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Hoà Lương Văn
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20Lý Nguyễn Tuyết Nhi9a1
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Thảo Phương
22 tháng 11 2021 lúc 21:08

\(4Al+3O_2-^{t^o}\rightarrow2Al_2O_3\\ Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3-^{t^o}\rightarrow Al_2O_3+3H_2O\\ Al_2O_3-^{đpnc,criolit}\rightarrow2Al+\dfrac{3}{2}O_2\\ 2Al+6HCl\rightarrow2AlCl_3+3H_2\)

Nguyễn Nho Bảo Trí
22 tháng 11 2021 lúc 21:06

\(Al\underrightarrow{1}Al_2O_3\underrightarrow{2}AlCl_3\underrightarrow{3}Al\left(OH\right)_3\underrightarrow{4}Al_2O_3\underrightarrow{5}Al\underrightarrow{6}AlCl_3\)

(1) \(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)

(2) \(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

(3) \(AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\)

(4) \(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

(5) \(2Al_2O_3\xrightarrow[criolit]{điện.phân.nóng.chảy}4Al+3O_2\)

(6) \(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

 Chúc bạn học tốt

 

linh nguyen
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B.Thị Anh Thơ
24 tháng 3 2020 lúc 8:50

\(3Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

\(Al_2\left(SO_4\right)_3+3Cu\rightarrow3CuSO_4+2Al\)

\(4Al+3O_2\rightarrow2Al_2O_3\)

\(Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\)

\(AlCl_3+3H_2O\rightarrow Al\left(OH\right)_3+3HCl\)

\(2Al\left(OH\right)_3\rightarrow Al_2O_3+3H_2O\)

\(2Al_2O_3\rightarrow4Al+3O_2\)

\(2Al+3Cl_2\rightarrow2AlCl_3\)

Khách vãng lai đã xóa
Ngọc Nhi
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Lê Ng Hải Anh
18 tháng 12 2023 lúc 21:15

\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)

\(AlCl_3+3NaOH\rightarrow3NaCl+Al\left(OH\right)_3\)

\(2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\)

\(Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\)

\(AlCl_3+3AgNO_3\rightarrow3AgCl+Al\left(NO_3\right)_3\)

\(Al\left(NO_3\right)_3+3KOH\rightarrow3KNO_3+Al\left(OH\right)_3\)

\(2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\)

\(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

HaNa
18 tháng 12 2023 lúc 21:20

\(Al+\dfrac{3}{2}Cl_2\rightarrow AlCl_3\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+6H_2O\\ Al_2\left(SO_4\right)_3+3BaCl_2\rightarrow2AlCl_3+3BaSO_4\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ Al\left(NO_3\right)_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaNO_3\\ 2Al\left(OH\right)_3\underrightarrow{t^o}Al_2O_3+3H_2O\\ Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

Huy Huy Anh
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Nguyễn Sỹ Tấn
29 tháng 12 2020 lúc 21:42

4Al+3O2----to--->2Al2O3

Al2O3 +3H2SO4----->Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2------>2AlCl3+3BaSO4

2AlCl3+3Ca(OH)2---->2Al(OH)3+3CaCl2

Al(OH)3+3HNO3---->Al(NO3)3+3H2O

2Al(NO3)3+3Mg----->3Mg(NO3)2+2Al

2Al+3H2SO4------->Al2(SO4)3+3H2

Al2(SO4)3+3Ca(OH)2------>2Al(OH)3+3CaSO4

2Al(OH)3-----to----->Al2O3+3H2O

2Al2O3----\(\dfrac{t^o}{criolit}\)---->4Al+3O2

2Al+2H2O+2NaOH------>2NaAlO2+3H2

Kresol♪
29 tháng 12 2020 lúc 21:50

4Al+3O2\(\underrightarrow{t^o}\) 2Al2O3

Al2O3+H2SO4 —> Al2(SO4)3+3H2O

Al2(SO4)3+3BaCl2–>3BaSO4\(\downarrow\)+2AlCl3

AlCl3+3NaOH—>Al(OH)3\(\downarrow\)+3NaCl

Al(OH)3+HNO3 —>Al(NO3)3+NO2\(\uparrow\)+H2O

2Al(NO3)3+3Mg—>3Mg(NO3)2+2Al\(\downarrow\)

