a: \(\left(x^3-x^2+x\right)\left(121-25y^2-10y\right)-\left(x^3-x^2+x\right)-\left(121-25y^2-10y\right)+1\)

\(=\left(x^3-x^2+x\right)\left(120-25y^2-10y\right)-\left(120-25y^2-10y\right)\)

\(=\left(120-25y^2-10y\right)\left(x^3-x^2+x-1\right)\)

\(=-\left[\left(25y^2+10y+1\right)-121\right]\left[x^2\left(x-1\right)+\left(x-1\right)\right]\)

\(=-\left(5y-10\right)\left(5y-12\right)\left(x-1\right)\left(x^2+1\right)\)

\(=-5\left(y-2\right)\left(5y-12\right)\left(x-1\right)\left(x^2+1\right)\)

b: \(x^4-14x^3+71x^2-154x+120\)

\(=x^4-5x^3-9x^3+45x^2+26x^2-130x-24x+120\)

\(=\left(x-5\right)\left(x^3-9x^2+26x-24\right)\)

\(=\left(x-5\right)\left(x^3-4x^2-5x^2+20x+6x-24\right)\)

\(=\left(x-5\right)\left(x-4\right)\left(x^2-5x+6\right)\)

\(=\left(x-5\right)\left(x-4\right)\left(x-3\right)\left(x-2\right)\)

\(\dfrac{x+27}{343}+\dfrac{x+28}{342}=\dfrac{x+121}{249}+\dfrac{x+120}{250}\)

\(\Rightarrow\left(\dfrac{x+27}{343}+1\right)+\left(\dfrac{x+28}{342}+1\right)=\left(\dfrac{x+121}{249}+1\right)+\left(\dfrac{x+120}{250}+1\right)\)

\(\Rightarrow\dfrac{x+370}{343}+\dfrac{x+370}{342}-\dfrac{x+370}{249}-\dfrac{x+370}{250}=0\)

\(\Rightarrow\left(x+370\right)\left(\dfrac{1}{343}+\dfrac{1}{342}-\dfrac{1}{249}-\dfrac{1}{250}\right)=0\)

Mà \(\dfrac{1}{343}+\dfrac{1}{342}-\dfrac{1}{249}-\dfrac{1}{250}\ne0\)

\(\Rightarrow x+370=0\Rightarrow x=-370\)

Vậy x = -370

\(\dfrac{x+27}{343}+\dfrac{x+28}{342}=\dfrac{x+121}{249}+\dfrac{x+120}{250}\)

\(\Rightarrow\dfrac{x+27}{343}+\dfrac{x+28}{342}-\dfrac{x+121}{249}-\dfrac{x+120}{250}=0\)

\(\Rightarrow\left(\dfrac{x+27}{343}+1\right)+\left(\dfrac{x+28}{342}+1\right)-\left(\dfrac{x+121}{249}+1\right)-\left(\dfrac{x+120}{250}+1\right)=0\)

\(\Rightarrow\dfrac{x+370}{343}+\dfrac{x+370}{342}-\dfrac{x+370}{249}-\dfrac{x+370}{250}=0\)

\(\Rightarrow\left(x+370\right)\left(\dfrac{1}{343}+\dfrac{1}{342}-\dfrac{1}{249}-\dfrac{1}{250}\right)=0\)

\(\Rightarrow x+370=0\Rightarrow x=-370\)

=2x2/1x3 x 3x3/2x4x4/3x5 x ... x 11x11/10x12

=2x2x3x3x4x4x...x11x11/1x3x2x4x3x5x...x10x12

= 2x3x4x...x11)x(2x3x4x...x11)/(1x2x3x4x...x11)/(1x2x3x...x10)x(2x3x4x...x11)

=11x2/1x12

=22/12

=11/6

4/3x9/8x16/15x...x121/120=\(\dfrac{2^2}{1\cdot3}\)x\(\dfrac{3^2}{2\cdot4}\)x\(\dfrac{4^2}{3\cdot5}\)x...x\(\dfrac{11^2}{10\cdot12}\)=\(\dfrac{2}{3}\)x\(\dfrac{11}{10}\)=\(\dfrac{11}{15}\)

4/3x9/8x16/15x...x121/120=\(\dfrac{2^2}{1\cdot3}\)x\(\dfrac{3^2}{2\cdot4}\)x...x\(\dfrac{11^2}{10\cdot12}\)=\(\dfrac{2}{3}\)x\(\dfrac{11}{10}\)=\(\dfrac{11}{15}\)

\(x\in z=\left\{\left(-120\right)\right\}\)

B=1x3/2x2x2x4/3x3x3x5/4x4x...x10x12/11x11

B=1x3x2x4x3x5x...x10x12/2x2x3x3x4x4x...x11x11

B=(1x2x3x...x10)x(2x3x5x...x12)/(2x3x4x...x11)x(2x3x4x...x11)

B=1x12/11x2

B=12/22

B=6/11

Vậy B = 6/11

\(120+x=300\)

               \(x=300-120\)

               \(X=180\)

Vậy \(x=180\)

chúc bn học gioi!@@

x = 300 - 120

x = 180

120 + x = 300 

         x = 300 - 120 

         x = 180

\(120+x=300\)

              \(x=300-120\)

               \(x=180\)

X = 180 

tích  nha

120+X=300

        X=300-120

        X=180

k mik nha mik k nha ^_^