(x+1).(xy-2)=11
xy-7x+y=-22
xy-3x+y=-20
xy-5y-2x=-41
lam ca cach trinh bay giup mk nhe
mk se tich dung cho
Tìm x,y thuộc Z: xy-3x+2y=-5. câu b. 2xy-x+y=-3............. Cac ban trinh bay cach giai giup mink nhe .Neu ai giai dung mink se tick
17x+3(-16x-37)=2x+43-4x
{-3x+2[45-x-3(3x+7)-2x]+4x}=55
103-57:[-2.(2x-1)2-(-9)0]=-106
lam ca cach trinh bay giup mk nhe
mk se tich dung cho
Bài 1:
a, -2x+3.{12-2[3x-(20+2x)-4x]+1}=45
b,3x-32>-5x+1
c,15+4x<2x-145
d, x+(x+1)+(x+2)+(x+3)+.....+13+14=14
lam ca cach trinh bay giup mk nhe
mk se tich dung cho
Giup minh voi toi nay minh rat can, dung thi minh tich cho, ca cach lam nua nhe.
Tim x,y
a, 2x.y+xy=7
b, xy + 2x - 7y = 14
c, x^3 - 64x = 0
Thu gọn đa thức sau
Q= 7x2y - 2xy + 1/2x2y - xy + 11xy - 1/3x+ 1/3+2/3x- 1/6
\(Q=7x^2y-2xy+\dfrac{1}{2}x^2y-xy+11xy-\dfrac{1}{3}x+\dfrac{1}{3}+\dfrac{2}{3}x-\dfrac{1}{6}\)
\(Q=\dfrac{15}{2}x^2y+8xy-x-\dfrac{1}{6}\)
Q = ( 7x\(^2\)y + \(\dfrac{1}{2}\)x\(^2\)y ) + ( -2xy - xy + 11xy ) +( -\(\dfrac{1}{3}\)x + \(\dfrac{2}{3}\)x ) + ( -\(\dfrac{1}{3}\) - \(\dfrac{1}{6}\) )
= \(\dfrac{15}{2}\)x\(^2\)y + 8xy + \(\dfrac{1}{3}\)x _ \(\dfrac{1}{2}\)
Phan tich da thuc thanh nhan tu :
a, -x^3 * ( 2x + 1 )^2 + 49x
b, 125x^2 + 20y - 5y^2 - 20
c, ( 1+ 2x )*(1 - 2x ) - x*(x + 2 )*( x - 2 )
d, ( x - z )*(x + z) - y*(2x - y )
e, x^2 - 3x - 54
Giup minh voi nhe cac ban. Minh se tick cho.
a: \(=x\left[49-x^2\left(2x+1\right)^2\right]\)
\(=x\left[49-\left(2x^2+x\right)^2\right]\)
\(=x\left[\left(7-2x^2-x\right)\left(7+2x^2+x\right)\right]\)
b: \(=5\left[25x^2-\left(y^2-4y+4\right)\right]\)
\(=5\left[\left(5x-y+2\right)\left(5x+y-2\right)\right]\)
c: \(=1-4x^2-x\left(x^2-4\right)\)
\(=1-4x^2-x^3+4x\)
\(=\left(1-x\right)\left(1+x+x^2\right)-4x\left(x-1\right)\)
\(=\left(1-x\right)\left(1+x+x^2+4x\right)\)
\(=\left(1-x\right)\left(x^2+5x+1\right)\)
e: =(x-9)(x+6)
1, (x+1)2-3(x+1)
2, 2x(x-2) - (x-2)2
3, 4x2-20xy+ 25y2
4, x2+3x-x-3
5, x2-xy+x-y
6, 2y(x+2)-3x-6 giai giup em voi ạ
\(\left(x+1\right)^2-3\left(x+1\right)=\left(x+1\right)\left(x+1-3\right)=\left(x+1\right)\left(x-2\right)\)
\(2x\left(x-2\right)-\left(x-2\right)^2=\left(x-2\right)\left[2x-\left(x-2\right)\right]=\left(x-2\right)\left(2x-x+2\right)=\left(x-2\right)\left(x+2\right)\)
\(4x^2-20xy+25y^2=\left(2x\right)^2-2.2x.5y+\left(5y\right)^2=\left(2x-5y\right)^2\)
\(x^2+3x-x-3=x\left(x+3\right)-\left(x+3\right)=\left(x-1\right)\left(x+3\right)\)
\(x^2-xy+x-y=x\left(x-y\right)+\left(x-y\right)=\left(x-y\right)\left(x+1\right)\)
\(2y\left(x+2\right)-3x-6=2y\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(2y-3\right)\)
xy-7x+y=-22
xy-3x+y=-20
xy-5y-2x=-41
TÌM X
GIÚP MK NHA
Toi cung co cau giong the nhung tra lam duoc
xy - 7x + y = -22
xy + y - 7x = -22
y ( x + 1 ) - 7x = -22
y ( x + 1 ) - 7x - 7 = -29
y ( x + 1 ) - ( 7x + 7 ) = -29
y ( x + 1 ) - 7 . ( x + 1 ) = -29
( y - 7 ) . ( x + 1 ) = -29
ta có bảng sau :
y-7 | -29 | 1 | -1 | 29 |
x+1 | 1 | -29 | 29 | -1 |
y | -22 | 8 | 6 | 36 |
x | 0 | -30 | 28 | -2 |
Vậy ....
moi nguoi oi giup minh voi, ca cach giai nua nhe, dung thi minh se tich cho. thank you moi nguoi
tim x biet
x^2 - 1 < 15