C

Literature is my favorite subject.

I like literature the most

\(\left(123\text{ ×}0,25+123\text{ ×}0,75\right)\text{ ×}\left(11\text{ ×}9-900\text{ ×}0,1-9\right)\)

\(=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}100\text{×}0,1-9\text{×}1\right)\)

\(=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}10-9\text{×}1\right)\)

\(=\left[123\left(0,25+0,75\right)\right]\text{×}\left[9\text{×}\left(11-10-1\right)\right]\)

\(=\left(123\text{×}1\right)\text{×}\left(9\text{×}0\right)=123\text{×}0=0\)

$\left(123\text{ ×}0,25+123\text{ ×}0,75\right)\text{ ×}\left(11\text{ ×}9-900\text{ ×}0,1-9\right)$

$=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}100\text{×}0,1-9\text{×}1\right)$

$=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}10-9\text{×}1\right)$

$=\left[123\left(0,25+0,75\right)\right]\text{×}\left[9\text{×}\left(11-10-1\right)\right]$

$=\left(123\text{×}1\right)\text{×}\left(9\text{×}0\right)$

$=123\text{×}0$

$=0$

$=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}100\text{×}0,1-9\text{×}1\right)$

$=\left(123\text{×}0,25+123\text{×}0,75\right)\text{ ×}\left(11\text{×}9-9\text{×}10-9\text{×}1\right)$

$=\left[123\left(0,25+0,75\right)\right]\text{×}\left[9\text{×}\left(11-10-1\right)\right]$

$=\left(123\text{×}1\right)\text{×}\left(9\text{×}0\right)=123\text{×}0=0\; (nhớ\; tick\; cho\; mình\; nha:3)$

1 He told her she was his friend

2 Johnny told his mother he didn't know how to do that exercise

3 My brother advised me not to come back before 1 o'clock

4 Mrs Brown told her daughter to cook it in butter

5 THe pupils told the teacher to give them better marks

6 My friend asked me if I was going to leave the day after

7 My mother asked me if I had done my homework

8 I asked Bill what time he had gone to bed the night before

( 10*2 + 11*2 + 12*3 ) : ( 13*2+14*2 ) 

= 1949 : 365 

= 5,339726027

Chắc thế rồi chứ tui ko chắc lắm 

\(\dfrac{1}{\left(x^2+4x+3\right)^3}=\dfrac{1}{\left(x+1\right)^3\left(x+3\right)^3}\)

Phân tích hệ số bất định:

\(=\dfrac{a_1}{x+1}+\dfrac{a_2}{\left(x+1\right)^2}+\dfrac{a_3}{\left(x+1\right)^3}+\dfrac{b_1}{x+3}+\dfrac{b_2}{\left(x+3\right)^2}+\dfrac{b_3}{\left(x+3\right)^3}\)

Cách phân tích thứ 2:

\(=\dfrac{a\left(x+2\right)}{x^2+4x+3}+\dfrac{b\left(x+2\right)}{\left(x^2+4x+3\right)^2}+\dfrac{c}{x+1}+\dfrac{d}{x+3}\)

À mà cách thứ 2 hình như ko đúng, bậc ko đảm bảo

Bài này mẫu số hơi đặc biệt nên có thể ko cần máy móc như vậy:

\(\left(\dfrac{1}{\left(x+1\right)\left(x+3\right)}\right)^3=\dfrac{1}{8}\left(\dfrac{1}{x+1}-\dfrac{1}{x+3}\right)^3\)

Khai triển nó ra có vẻ dễ thực hiện hơn

Kiên nhẫn đi :)

Trên thực tế, những bài kiểu này ko cần quan tâm, vì ko ai cho cả