x+30%x=-1,31
x+30%x=-1,31
x + \(\frac{3}{10}\)x - -1,31
x . ( \(1\)+ \(\frac{3}{10}\)) = -1,31
x . \(\frac{13}{10}\)= -1,31
x = -1,31 : \(\frac{13}{10}\)
x = \(\frac{-131}{130}\)
ai tốt bụng thì tk cho mk nha, mk đg âm điểm nè
\(\frac{-131}{130}\)bạn nha
CHÚC BẠN HỌC GIỎI
x+30%x=-1,31
\(x+30\%x=-1,31\\ x+\dfrac{3}{10}x=-1\dfrac{31}{100}\\ x\cdot\left(1+\dfrac{3}{10}\right)=-\dfrac{131}{100}\\ x\cdot\dfrac{13}{10}=-\dfrac{131}{100}\\ x=-\dfrac{131}{100}:\dfrac{13}{10}=\dfrac{-131}{100}\cdot\dfrac{10}{13}=-\dfrac{131}{130}\)
x+30%x=-1,31
x + 30%x = - 1,31
1,3 x = - 1,31
x = -131/130
x + 30% x = -1,31
<=> x + 3/10 x = -32/31
<=>1x + 3/10 x=-32/31
<=> 10/10 x + 3/10 x = -32/31
<=> x . 13/10 = -32/31
=> x= -32/31 : 13/10=.....?
Tìm x:
x + 30% x = -1,31
Ta có: x(1+30%)=-1,31
⇒ \(\dfrac{13}{10}\)x =-1,31
⇒ x =-1,31 : \(\dfrac{13}{10}\)
⇒ x = -\(\dfrac{131}{130}\)
x + 30% x = -1,31
\(x+\dfrac{30}{100}x=-1,31\)
x+0,3x=-1,31
x.(0,3+1)=-1,31
x.1,3=-1,31
\(x=\dfrac{-1,31}{1,3}\)
\(x=-\dfrac{131}{130}\)
x + 30%x = -1,31
tìm x
x+30%x=-1,31
<=> x(0.3+1)=-1,31
<=> X=\(\frac{-1,31}{1,3}\)
<=>x.(1+30%)=-1,31
<=>x.1,31=-1,31
<=>x=-1
\(x+30\%x=-1,31\)
\(\Leftrightarrow x+\dfrac{30}{100}x=-1,31\)
\(\Leftrightarrow\dfrac{13}{10}x=-1,31\)
\(\Leftrightarrow x=-\dfrac{131}{130}\)
a)x+30%x=-1,31
b)x+3/-15=1/3
Ta có: x + 30 % x = -131/100
x ( 1 + 30%) = -131/100
x 13/10=-131/100
x = -131/100 ; 13/10
x = -131/130
b) )x+3/-15=1/3
x = 1/3 -3/-15
x= 8/15
=> x = \(\frac{8}{15}\)
Ta có: x + 30 % x = -131/100
x ( 1 + 30%) = -131/100
x 13/10=-131/100
x = -131/100 ; 13/10
x = -131/130
Ta có: x + 30 % x = -131/100
x ( 1 + 30%) = -131/100
x 13/10=-131/100
x = -131/100 ; 13/10
x = -131/130
x + \(\dfrac{30}{100}\).x=-1,31
\(x+\dfrac{30}{100}.x=-1,31\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\left(1+\dfrac{30}{100}\right)=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\left(\dfrac{100}{100}+\dfrac{30}{100}\right)=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ x.\dfrac{26}{20}=\dfrac{-131}{100}\\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ \\\\ \\ x=\dfrac{-131}{100}:\dfrac{26}{20}=\dfrac{-131}{100}.\dfrac{20}{26}\\ \\ \\ \\ \\ \\ \\ \\ \\\\ \\ x=\dfrac{-131}{130}\)
coi chừng mình làm sai nhưng trinh bày mình đúng nhưng cẩn thận kết quả. nhé bye
x+\(\dfrac{30}{100}\).x=-1,31
x+0,3.x=-1,31
x.(0,3+1)=-1,31
x.1,3=-1,31
x=-1,31:1,3
x=\(\dfrac{-131}{130}\)
Vậy x=\(\dfrac{-131}{130}\)
Chúc bạn học tốt nha
x+\(\dfrac{30}{100}\).x=-1,31
x.1+\(\dfrac{30}{100}\)x=\(\dfrac{-131}{100}\)
x(1+\(\dfrac{30}{100}\))=\(\dfrac{-131}{100}\)
x(\(\dfrac{100}{100}\)+\(\dfrac{30}{100}\))=\(\dfrac{-131}{100}\)
x.\(\dfrac{130}{100}\)=\(\dfrac{-131}{100}\)
x=\(\dfrac{-131}{100}\):\(\dfrac{130}{100}\)
x=\(\dfrac{130}{100}\).\(\dfrac{100}{131}\)
x=\(\dfrac{100.130}{131.100}\)
x=\(\dfrac{130.1}{131.1}\)
x=\(\dfrac{130}{131}\)
a) x+30% x = -1,31
b) ((x-1/2) : 1/3+5/7=9 và 5/7
\(x+\frac{3}{10}x=-\frac{131}{100}\)
\(x.\left(1+\frac{3}{10}\right)=-\frac{131}{100}\)
\(x.\frac{13}{10}=-\frac{131}{100}\)
\(x=-\frac{131}{100}:\frac{13}{10}\)
\(x=-\frac{131}{130}\)
x + 30% = 1,31
ai nhanh nhất mình tích 2 tick