\(A=\dfrac{2^{19}\cdot3^9-3\cdot5\cdot2^{18}\cdot3^8}{2^9\cdot2^{10}\cdot3^9+2^{20}\cdot3^{10}}\)

\(=\dfrac{2^{19}\cdot3^9-2^{18}\cdot3^9\cdot5}{2^{19}\cdot3^9+2^{20}\cdot3^{10}}\)

\(=\dfrac{2^{18}\cdot3^9\left(2-5\right)}{2^{19}\cdot3^9\cdot7}=\dfrac{1}{2}\cdot\dfrac{-3}{7}=\dfrac{-3}{14}\)

 = 2^19 x (3^3)^3 + 3 x 5 x (2^2)^9 x (3^2)^4 / 2^9 x 3^9 x 2^10 + (2^2)^10 x 3^10

 = 2^19 x 3^9 + 3^9 x 2^18 x 5 / 2^19 x 3^9+2^20 x 3^10 

 = 3^9 x 2^18 x (2+5) / 3^9 x 2^19 x (1 + 2 x 3)

 = 3^9 x 2^18 x 7 / 3^9 x 2^19 x 7 = 1/2

k mk nha

Cảm ơn bạn đẹp trai 

\(1\frac{13}{15}\cdot3\cdot(0,5)^2\cdot3+\left[\frac{8}{15}-1\frac{19}{60}:1\frac{23}{24}\right]\)

\(=\frac{28}{15}\cdot3\cdot0,5\cdot0,5\cdot3+\left[\frac{8}{15}-\frac{79}{60}:\frac{47}{24}\right]\)

\(=\frac{28}{5}\cdot0,25\cdot3+\left[\frac{32}{60}-\frac{79}{60}\cdot\frac{24}{47}\right]\)

\(=\frac{28}{5}\cdot\frac{25}{100}\cdot3+\left[\frac{32}{60}-\frac{158}{235}\right]\)

\(=\frac{28}{5}\cdot\frac{1}{4}\cdot3+\frac{-98}{705}=\frac{7}{5}\cdot1\cdot3+\frac{-98}{705}\)

Đến đây là tính dễ rồi :v

\((-3,2)\cdot\frac{-15}{64}+\left[0,8-2\frac{4}{15}\right]:1\frac{23}{24}\)

\(=\frac{-32}{10}\cdot\frac{-15}{64}+\left[\frac{8}{10}-\frac{34}{15}\right]:\frac{47}{24}\)

\(=\frac{-32\cdot(-15)}{10\cdot64}+\left[\frac{4}{5}-\frac{34}{15}\right]:\frac{47}{24}\)

\(=\frac{-1\cdot(-3)}{2\cdot2}+\frac{4\cdot3-34}{15}:\frac{47}{24}\)

\(=\frac{3}{4}+\frac{-22}{15}:\frac{47}{24}\)

\(=\frac{3}{4}+\frac{-517}{180}=\frac{-191}{90}\)

Bài 2 : \(\frac{2\cdot(-13)\cdot9\cdot10}{(-3)\cdot4\cdot(-5)\cdot26}=\frac{1\cdot(-1)\cdot3\cdot2}{(-1)\cdot2\cdot(-1)\cdot2}=\frac{1\cdot3}{-1\cdot2}=\frac{3}{-2}=\frac{-3}{2}\)

\(\frac{15\cdot8+15\cdot4}{12\cdot3}=\frac{15\cdot(8+4)}{12\cdot3}=\frac{15\cdot12}{12\cdot3}=\frac{15}{3}=5\)

VIẾT ĐỀ BÀI RỒI = A

    A=B/C

B= 2¹⁹ . 27³ + 15 .4⁹ . 9⁴

B= 2¹⁹ . (3³)³ + 5.3 (2²)⁹ . (3²)⁴

B= 2¹⁹ . 3⁹ +5.3 .2¹⁸ . 3⁸

B=2

    K VÀ KẾT BẠN NHA

\(P=\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)

\(P=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)

\(P=\frac{2^{18}.3^9\left(2+5\right)}{2^{18}.3^9\left(2+2^2.3\right)}\)

\(P=\frac{7}{14}=\frac{1}{2}\)

a) \(2^5+8\left[\left(-2\right)^3:\frac{1}{2}\right]^0-\left(\frac{1}{2}\right)^3\times2+\left(-2\right)^3\)

\(=32+8\times1-\frac{1}{8}\times2+\left(-8\right)\)

\(=32+8-\frac{1}{4}+\left(-8\right)\)

\(=40-\frac{1}{4}+\left(-8\right)\)

\(=39\frac{3}{4}+\left(-8\right)\)

\(=31\frac{3}{4}\)

b vaf c mai minhf lamf, ht

Đáp án là 1/2

BẠn Thảo có thể viết cách làm ko ?