so nguyen duong x thoa man la ? biet x/9<7/x<x/6
GIUP MIK NHA
Mik se tk cho ai ma giai dung
(nho la giai chi tiet ra nhe)
cho x va y la so nguyen duong nho hon 10 ,thoa man 3x-4y=-21
3x=4y-21
<=> x=(4y/3)-7
Thay x=1; x=2; .... x=9
Được 2 nghiệm:
x=1 <=> 8=(4y/3) <=> 24=4y <=>y=6
x=5 <=> 12=(4y/3) <=> 36=4y <=> y=9
Đáp số:
x=1 y=6
x=5 y=9
Cap so nguyen duong ( x,y ) thoa man |(x2 + 2).(y + 1)| = 9 la (x,y)=.....
(Nhap cac gia tri theo thu tu , cach nhau boi dau;)
Tim cac so nguyen duong x;y;z thoa man x!+y!=10.z+9
so nguyen duong x thoa man 8<2^x<2^9:2^4
tá có: 8 < 2x < 29:24
=> 23 < 2x < 25
=> 3 < x < 5 Vì x là số nguyên dương nên x = 4
a)Tim tat ca cac so nguyen duong x, y , z thoa man: \(\frac{x+y\sqrt{2013}}{y+z\sqrt{2013}}\)la so huu ti, dong thoi x2 + y2+ z2 la so nguyen to.
b) Tim so tu nhien x, y thoa man: x(1+x+x2) = y(y-1).
cap so nguyen duong x;y thoa man |(x2+2).(y+1)| =9
cho (xo;yo) la cac so nguyen duong thoa man : (x - 2) (2x + 3)=26
khi do xo + yo =
cho x,y la cac so nguyen duong thoa man \(9y\left(y-x\right)=4x^2tinhA=\frac{x-y}{x+y}\)
\(4x^2=9y\left(y-x\right)\)
\(\Leftrightarrow4x^2+9xy-9y^2=0\)
\(\Leftrightarrow\left(4x^2-3xy\right)+\left(12xy-9y^2\right)=0\)
\(\Leftrightarrow\left(4x-3y\right)\left(x+3y\right)=0\)
Mà x;y>0 nên x+3y>0
=> 4x-3y=0
=>4x=3y
Thay vào mà tính
cho 2017 so nguyen thoa man tich cua 17 so nguyen bat ki la mot so nguyen duong .chung minh 2017 so nguyen da cho deu la so nguyen duong
toan lop 6