Bao Ngoc oi! phan a,la (x+1)/10 hay x+(1/10)?
cac phan khac nua!
(x+1)+(x+4)+(x+4)+(x+7)+(x+10)+........+(x+28)=155
(x+1) + (x+4) + ( x+7 ) + (x+10)+...+(x+28)=155
x+1 + x+4 + x+7 + x+10 + ...+ x+28 = 155
(x+x+x+x+...+x) + (1+4+7+10+...+28) = 155
((28-1):3+1=10 (x) + (28 +1 ) . 10 : 2 = 145 )*cách tính*
x.10 + 145 = 155
x.10 = 155 - 145
x.10 =10
x = 10:10
x =1
x bằng 1 nha bạn
đúng 100% luôn
Bài 1: a) 3/10 x13 + 3 / 13 x 16 + 3 / 16 x 19 + .......+ 3 58 x 61
b) 1 / 4 x 7+ 1/7 x 10 = 1 / 10 x 13 + 1/ 13 x 16 + 1/ 16x19
cach lam thi ko nho nhung ket qua 100 % la 51/610
(X + 1) + (X + 4) + (X +7) +(X + 10) + . . . + (X + 28) = 155
\(\left(x+1\right)+\left(x+4\right)+...+\left(x+28\right)=155\)
\(\Leftrightarrow10x=10\)
hay x=1