\(a^3+4a^2-7a-10\)

\(=\left(a^3+5a^2\right)-\left(a^2+5a\right)-\left(2a+10\right)\)

\(=a^2\left(a+5\right)-a\left(a+5\right)-2\left(a+5\right)\)

\(=\left(a^2-a-2\right)\left(a+5\right)\)

\(=\left(a^2-2a+a-2\right)\left(a+5\right)\)

\(=\left[a\left(a-2\right)+\left(a-2\right)\right]\left(a+5\right)\)

\(=\left(a+1\right)\left(a-2\right)\left(a+5\right)\)

\(a.25^2-4a^2+12ab-9b^2\\ =25^2-\left(4a^2+12ab-9b^2\right)\\ =25^2-\left(2a-3b\right)^2\\ =\left(25-2a+3b\right)\left(25+2a-3b\right)\\ b.x^3+x^2y-xy^2-y^3\\ =x^2\left(x+y\right)-y^2\left(x+y\right)\\ =\left(x+y\right)\left(x^2-y^2\right)\\ =\left(x+y\right)\left(x+y\right)\left(x-y\right)\\ =\left(x+y\right)^2\left(x-y\right)\)

a: Ta có: \(25x^2-4a^2+12ab-9b^2\)

\(=25x^2-\left(2a-3b\right)^2\)

\(=\left(5x-2a+3b\right)\left(5x+2a-3b\right)\)

b: Ta có: \(x^3+x^2y-xy^2-y^3\)

\(=\left(x-y\right)\left(x^2+xy+y^2\right)+xy\left(x-y\right)\)

\(=\left(x-y\right)\left(x+y\right)^2\)

\(a^3+4a^2+4a+3\)

\(=a^3+a^2+3a^2+3a+a+3\)

\(=\left(a^3+a^2+a\right)+\left(3a^2+3a+3\right)\)

\(=a\left(a^2+a+1\right)+3\left(a^2+a+1\right)\)

\(=\left(a+3\right)\left(a^2+a+1\right)\)

4a²b² + 36a²b³ + 6ab⁴

= 2ab²(2a + 18ab + 3b²)

4a²b³ - 6a³b²

= 2a²b²(2b - 3a)

Đa thức không phân tích được thành nhân tử bạn nhé. 

E = x^3 - 3x^2 + 7x^2 - 21x - 8x + 24

  = x^2 ( x- 3 ) + 7x ( x- 3 ) - 8 ( x- 3 )

= ( x- 3 )(x^2 + 7x - 8 )

= ( x- 3 )[ x^2 + 8x - x - 8 ) 

= ( x -3 ) [ x(x + 8 ) - ( x + 8 ) ]

= ( x- 3  )( x - 1 )( x +  8)  

=a³-3a²+7a²-21a-8a+24

=a²(a-3)+7a(a-3)-8(a-3)

=(a-3)(a²+7a-8)

=(a-3)(a²-a+8a-8)

=(a-3)(a+8)(a-1)

a² - 4a + 3

= a² - a - 3a + 3

= a.(a - 1) - 3.(a - 1)

= (a - 1).(a - 3)

=   \(a^2-3a-a+3\)= \(a\left(a-3\right)-\left(a-3\right)\)=   \(\left(a-3\right)\left(a-1\right)\)