Bài 1: 

a) 0²⁰⁰² < 0²⁰²³

b) 2022⁰ = 2023⁰

c) 54⁹ < 55¹⁰

d) ( 4 + 5 )³ > 4² + 5²

đ) 9² - 3² > ( 9 - 3 )²

Bài 2:

a) 3² x 4³ - 3² + 333

= 9 x 64 - 9 + 333

= 576 - 9 + 333

= 567 + 333

= 900

b) 5 x 4³ + 24 x 5 + 41⁰

= 5 x 64 + 24 x 5 + 1

= 5 x ( 64 + 24 ) + 1

= 5 x 88 + 1

= 440 + 1

= 441

c) 2³ x 4² + 3² x 5 - 40 x 1²⁰²³

= 8 x 16 + 9 x 5 - 40 x 1

= 128 + 45 - 40

= 133

Bài 1 :

a) \(0^{2002}=0;0^{2023}=0\Rightarrow0^{2002}=0^{2023}\)

b) \(2022^0=1;2023^0=1\Rightarrow2022^0=2023^0\)

c) \(54^9< 55^9;55^9< 55^{10}\Rightarrow54^9< 55^{10}\)

d) \(\left(4+5\right)^3>\left(4+5\right)^2;\left(4+5\right)^2>4^2+5^2\Rightarrow\left(4+5\right)^3>4^2+5^2\)

đ) \(9^2-3^2=81-9=82;\left(9-3\right)^2=6^2=36\Rightarrow9^2-3^2>\left(9-3\right)^2\)

Bài 2 :

a) \(3^2.4^3-3^2+333=3^2\left(4^3-1\right)+9.37=9.63+9.37=9\left(63+37\right)=9.100=900\)

b) \(5.4^3+24.5+41^0=20.4^2+20.6+1=20\left(16+6\right)+1=20.22+1=441\)

c) \(2^3.4^2+3^2.5-40.1^{2023}=8.16+9.5-40.1=128+45-40=128+5=133\)

\(\left[400-\left(40:2^3+3.5^3\right)\right]:5\)

\(=\left[400-\left(40:8+3.125\right)\right]:5\)

\(=\left[400-\left(5+375\right)\right]:5\)

\(=\left[400-380\right]:5=20:5=4\)

4/19

4/19

\(4^3:8\cdot3^2-5^2+9\)

\(=8\cdot9-25+9\)

=81-25

=56

45^10*5^20/75^15

=5^10*9^10*5^20/(5^2)^15

=5^10*5^20*9^10/5^30

=9^10

(0.8)^5/(0.4)^6

=(0.4)^5*2^5/(0.4)^6

=2^5/(0.4)

=32/(0.4)

=80

2^15*9^4/6^6*8^3

=2^15*(3^2)^4/2^6*3^6*(2^3)^3

=2^15*3^8/2^6*3^6*2^9

=3^2

=9

\(-22x^3-\left(-21x^3+19x^2+23^0\right)-\left(-x^3-18x^2\right)+\left(x^2-23^1\right)\)

\(=-22x^3+21x^3-19x^2-1+x^3+18x^2+x^2-23\)

\(=\left(-22x^3+21x^3+x^3\right)+\left(-19x^2+18x^2+x^2\right)+\left(-1-23\right)\)

\(=0x^3+0x^2-24\)

\(=-24\)

Vậy biểu thức trên có giá trị không phụ thuộc vào biến.

a) \(2^3.3^2=8.9=72\)

b) \(5^{10}:5^7=5^2=25\)

c) \(2^6:2=2^5=32\)

d) \(7^4:7^4=7^0=1\)

e) \(9^5:9^5=9^0=1\)

a) 23.32=8.9=7223.32=8.9=72

b) 510:57=52=25510:57=52=25

c) 5

32

d) $1$

e) $1$