1+1/3x4+1/4x5+1/5x6
tính nhanh
1/2x3 + 1/3x4 + 1/4x5 + 1/5x6 + 1/6x7
1/2x3 + 1/3x4 + 1/4x5 + 1/5x6 + 1/6x7 + 1/20x21
\(=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{6}-\dfrac{1}{7}=\dfrac{1}{2}-\dfrac{1}{7}=\dfrac{5}{14}\)
\(=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{20}-\dfrac{1}{21}=\dfrac{21-2}{42}=\dfrac{19}{42}\)
Lời giải:
Gọi biểu thức số 1 là A và số 2 là B
\(A=\frac{3-2}{2\times 3}+\frac{4-3}{3\times 4}+\frac{5-4}{4\times 5}+\frac{6-5}{5\times 6}+\frac{7-6}{6\times 7}\)
\(=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)
\(=\frac{1}{2}-\frac{1}{7}=\frac{5}{14}\)
B tương tự A:
\(B=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+....+\frac{1}{20}-\frac{1}{21}\)
\(=\frac{1}{2}-\frac{1}{21}=\frac{19}{42}\)
1/3x4+1/4x5+1/5x6+...+1/11x12=x?
Bài nào khó lắm thì mới hỏi thôi chứ bài này dễ mà bạn tự vận động não đi
\(\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+...+\dfrac{1}{11\cdot12}=x\)
\(\Leftrightarrow x=\dfrac{1}{3}-\dfrac{1}{12}=\dfrac{4}{12}-\dfrac{1}{12}=\dfrac{1}{4}\)
dễ lắm ko cần hỏi đâu ,tự vận động não đi
Tính nhanh:
1+1/3x4+1/4x5+1/5x6
=1+1/3-1/4+1/4-1/5+1/5-1/6
=1+1/3-1/6
=1+1/6=7/6
1/1x2 + 1/2x3 +1/3x4 +1/4x5 +1/5x6
1/1x2 + 1/2x3 + 1/3x4 +1/4x5 +1/5x6
= 1 -1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6
= 1 - 1/6 = 5/6
1/3x4 + 1/4x5 + 1/5x6 + ...........+ 1/11x12
=\(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....+\frac{1}{11}-\frac{1}{12}\)
=\(\frac{1}{3}-\frac{1}{12}\)
=\(\frac{3}{12}=\frac{1}{4}\)
\(\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+...+\frac{1}{11\times12}\) =\(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{11}-\frac{1}{12}\) =\(\frac{1}{3}-\frac{1}{12}\) =\(\frac{1}{4}\)
1\2x3+1\3x4+1\4x5+1\5x6
Ta có : 1/2.3+1/3.4+1/4.5+1/5.6
=1/2-1/3+1/3-1/4+….+1/5-1/6
=1/2-1/6
=2/6=1/3
\(\frac{1}{2x3}\) + \(\frac{1}{3x4}\) + \(\frac{1}{4x5}\) + \(\frac{1}{5x6}\)
=\(\frac{1}{2}\) -\(\frac{1}{3}\) +\(\frac{1}{3}\) -\(\frac{1}{4}\) +\(\frac{1}{4}\) -\(\frac{1}{5}\) +\(\frac{1}{5}\) -\(\frac{1}{6}\)
=\(\frac{1}{2}\)-\(\frac{1}{6}\) =\(\frac{1}{3}\)
k cho mình nha
1/3x4 + 1/4x5 + 1/5x6 + ... + 1/20x21 = x/14
\(\dfrac{1}{3\times4}+\dfrac{1}{4\times5}+\dfrac{1}{5\times6}+...+\dfrac{1}{20\times21}=\dfrac{x}{14}\)
\(\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{20}-\dfrac{1}{21}=\dfrac{x}{14}\)
\(\dfrac{1}{3}-\dfrac{1}{21}=\dfrac{x}{14}\)
\(\dfrac{7}{21}-\dfrac{1}{21}=\dfrac{x}{14}\)
\(\dfrac{6}{21}=\dfrac{x}{14}\)
\(\Rightarrow x.21=6.14\)
\(x.21=84\)
\(x=84:21\)
\(x=4\)
Vậy x = 4
1/3x4 + 1/4x5 + 1/5x6 + .. + 1/20x21 = x/14
1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + .. + 1/20 - 1/21 = x/14
1/3 - 1/21 = x/14
7/21 - 1/21 = x/14
6/21 = x/14
x . 21 = 6 x 14
x x 21 = 84
x = 84 : 21
x = 4
1/(3×4) + 1/(4×5) + 1/(5×6) + ... + 1/(20×21) = x/14
1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + ... + 1/20 - 1/21 = x/14
1/3 - 1/21 = x/14
2/7 = x/14
x = 14 × 2/7
x = 4
1/3x4 + 1/4x5 + 1/5x6 + .........+ 1/11x12 =
Cách làm : =4/3*5/4*6/5*7/6*8/7*9/8*10/9*11/10*12/11=Ta làm cách số trên và số dưới đều có thì gạch nhé thì ta sẽ còn , hàng trên là 12 , hàng dưới là 3 ta sẽ =12/3=4 nha bạn
1/3x4 + 1/4x5 + 1/5x6 + ... + 1/2009+2010
1/3x4 + 1/4x5 + 1/5x6 + ... + 1/2009x2010
= 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + ... + 1/2009 - 1/2010
= 1/3 - 1/2010
= 223/670
\(\frac{1}{3\times4}+\frac{1}{4\times5}+\frac{1}{5\times6}+...+\frac{1}{2009\times2010}\)
\(=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{2009}-\frac{1}{2010}\)
\(=\frac{1}{3}-\frac{1}{2010}\)
\(=\frac{670}{2010}-\frac{1}{2010}\)
\(=\frac{669}{2010}\)
\(=\frac{223}{670}\)
Hình như bạn viết sai đề bài! Ko phải là 1/2009+2010 mà phải là 1/2009x2010 mới đúng đó!