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cô gái của quá khứ
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Trần Công Cường
2 tháng 9 2018 lúc 20:13

(x + 2) / 327 + (x + 3) / 326 + (x + 4) / 325 + (x + 5) / 324 + (x + 349) / 5 = 0  
<=> (x + 2) / 327 +1+ (x + 3) / 326 +1+ (x + 4) / 325 +1+ (x + 5) / 324 +1+ (x + 349) / 5 -4 = 0  
<=> (x+ 329)/327 + (x+ 329)/326 + (x+ 329)/325 + (x+ 329)//324 + (x+ 329)/5 =0  
<=> (x+ 329).(1/327 + 1/ 326 + 1/325 + 1/324 +1/5) =0  
Do (1/327 + 1/ 326 + 1/325 + 1/324 +1/5) >0 nên x+ 329 =0 => x= -329 

Nobi Nobita
24 tháng 6 2020 lúc 16:42

\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

\(\Leftrightarrow\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\left(\frac{x+349}{5}-4\right)=0\)

\(\Leftrightarrow\frac{x+2+327}{327}+\frac{x+3+326}{326}+\frac{x+4+325}{325}+\frac{x+5+324}{324}+\frac{x+349-20}{5}=0\)

\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

Vì \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}>0\)

\(\Rightarrow x+329=0\)\(\Leftrightarrow x=-329\)

Vậy \(x=-329\)

Khách vãng lai đã xóa
⋆~ஐTốηɢ Tử Nɢôη♀~
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Huỳnh Quang Sang
30 tháng 6 2019 lúc 20:48

\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

\(\Leftrightarrow\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4=0\)

\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

\(\Leftrightarrow\left[x+329\right]\cdot\left[\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right]=0\)

\(\Leftrightarrow x+329=0\) vì \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}>0\)

\(\Leftrightarrow x=-329\)

Vậy x = -329

Trả lời:

\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

\(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}-4=0\)

\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

\(\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

\(\Leftrightarrow x+329=0\Leftrightarrow x=-329\)

Vậy \(x=-329\)

     ~ Học tốt ~

#𝒌𝒂𝒎𝒊ㅤ♪
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I don
16 tháng 11 2018 lúc 14:56

\(\frac{x+2}{327}\) +\(\frac{x+3}{326}\) +\(\frac{x+4}{325\ }+\frac{x+5}{324}+\frac{x+349}{5}=0\)

=> \(\left(\frac{x+2\ }{327}+1\right)+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}\)+1+(\(\frac{x+349}{5}\) - 4) = 0

\(\frac{x+329}{327}\) + \(\frac{x+329}{326}+\frac{x+329}{325}\) + \(\frac{x+329}{324}\) +\(\frac{x+329\ }{5\ }\) = 0

(x+329).(1/327+1/326+1/325+1/324+1/5) = 0

=> x + 329 = 0

x = -329

có mấy chỗ mk quên đóng ngoặc bn sửa giúp mk nak

Đỗ Minh Quang
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Devil
24 tháng 2 2016 lúc 20:30

ta có:\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

\(\left(1+\frac{x+2}{327}\right)+\left(1+\frac{x+3}{326}\right)+\left(1+\frac{x+4}{327}\right)+\left(1+\frac{x+5}{324}\right)+\left(\frac{x+349}{5}-4\right)=0\)

\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

\(\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

\(\left(x+329\right)=0\left(vì\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)>0\right)\)

\(x+329=0\Rightarrow x=-329\)

Công chúa ori
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Alexander Sky Sơn Tùng M...
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OoO Kún Chảnh OoO
29 tháng 12 2015 lúc 13:25

(x + 2) / 327 + (x + 3) / 326 + (x + 4) / 325 + (x + 5) / 324 + (x + 349) / 5 = 0 
<=> (x + 2) / 327 +1+ (x + 3) / 326 +1+ (x + 4) / 325 +1+ (x + 5) / 324 +1+ (x + 349) / 5 -4= 0 
<=> (x+ 329)/327 + (x+ 329)/326 + (x+ 329)/325 + (x+ 329)//324 + (x+ 329)/5 =0 
<=> (x+ 329).(1/327 + 1/ 326 + 1/325 + 1/324 +1/5) =0 
Do (1/327 + 1/ 326 + 1/325 + 1/324 +1/5) # 0 nên x+ 329 =0 => x= -329 

Alexander Sky Sơn Tùng M...
4 tháng 1 2016 lúc 12:37

http://olm.vn/thanhvien/letrunghieuxiteen cám ơn nhiều nha

Nguyễn Đăng Hoàng
12 tháng 12 2017 lúc 12:25

dấu # nghĩa là j

Read Madridsta
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angela
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Trần Thị Hà Giang
21 tháng 3 2018 lúc 7:19

\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}\)\(+\frac{x+349}{5}=0\)

=>  \(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)\)\(+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)\)\(+\left(\frac{x+349}{5}-4\right)=0\)

=>   \(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}\)\(+\frac{x+329}{324}+\frac{x+329}{5}=0\)

=> \(\left(x+329\right)\)\(\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)\)\(=0\)

=>  \(x+329=0\)\(\left(do\frac{1}{327}+...+\frac{1}{324}+\frac{1}{5}\ne0\right)\)

=> \(x=-329\)

Vậy x = -329

hotboy
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Đức Lương Nguyễn
15 tháng 2 2016 lúc 16:33

Ta có: \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)

\(\Leftrightarrow\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)+\left(\frac{x+349}{5}-4\right)=0\)

\(\Leftrightarrow\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+\frac{x+329}{5}=0\)

\(\Leftrightarrow\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}\right)=0\)

\(\Leftrightarrow x+329=0\)        vì   \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+\frac{1}{5}>0\)

\(\Leftrightarrow x=-329\)

Nguyễn Ngọc Mai
15 tháng 2 2016 lúc 19:17

có ai biết làm câu  này không:

              |x+1/2|-|x-2|-|5-x|=x+3