41/10

69/14

5/1 - 3/8 x 12/5 = 5/1 - 9/10 = 41/10

6/1 - 5/12 x 18/7 = 6/1 - 15/14 = 69/14

41/10

A

A

A

1:

a: \(=\dfrac{-4}{7}+\dfrac{4}{7}+\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=-\dfrac{1247}{1190}\)

b:

Sửa đề: \(\dfrac{-5}{13}+\dfrac{4}{19}+\dfrac{-8}{13}+\dfrac{15}{19}+\dfrac{45}{6}\) 

\(=\dfrac{-5}{13}-\dfrac{8}{13}+\dfrac{4}{19}+\dfrac{15}{19}+\dfrac{45}{6}=\dfrac{9}{2}\)

\(15-2.x=25\)

        \(2.x=15-25=-10\)

           \(x=\left(-10\right)\div2=-5\)

\(31-\left(17+x\right)=18\)

        \(\left(17+x\right)=31-18=13\)

                  \(x\)  \(=13-17=-4\)

15−2.x=2515−2.x=25

        2.x=15−25=−102.x=15−25=−10

           x=(−10)÷2=−5x=(−10)÷2=−5

31−(17+x)=1831−(17+x)=18

        (17+x)=31−18=13(17+x)=31−18=13

                  xx  =13−17=−4

\(a)x\times\dfrac{4}{7}=8\)                        \(b)\dfrac{1}{6}:x=\dfrac{5}{18}\)

\(x=8:\dfrac{4}{7}\)                                \(x=\dfrac{1}{6}:\dfrac{5}{18}\)

\(x=\dfrac{56}{4}=14\)                            \(x=\dfrac{18}{30}=\dfrac{3}{5}\)

a) x = 8 : 4/7

x = 14

b) x = 1/6 : 5/18

x = 3/5

3/5

a) \(0,6+\dfrac{2}{3}=\dfrac{6}{10}+\dfrac{2}{3}=\dfrac{3}{5}+\dfrac{2}{3}=\dfrac{9}{15}+\dfrac{10}{15}=\dfrac{19}{15}\)

b) \(-\dfrac{5}{12}+0,75=-\dfrac{5}{12}+\dfrac{75}{100}=-\dfrac{5}{12}+\dfrac{3}{4}=-\dfrac{5}{12}+\dfrac{9}{12}=\dfrac{4}{12}=\dfrac{1}{3}\)

c) \(\dfrac{1}{3}-\left(-0,4\right)=\dfrac{1}{3}+\dfrac{4}{10}=\dfrac{1}{3}+\dfrac{2}{5}=\dfrac{5}{15}+\dfrac{6}{15}=\dfrac{11}{15}\)

d) \(1\dfrac{3}{5}+\dfrac{5}{6}=\dfrac{8}{5}+\dfrac{5}{6}=\dfrac{48}{40}+\dfrac{25}{30}=\dfrac{73}{30}\)

bài 1: 

\(2\dfrac{3}{4}:1\dfrac{1}{3}=\dfrac{11}{4}:\dfrac{4}{3}=\dfrac{33}{16}\)

ta có:

a - b = 18

=> 2a - 2b = 36

mà 2a = 5b

=> 5b - 2b = 36

=> 3b = 36

=> b = 12

Ta có:

a - b = 18

=> a - 12 = 18

=> a = 30

Vậy a = 30, b = 12

ta có:

a - b = 18

=> 2a - 2b = 36

mà 2a = 5b

=> 5b - 2b = 36

=> 3b = 36

=> b = 12

Ta có:

a - b = 18

=> a - 12 = 18

=> a = 30

Vậy a = 30, b = 12

Ta có: 2a=5b

nên \(\dfrac{a}{5}=\dfrac{b}{2}\)

mà a-b=18

nên Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:

\(\dfrac{a}{5}=\dfrac{b}{2}=\dfrac{a-b}{5-2}=\dfrac{18}{3}=6\)

Do đó: a=30; b=12

A, \(2\frac{2}{5}\left(\frac{1}{2}x-0,75\right)=\frac{3}{10}\)

\(=>\frac{2.5+2}{5}\left(\frac{1}{2}x-\frac{3}{4}\right)=\frac{3}{10}\)

\(=>\frac{1}{2}x-\frac{3}{4}=\frac{3}{10}:\frac{12}{5}=\frac{1}{8}\)

\(=>x=\left(\frac{1}{8}+\frac{3}{4}\right):\frac{1}{2}\)

\(=>x=\frac{7}{4}\)

B, \(\frac{3}{5}-|x-\frac{1}{2}|=25\%\)

\(=>|x-\frac{1}{2}|=\frac{3}{5}-\frac{1}{4}\)

\(=>|x-\frac{1}{2}|=\frac{7}{20}\)

\(=>x-\frac{1}{2}=\frac{7}{20};-\frac{7}{20}\)

TH1: \(x-\frac{1}{2}=\frac{7}{20}=>x=\frac{17}{20}\)

TH2: \(x-\frac{1}{2}=-\frac{7}{20}=>x=\frac{3}{20}\)