2^3 (x-3^2)=5^3-4^3
help me!
10^3+5*10^2+5^2/6^3+3*6^2+3^3
help me!!!
\(\dfrac{10^3+5\cdot10^2+5^2}{6^3+3\cdot6^2+3^3}=\dfrac{5^3\cdot2^3+5\cdot2^2\cdot5^2+5^2}{2^3\cdot3^3+3\cdot2^2\cdot3^2+3^3}\\ =\dfrac{5^3\left(2^3+2^2+1\right)}{3^3\left(2^3+2^2+1\right)}=\dfrac{5^3}{3^3}=\dfrac{125}{27}\)
b) 4(x – 3) = 3
help me pls
b, 4 ( x - 3 ) = 3
x - 3 = \(\dfrac{3}{4}\) = 0,75
x = 0,75 + 3 = 3,75
x/3=7/25+ -1/5
4/9 + x/5 =5/11
-5/9 + x/10=1/3
help
x/3=7/15+-1/5
x/3=2/15
5x/15=2/15
5x=2
x=2/5
x= 2/5
CHÚC BẠN HỌC TỐT
Chứng minh rằng nếu a^2+b^2 chia hết cho 3 thì a và b đều chia hết cho 3
Help với mn
Ta có :
\(a^2+b^2⋮3\)
=> \(a.a+b.b⋮3\)
=> \(a+b⋮3\)
=> \(a,b⋮3\)
TÌM X, BIẾT:
a) 3 . ( 1/2 - x ) + 1/3 = 7/6 - x
b) 4 . ( 1/2 - x ) - 5 . ( x - 3/10 ) = 7/4
c) -3/2 . ( 4/5 - 2/3 ) + x = 4 . ( x - 1/2 )
d) 2 . ( 3/2 - x ) - 1/3 = 7x - 1/4
e) 1/5 . ( -3/5 -10 ) + 5x = x - 2/3
f) -3/2 . ( 5 - 1/6 ) + 4 . ( x - 1/2 ) = 1
~ PLEASE HELP ME ~
Nguyễn Trà My
Phần a)
\(3\times\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
\(32-3x+13=76-x\)
\(116-3x=76-x\)
\(116-76=3x-x\)
\(46=2x\)
\(x=46\div2\)
\(x=13\)
a) \(3.\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
\(3.\left(\frac{1}{2}-x\right)+x=\frac{7}{6}-\frac{1}{3}\)
\(\Rightarrow\frac{3}{2}-3x+x=\frac{5}{6}\)
\(-3x+x=\frac{5}{6}-\frac{3}{2}\)
\(2x=-\frac{2}{3}\)
\(x=-\frac{2}{3}:2\)
\(x=-\frac{1}{3}\)
tìm x :a)(2x-3/4)^2=(3-x)^2
b)(5/3x-1/3)^5=(2x+3/4)^3
HELP ME !!!!!!!!!!!!!!!!!!!
\(\left(2x-\dfrac{3}{4}\right)^2=\left(3-x\right)^2\)
\(\Rightarrow2x-\dfrac{3}{4}=3-x\)
\(3x=3\dfrac{3}{4}\)
\(x=\dfrac{5}{4}\)
giai pt x^2/3+48/x^2=5.(x/3+4/x)
help me ! thanks
\(\dfrac{2x^3+5}{x^2-x+1}-\dfrac{x^3+4}{x^2-x+1}\)help me :(
= \(\dfrac{2x^3+5-x^3-4}{x^2-x+1}\) = \(\dfrac{x^3-1}{x^2-x+1}\)
\(\dfrac{2x^3+5 -x^3-4}{x^2-x+1}=\dfrac{x^3+1 }{x+1}\)
câu này luôn \(\dfrac{2x^2y^5}{xy^2z}-\dfrac{4x^2y^3}{xy^2z}\)
help me
-4/7-x=3/5-2x
3/7.x-2/3.x=10/21
\(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\\ \Rightarrow-x+2x=\dfrac{3}{5}+\dfrac{4}{7}\\ \Rightarrow x=\dfrac{21}{35}+\dfrac{20}{35}\\ \Rightarrow x=\dfrac{41}{35}\)
Vậy `x=41/35`
__
\(\dfrac{3}{7}x-\dfrac{2}{3}x=\dfrac{10}{21}\\ \Rightarrow\left(\dfrac{3}{7}-\dfrac{2}{3}\right)x=\dfrac{10}{21}\\ \Rightarrow\left(\dfrac{9}{21}-\dfrac{14}{21}\right)x=\dfrac{10}{21}\\ \Rightarrow\dfrac{-5}{21}x=\dfrac{10}{21}\\ \Rightarrow x=\dfrac{10}{21}:\left(-\dfrac{5}{21}\right)\\ \Rightarrow x=-2\)
Vậy `x=-2`
a)
-4/7 - x = 3/5 - 2x
2x - x = 3/5 + 4/7
x = 41/35
Vậy x = 41/35
b)
3/7.x - 2/3.x = 10/21
x(3/7 - 2/3) = 10/21
x.(-5/21) = 10/21
x = 10/21 : (-5/21) = -2
Vậy x = -2
TÌM X, BIẾT:
a) 3 . ( 1/2 - x ) + 1/3 = 7/6 - x
b) 4 . ( 1/2 - x ) - 5 . ( x - 3/10 ) = 7/4
c) -3/2 . ( 4/5 - 2/3 ) + x = 4 . ( x - 1/2 )
d) 2 . ( 3/2 - x ) - 1/3 = 7x - 1/4
e) 1/5 . ( -3/5 -10 ) + 5x = x - 2/3
f) -3/2 . ( 5 - 1/6 ) + 4 . ( x - 1/2 ) = 1
~ PLEASE HELP ME ~
HOC24 có câu rất hay :Người hay giúp bạn khác trả lời bài tập sẽ trở thành học sinh giỏi. Người hay hỏi bài thì không. Còn bạn thì sao? đúng tính bà đó . Lên lớp đừng đập nha :)
a) 3 . ( 1/2 - x ) + 1/3 = 7/6 - x
=> 3/2 - 3x + 1/3 = 7/6-x
=> -3x +x=7/6 - 3/2 - 1/3
=> -2x = -2/3
=> x=-2/3 : (-2) = 1/3
hết :)