`-2/4 = 1/(x-1)`

`=> -2(x-1)=4.1`

`=> -2(x-1)=4`

`=> x-1=4:(-2)`

`=> x-1=-2`

`=>x=-2+1`

`=>x=-1`

\(2^{x+3}.2=2^2.3+52\)

\(=>2^{x+3}.2=64\)

\(=>2^{x+3}=64:2\)

\(=>2^{x+3}=32\)

\(=>2^{x+3}=2^5\)

=>x+3=5

=>x=5-3

=>x=2

Vậy ...........

 2^{x + 3} . 2 = 2² . 3 + 52

 2^{x + 3} . 2 = 4 . 3 + 52

 2^{x + 3} . 2 = 12 + 52

 2^{x + 3} . 2 = 64

     2^{x + 3}  = 64 : 2

     2^{x + 3}  = 32

     2^{x + 3} = 2⁵

     x + 3 = 5

           x = 5 - 3

           x = 2

Vậy x = 2

`x/2=2/x`

`=>x.x=2.2`

`=>x^2=4`

`=>x=+-2`

\(\dfrac{2\text{x}-1}{3}=\dfrac{3\text{x}+1}{4}\)

\(\Leftrightarrow=\dfrac{4\left(2\text{x}-1\right)}{12}=\dfrac{3\left(3\text{x}+1\right)}{12}\)

\(\Leftrightarrow8\text{x}-4=9\text{x}+3\)

\(\Leftrightarrow8\text{x}-9\text{x}=3+4\)

\(\Leftrightarrow-x=7\)

\(\Leftrightarrow x=-7\)

`(2x-1)/3 = (3x+1)/4`

`=> (2x-1).4= 3.(3x+1)`

`=> 8x -4= 9x+3`

`=> 8x-9x =3+4`

`=> -x=7`

`=>x=-7`

\(\dfrac{-1}{4}< \dfrac{x}{24}< \dfrac{-1}{6}\\ \dfrac{-6}{24}< \dfrac{x}{24}< \dfrac{-4}{24}\\ \Rightarrow x=-5\)

\(\dfrac{-1}{4}< \dfrac{x}{24}< \dfrac{-1}{6}\)
\(\Rightarrow\dfrac{-6}{24}< \dfrac{x}{24}< \dfrac{-4}{24}\)
\(\Rightarrow-6< x< -4\)
\(\Rightarrow x=-5\)

`(-1)/4 < x/24 < (-1)/6`

`(-6)/24 < x/24 < (-4)/24`

`->x=-5`

1/4×2/6×3/8×4/10×...×14/30×15/32=1/2^x

<=>1/(2×2)×2/(2×3)×...×14/(2×15)×15/2^5=1/2^x

<=>1/2×1/2×...×1/2×1/(2^5)=1/2^x

<=>1/2^19=1/2^x=>x=19

Đề mình không ghi lại nhé.

^{\(\Rightarrow\frac{1\times2\times3\times4\times...\times14\times15}{4\times6\times10\times...\times30\times32}=\frac{1}{2^x}\)}\(\frac{1}{2^x}\)

\(\Rightarrow\frac{1\times2\times3\times4\times...\times14\times15}{2\times4\times6\times8\times10\times...\times30\times32}\)\(=\frac{1}{2^{x+1}}\)

\(\Rightarrow\frac{1}{2^{15}\times32}=\)\(\frac{1}{2^{x+1}}\)

\(\Rightarrow2^{15}\times2^5=2^{x+1}\)

\(\Rightarrow2^{20}=2^{x+1}\)

\(\Rightarrow x+1=20\Rightarrow x=19\)

Vậy \(x=1\)

Học tốt nhaaa!

Vậy x = 19 nha cậu ơi! Lỗi kỹ thuật xíu!

a)   \(\left(x+3\right)^3-x.\left(3x+1\right)^2+\left(2x+1\right).\left(4x^2-2x+1\right)-3x^2=54\)

\(\Leftrightarrow x^3+9x^2+27x+27-x.\left(9x^2+6x+1\right)+8x^3+1-3x^2=54\)

\(\Leftrightarrow x^3+9x^2+27x+27-9x^3-6x^2-x+8x^3+1-3x^2=54\)

\(\Leftrightarrow26x+28=54\Leftrightarrow26x=54-28\Leftrightarrow26x=26\Leftrightarrow x=1\)

Vậy nghiệm của phương trình là x=1

b)   \(\left(x-3\right)^3-\left(x-3\right).\left(x^2+3x+9\right)+6.\left(x+1\right)^2+3x^2=-33\)

\(\Leftrightarrow x^3-9x^2+27x-27-\left(x^3-27\right)+6.\left(x^2+2x+1\right)+3x^2=-33\)

\(\Leftrightarrow x^3-9x^2+27x-27-x^3+27+6x^2+12x+6+3x^2=-33\)

\(\Leftrightarrow27x+12x+6=-33\Leftrightarrow39x=-33-6\Leftrightarrow39x=-39\Leftrightarrow x=-1\)

Vậy nghiệm của phương trình là x = -1

Trần Anh: Hí hí =)) ÀI LỚP DIU CHIU CHIU CHÍU :3 CẢM ƠN PẠN NHIỀU NHÁ ;) ;) ;)