2Al+3H2SO4–>Al2(SO4)3+3H2\(\uparrow\)

Al2(SO4)3+6NaOH—>2Al(OH)3+3Na2SO4

2Al(OH)3\(\underrightarrow{t^o}\)Al2O3+3H2O

2Al2O3\(\xrightarrow[criolit]{đien.phan.nong.chay}\)

4Al+3O2

2Al+2NaOH+2H2O—>2NaAlO2+3H2

Nguyễn Mạnh Tuấn
29 tháng 12 2020 lúc 23:04

\(\begin{array}{l} 4Al+3O_2\xrightarrow{t^o} 2Al_2O_3\\ Al_2O_3+3H_2SO_4\to Al_2(SO_4)_3+3H_2O\\ Al_2(SO_4)_3+3BaCl_2\to 3BaSO_4\downarrow+2AlCl_3\\ AlCl_3+3NaOH\to Al(OH)_3\downarrow+3NaCl\\ Al(OH)_3+3HNO_3\to Al(NO_3)_3+3H_2O\\ 2Al(NO_3)_3+3Mg\to 3Mg(NO_3)_2+2Al\\ 2Al+3H_2SO_4\to Al_2(SO_4)_3+3H_2\uparrow\\ Al_2(SO_4)_3+6NaOH\to 2Al(OH)_3\downarrow+3Na_2SO_4\\ 2Al(OH)_3\xrightarrow{t^o} Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow{\text{đpnc, Criolit}} 4Al+3O_2\uparrow\\ 2Al+2NaOH+2H_2O\to 2NaAlO_2+3H_2\uparrow\end{array}\)

vu chu
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hnamyuh
28 tháng 12 2022 lúc 13:25

$4Al + 3O_2 \xrightarrow{t^o} 2Al_2O_3$
$Al_2O_3 + 6HCl \to 2AlCl_3 + 3H_2O$
$AlCl_3 + 3KOH \to Al(OH)_3 + 3KCl$
$2Al(OH)_3 \xrightarrow{t^o} Al_2O_3 + 3H_2O$
$2Al_2O_3 \xrightarrow{dpnc} 4Al + 3O_2$

Linh
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Linh
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Ngọc hà
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乇尺尺のレ
23 tháng 11 2023 lúc 21:30

\(4Al+3O_2\xrightarrow[t^0]{}2Al_2O_3\\ Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\xrightarrow[t^0]{}Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow[criolit]{đpnc}4Al+3O_2\\ 2Al+2NaOH+2H_2O\rightarrow2NaAlO_2+3H_2\)

Hien My
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乇尺尺のレ
26 tháng 11 2023 lúc 20:53

\(a,4Al+3O_2\xrightarrow[t^0]{}2Al_2O_3\\ Al_2O_3+6HCl\rightarrow2AlCl_3+3H_2O\\ AlCl_3+3AgNO_3\rightarrow Al\left(NO_3\right)_3+3AgCl\\ AlCl_3+3NaOH\rightarrow Al\left(OH\right)_3+3NaCl\\ 2Al\left(OH\right)_3\xrightarrow[t^0]{}Al_2O_3+3H_2O\\ 2Al_2O_3\xrightarrow[đpnc]{criolit}4Al+3O_2\\ b,3Fe+2O_2\xrightarrow[t^0]{}Fe_3O_4\\ Fe_3O_4+8HCl\rightarrow2FeCl_3+FeCl_2+4H_2O\\ FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\\ 2Fe\left(OH\right)_3\xrightarrow[t^0]{}Fe_2O_3+3H_2O\\ Fe_2O_3+3CO\xrightarrow[t^0]{}2Fe+3CO_2\)

\(c,2Fe\left(OH\right)_3+3H_2SO_4\rightarrow Fe_2\left(SO_4\right)_3+6H_2O\\ Fe_2\left(SO_4\right)_3+3BaCl_2\rightarrow2FeCl_3+3BaSO_4\\ FeCl_3+AgNO_3\rightarrow Fe\left(NO_3\right)_3+3AgCl\)