tim x:
(x-1)2016+(x-2)2016=1
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Tinh gia tri bieu thuc
1/(2016^-2016+1)+1/(2016^-2015+1)+.....+1/(2016^-1+1)+1/(2016^0+1)+1/(2016^1+1)+....+1/(2016^2016+1)
2. Tim bo 3 so nguyen duong a,b,c biet
ac=b(a-b+c) và 1/a+1/b+1/c=1
3. Tim cac cap so thuc x,y co tich la 1 sao cho
(x+y-2)/4=1/(x-1)+1/(y-1)
Tim x de bieu thuc A =(x^2016+1)(| x |+2017)(x+2016)^2(x-3) nhan gia tri khong am
Ta có A nhận giá trị không âm => A>=0
Mà x^2016+1 >= 0
|x|+2017 >= 0
(x+2016)^2 >= 0
Suy ra x+3 >= 0
=> x >= 3
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Tim x,y,z biet (x +1)^2016 + (2y - 1)^2016 + |x + 2y - z |^2017
tim x : 1/3+1/6 +1/10 + .... +2/x(x+1) = 2016/2018
\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+.........+\dfrac{2}{x\left(x+1\right)}=\dfrac{2016}{2017}\)
\(\Leftrightarrow\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{20}+........+\dfrac{2}{x\left(x+1\right)}=\dfrac{2016}{2017}\)
\(\Leftrightarrow\dfrac{2}{2.3}+\dfrac{2}{3.4}+\dfrac{2}{4.5}+..........+\dfrac{2}{x\left(x+1\right)}=\dfrac{2016}{2018}\)
\(\Leftrightarrow2\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......+\dfrac{1}{x}-\dfrac{1}{x+1}\right)=\dfrac{2016}{2018}\)
\(\Leftrightarrow2\left(\dfrac{1}{2}-\dfrac{1}{x+1}\right)=\dfrac{2016}{2018}\)
\(\Leftrightarrow\dfrac{1}{2}-\dfrac{1}{x+1}=\dfrac{1008}{2018}\)
\(\Leftrightarrow\dfrac{1}{x+1}=\dfrac{1}{2018}\)
\(\Leftrightarrow x+1=2018\)
\(\Leftrightarrow x=2017\)
Vậy ..
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\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{2016}{2018}\)
\(\dfrac{2}{6}+\dfrac{2}{12}+\dfrac{2}{20}+...+\dfrac{2}{x\left(x+1\right)}=\dfrac{1008}{1009}\)
\(2.\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+...+\dfrac{1}{x\left(x+1\right)}\right)=\dfrac{1008}{1009}\)
\(2.\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{x\left(x+1\right)}\right)=\dfrac{1008}{1009}\)
\(2.\left(\dfrac{1}{2}-\dfrac{1}{x-1}\right)\) = \(\dfrac{1008}{1009}\)
\(\dfrac{1}{2}-\dfrac{1}{x-1}=\dfrac{504}{1009}\)
\(\dfrac{1}{x-1}=\dfrac{1}{2018}\)
\(x-1=2018\)
\(x=2019\)
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tim GTNN cua /x+1/+/x+2/+/x+3/+/x+4/+2016
Tim x; (1/2+ 1/3+ ...+1/2016).x=2015/1+ 2014/2+ ... +1/2015
tim x
|x+1|+|x+2|+|x+3|+...+|x+2016|=2015x
1/2+1/6+1/12+1/20+...+1/x[x+1]=2015/2016
tim x
VẾ TRÁI LÀ:
A=1/2.3+1/3.2+1/4.5+...+1/x[x+1]
A=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/n-1/n+1
A=1-1/n+1
1-1/n+1=2015/2016
1/n+1=1-2015/2016
1/n+1=1/2016
n=2016-1
n=2015
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Vế trái là
S=1/2+1/6+1/12+1/20+..+1/x(x+1)
S=1/1.2+1/2.3+1/3.4+1/4.5+...+1/x.(x+1)
S=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+...+1/x.(x+1)
S=1-1/(x+1)=Vế phải=2015/2016
<=>1-1/(x+1)=2015/2016
1/(x+1)=1/2016
=>x+1=2016
x=2015
Ủng hộ mk mha Chí Tiến
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Tim x thuoc N biet ( x - 2 )^2016 + /x -3/=1
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