De ma de minh giai cho , ko can chi can nick 1 cai la douc roi :

(x+5)+(x-9)=x+2

x+5+x+9=x+2

2x+14=x+2

ko viet vao vo nhe : trong truong hop nay ta bo bot 2 ben moi ben 1 con x

x+14=2

x=2-14

Vay x=-12, x=am 12 nhe . Dau tru to viet hoi nho chut

Cac ban xem va an **** cho minh nhe . Cam on

khong biet lam

Xx4+(1/2+1/4+1/8+1/16)=23/16

Xx4=23/16-(1/2+1/4+1/8+1/16)

Xx4=1/2

X=1/2:4

X=1/8

1/8 nha bn

ako lop may mik lop 4 neu ban lop 4 thi ket ban nha

2:x=1

x=2x1

x=2

tick nha

tick nha minh  tra loi truoc ma

x = 2

Tick nha! Pham Dinh Khanh

\(\left(x^2+2\right)\left(x^2+2^5\right)\)

\(\Rightarrow\orbr{\begin{cases}x^2+2=0\\x^2+2^5=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x\in\varnothing\\x\in\varnothing\end{cases}}\)

vậy \(x\in\varnothing\)

\(\left[\frac{2}{3x}-\frac{2}{x+1}\left(\frac{x+1}{3x}-x-1\right)\right]:\frac{x-1}{x}=\frac{2x}{x-1}\)( Điều kiện \(x\ne0\))

VT = \(\left[\frac{2}{3x}-\frac{2}{x+1}\left(\frac{x+1}{3x}-x-1\right)\right]:\frac{x-1}{x}\)

\(=\left[\frac{2}{3x}-\frac{2}{x+1}\left(\frac{x+1}{3x}-\frac{3x^2}{3x}-\frac{3x}{3x}\right)\right].\frac{x}{x-1}\)

\(=\left[\frac{2}{3x}-\frac{2}{x+1}\left(\frac{x+1-3x^2-3x}{3x}\right)\right].\frac{x}{x-1}\)

\(=\left(\frac{2}{3x}-\frac{2}{x+1}.\frac{-3x\left(x+1\right)+\left(x+1\right)}{3x}\right).\frac{x}{x-1}\)

\(=\left(\frac{2}{3x}-\frac{2}{x+1}.\frac{\left(x+1\right)\left(-3x+1\right)}{3x}\right).\frac{x}{x-1}\)

\(=\frac{2}{3x}-\frac{2x\left(-3x+1\right)}{3x}.\frac{x}{x-1}\)

\(=\left(\frac{2+6x-2}{3x}\right).\frac{x}{x-1}\)

\(=\frac{6x}{3x}.\frac{x}{x-1}\)

\(=\frac{2x}{x-1}=VP\)

Vậy đẳng thức được chứng minh . 

CÂU B  LÀM tt NHÉ

\(\left(x-1\right)^2+\left|x^2-1\right|=0.\)

Vì \(\hept{\begin{cases}\left(x-1\right)^2\ge0\\\left|x^2-1\right|\ge0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x-1=0\\x^2-1=0\end{cases}\Rightarrow x=1}\)

khó quá

xin loi to h cau 3 lan het luot roi\

de mai nha