96 - 3x ( X + 1 ) = 42
96-3x(x+a)=42
96-3.(x+a)=42
3(x+a)=96-42
3(x+a)=54
x+a=54:3
x+a=18
(3x - 6 )+ 9 = 34.3
96 + 3 . (x -1 )=42
(3x - 6) + 9 = 34 . 3
(3x - 6) + 9 = 35
(3x - 6) + 9 = 243
3x - 6 = 243 - 9
3x - 6 = 234
3x = 234 + 6
3x = 240
x = 240 : 3
x = 80
Vậy x = 80.
96 + 3 . (x - 1) = 42
3 . (x - 1) = 42 - 96
3 . (x - 1) = -54
x - 1 = -54 : 3
x - 1 = -18
x = -18 + 1
x = -17
Vậy x = -17
a,x=80
~~~~~~~~~~~~
~~~~~~~~~~~
~~~~~~~~~~~~~~
a, (3x-6)+ 9 = \(3^5\)
(3x- 6)+ 9 = 243
3x - 6 = 243 -9
3x - 6 = 234
3x=234+6
3x=240
=> x=80
b,96 +3 . (x-1)=42
98. (x-1)=42
x-1=98-42
x-1=56
=> x=56+1=57
2.Tìm x, biết
a,3.x+7=25
b,(5.x+4)-1=23
c,96-3x(x+1)=42
d,2x=16
e,x2=16
a) 3.x+7=25
3.x = 25 -7
. 3.x = 18
x. = 18 :3
. x. 6
a. 3.x+7=25
<=> 3x = 18
<=> x = 6
b. (5.x+4)-1=23
<=> 5x + 4 = 24
<=> 5x = 20
<=> x = 4
c. 96-3(x+1)=42
<=> 3(x + 1) = 54
<=> x + 1 = 18
<=> x = 17
d. 2x=16
<=> 2x = 24
<=> x = 4
e. x2=16
<=> \(\orbr{\begin{cases}x^2=4^2\\x^2=\left(-4\right)^2\end{cases}}\)
<=> x = \(\pm\)4
a, 3x + 7 = 25
=> 3x = 25 - 7
=> 3x = 18
=> x = 18 : 3
=> x = 6
b, ( 5x + 4 ) - 1 = 23
=> 5x + 4 = 24
=> 5x = 24 - 4
=> 5x = 20
=> x = 20 : 5
=> x = 4
c, 96 - 3x ( x + 1 ) = 42
=> 3x ( x + 1 ) = 54
=> 4x + 3x = 54
=> 7x = 54
=> x = 54/7
d, 2x = 16
=> 2x = 24
=> x = 4
e, x2 = 16
=> x2 = 42
=> x = 4
tm x
a,(3x-17).4^5=4^6
b,3 |x-5|-23=(-2)^3
c,96-3 (x+1)=42
d,48:(2x+1)-7=5
e,4.(x+1)^3-5=3^3
a) ( 3x-17) . 45= 46
( 3x -17) = 46: 45
( 3x-17) = 4
3x = 4+17
3x= 21
x= 21:3
x=7
Vậy....
b) 3 |x-5|-23=(-2)3
3 |x-5| -23 = -8
3 |x-5| = -8+23
3 |x-5| = 15
| x -5| = 15:3
|x-5| = 5
TH1: x- 5= 5
x= 5+5
x= 10
TH2: x -5 = -5
x= -5+5
x= 0
Vậy...
c) 96-3 (x+1)=42
3 ( x+1) = 96-42
3(x+1) = 54
x+1 = 54:3
x+1 = 18
x= 18-1
x= 17
Vậy...
ai giải giúp mình với ạ
a) 4,57 x 42 + 5,43 x 42
b) 8,4 x 96 +1,6 x 96
`#3107.101107`
`a)`
`4,57 \times 42 + 5,43 \times 42`
`= 42 \times (4,57 + 5,43)`
`= 42 \times 10`
`= 420`
`b)`
`8,4 \times 96 + 1,6 \times 96`
`= 96 \times (8,4 + 1,6)`
`= 96 \times 10`
`= 960`
a) 4,57x42+5,43x42
= (4,57+5,43)x42
= 10x42
=420
b) 8,4x96+1,6x96
= (8,4+1,6)x96
= 10x96
= 960
96-3(x+1)=42
\(96-3\left(x+1\right)=42\)
\(=>3\left(x+1\right)=96-42\)
\(=>3\left(x+1\right)=54\)
\(=>x+1=54:3\)
\(=>x+1=18\)
\(=>x=18-1\)
\(=>x=17\)
\(96-3\left(x+1\right)=42\)
\(\Rightarrow3\left(x+1\right)=96-42\)
\(\Rightarrow3\left(x+1\right)=54\)
\(\Rightarrow x+1=54:3\)
\(\Rightarrow x+1=18\)
\(\Rightarrow x=18-1\)
\(\Rightarrow x=17\)
A)(-7)+14-(-7)+4.(-14)+12
B)(3x-6).3=3^4
C)96-3(x+1)=42
Ai giúp em bài này với em đang cần gấp lắm
a. (-7)+14-(-7)+4.(-14)+12
= (-7)+14+7+(-56)+12
= (-7+7)+14-56+12
= 0 + 14+12-56
= -30
b. (3x-6).3=34
=> 3x-6=34:3
=> 3x-6=33
=> 3x-6=27
=> 3x=27+6
=> 3x=33
=> x=33:3
Vậy x=11.
c. 96-3(x+1)=42
=> 3(x+1)=96-42
=> 3(x+1)=54
=> x+1=54:3
=> x+1=18
=> x=18-1
Vậy x=17.
96 - 3 ( x + 1) = 42. Tìm x
96 - 3(x+1)= 42
3(x+1) = 96 - 42 = 54
x + 1 = 54 : 3 = 18
x = 18 - 1 = 17
96-3.(x+1)=42
96-3.(x+1)=16
93 .(x+1)=16
(x+1)= 93-16
(x+1)=77
x = 77-1
x = 76
Tìm x biết
c)96 - 3.(x + 1) = 42
c)96 - 3.(x + 1) = 42
3.(x + 1)= 96 - 42
3.(x + 1) = 54
x + 1= 54:3
x + 1= 18
x = 18 - 1
x = 17