(x+1/5)^2 + 17/5 = 26/25
(x + 1/5)^2 + 17/25=26/25
(x+1/5)^2+17/25=26/25
(x+1/5)^2=26/25-17/25=9/25
x+1/5=\(\sqrt{\dfrac{9}{25}}\)
=3/5 =>x=3/5-1/5=2/5
\(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)
\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)
\(\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)
\(\left(x+\dfrac{1}{5}\right)^2=\dfrac{26}{25}+\dfrac{17}{25}\\ \left(x+\dfrac{1}{5}\right)^2=\dfrac{43}{25}\\ x+\dfrac{1}{5}=\dfrac{\sqrt{45}}{5}\\ x=\dfrac{\sqrt{45}}{5}-\dfrac{1}{5}\\ x=\dfrac{-1+\sqrt{43}}{5}\)
28) (x+1/5)2 + 17/25=26/25
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\Rightarrow\left(x+\frac{1}{5}\right)^2=\frac{9}{25}=\frac{3}{5}^2\)
\(\Rightarrow x^2=\frac{3}{5}^2-\frac{1}{5}^2=\frac{2}{5}^2\)
\(\Rightarrow x=\frac{2}{5}\)
Mk nhanh nhất k mk nka!!!^_^^_^^_^
(x+1/5)2 + 17/25=26/25
x+2/ 327+ x+3/326+x+4/325+x+5/324+x+349/5=0
(x+1/5)^2 =26/25-17/25
<=> (x +1/5)^2 =(3/5)^2
<=> x+1/5=3/5
=> x= 2/5
a)
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\left(\frac{3}{5}\right)^2\)
\(x+\frac{1}{5}=\frac{3}{5}\)
\(x=\frac{3}{5}-\frac{1}{5}\)
\(x=\frac{2}{5}\)
b)
\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+349}{5}=0\)
\(\frac{x+2}{327}+1+\frac{x+3}{326}+1+\frac{x+4}{325}+1+\frac{x+5}{324}+1+\frac{x+349}{5}=0\)
\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}+4+\frac{x+329}{5}=0\)
\(\left(x+329\right).
\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}+4+\frac{1}{5}\right)=0\)
\(\Rightarrow\left(x+329\right)=0\)
\(\Rightarrow x=-329\)
(x+1/5)2+17/25=26/25
28) (x+1/5)2 + 17/25=26/25
35) x+2/ 327+ x+3/326+x+4/325+x+5/324+x+349/5=0
1.
(x + 1/5)² = 26/25 - 17/25
(x + 1/5)² = 9/25
Rút căn hai vế :
|(x + 1/5)| = 3/5
x = -4/5
hoặc
x = 2/5
2.
(x + 2) / 327 + (x + 3) / 326 + (x + 4) / 325 + (x + 5) / 324 + (x + 349) / 5 = 0
<=> (x + 2) / 327 +1+ (x + 3) / 326 +1+ (x + 4) / 325 +1+ (x + 5) / 324 +1+ (x + 349) / 5 -4 = 0
<=> (x+ 329)/327 + (x+ 329)/326 + (x+ 329)/325 + (x+ 329)//324 + (x+ 329)/5 =0
<=> (x+ 329).(1/327 + 1/ 326 + 1/325 + 1/324 +1/5) =0
Do (1/327 + 1/ 326 + 1/325 + 1/324 +1/5) >0 nên x+ 329 =0 => x= -329
Câu 1 chưa chắc đã đúng ( quên hết kiến thức lớp 6 rùi ) hihi
aaaaaaaa . chết rồi . cho mình sủa câu thứ nhất :
(x+1/5)2 + 17/25=26/25
( x + 1/5 ) 2 = 26/25 - 17/25
( x + 1/5 ) 2 = 3/52
x + 1/5 = 3/5
x = 2/5.
tìm x
(x+1/5)^2+17/35=26/25
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}=\left(\frac{3}{5}\right)^2=\left(-\frac{3}{5}\right)^2\)
\(\Rightarrow x+\frac{1}{5}=\frac{3}{5}\) \(\Rightarrow x+\frac{1}{5}=-\frac{3}{5}\)
\(x=\frac{3}{5}-\frac{1}{5}\) \(x=-\frac{3}{5}-\frac{1}{5}\)
\(x=\frac{2}{5}\) \(x=\frac{-4}{5}\)
\(vậy...\)
(x+1/5)2 + 17/25 = 26/25
x = ????
\(\left(x+\frac{1}{5}\right)^2+\frac{17}{25}=\frac{26}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{26}{25}-\frac{17}{25}\)
\(\left(x+\frac{1}{5}\right)^2=\frac{9}{25}\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{1}{5}=\frac{3}{5}\\x+\frac{1}{5}=-\frac{3}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{2}{5}\\x=-\frac{4}{5}\end{cases}}}\)
\(\Rightarrow x\in\left\{-\frac{4}{5};\frac{2}{5}\right\}\)
(x+1/5)2 + 17/25= 26/25
(x+1/5)2 = 26/25- 17/25
(x+1/5)2 = 9/25
(x+1/5)2 = (3/5)2
=> x+1/5 = 3/5
x = 3/5-1/5
x = 2/5
Pls cho mk nha
(x+1/5)^2=26/25-17/25
(x+1/5)^2=9/25
x+1/5=3/25
x=3/25-1/5
x=-2/25