We might go to the Moon for our summer holiday in 2030.

We might go to the Moon for their summer holiday in 2030.

We might go to the Moon for our summer holiday in 2030.

=2000 x 2010 x 2020 x 2030 x 2040/2010 x 2020 x 2030 x 2040 x 2050

=2000/2050 = 40/41

Tí cậu gạch 2010;2020;2030;2040;2050 cả trên cả dưới nhé. Tớ ko biết ấn vào đâu để gạch

2000/2010 x 2010/2000 x 2020/2030 x 2030/2040 x 2040/50

=1/1 x 1/1 x 202/203

=202/203

=2010

=2010

=2010

=12030

k mình nha!!

12030

10000+2030=12030

\(=\dfrac{98\cdot76\left(101-101\right)}{2021\cdot2022\cdot...\cdot2030}=0\)

\(\text{(98.7676-9898.76): (2021.2022.2023...2030)}\)

= \(\text{(752 248 - 752 248): (2021.2022.2023...2030)}\)

= \(\text{0 : (2021.2022.2023...2030)}\)

= \(0\)

 \(B=\)\(\left(98.7676-9898.76\right):\left(2021.2022.2023....2030\right)\)

\(=(98.101.76-9898.76):\left(2021.2022.2023....2030\right)\)

\(=\left(9898.76-9898.76\right):\left(2021.2022.2023...2030\right)\)

\(=0:\left(2021.2022.2023....2030\right)\)

\(=0\)

x^2016> 2030

=> Ta có x khác 0; khác 1 và khác -1

=> Với mọi x khác ba số trên thì đều hợp lệ

( 98 . 7676 - 9898 . 76 ) : ( 2021. 2022 . 2023 ... 2030 )

= ( 98 . 76 . 101 - 98 . 101 . 76 ) : ( 2021 . 2022 . 2023 ... 2030 )

= 0 : ( 2021 . 2022 . 2023... 2030 )

= 0.

Yêu cầu?

2030

\(A=\left(x+y\right)^2+\left(y-3\right)^2+2021\ge2021\\ A_{min}=2021\Leftrightarrow\left\{{}\begin{matrix}x=-3\\y=3\end{matrix}\right.\)