Gọi tuổi mẹ là x

=>Tuổi con là x/3

Theo đề, ta có: x/3+4=9/23(x+4)

=>x/3+4=9/23x+36/23

=>x=42

Đặt B = \(\frac{3}{1.8}+\frac{3}{8.15}+...+\frac{3}{106.113}\)

\(\frac{7}{3}B=\frac{7}{1.8}+\frac{7}{8.15}+...+\frac{7}{106.113}\)

\(\frac{7}{3}B=1-\frac{1}{8}+\frac{1}{8}-\frac{1}{15}+....+\frac{1}{106}-\frac{1}{113}\)

\(\frac{7}{3}B=1-\frac{1}{113}=\frac{112}{113}\)

\(B=\frac{48}{113}\)

Đặt \(C=\frac{25}{50.55}+\frac{25}{55.60}+...+\frac{25}{95.100}\)

\(\frac{1}{5}C=\frac{5}{50.55}+\frac{5}{55.60}+....+\frac{5}{95.100}\)

\(\frac{1}{5}C=\frac{1}{50}-\frac{1}{55}+\frac{1}{55}-\frac{1}{60}+....+\frac{1}{95}-\frac{1}{100}\)

\(\frac{1}{5}C=\frac{1}{50}-\frac{1}{100}=\frac{1}{100}\)

\(C=\frac{1}{20}\)

\(\Rightarrow A=\frac{48}{113}-\frac{1}{20}=\frac{847}{2260}\)

HT

2 A

3 D

4 A

5 A

6 B

7 A

8 A

9 A

Đổi 60 km = 60 000 m

Thời gian :

\(t=\dfrac{s}{v}=\dfrac{60000}{20}=3000\left(s\right)=50'\)

Chonj C

Lời giải:

\(H=2-\frac{3}{17}-\frac{5}{23}+\frac{2}{17}-\frac{1}{2023}-\frac{16}{17}-\frac{18}{23}\\ =2-(\frac{3}{17}-\frac{2}{17}+\frac{16}{17})-(\frac{5}{23}+\frac{18}{23})-\frac{1}{2023}\\ =2-1-1-\frac{1}{2023}=-\frac{1}{2023}\)

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\(K=\frac{7}{23}.\frac{-11}{17}+\frac{7}{23}.\frac{4}{17}-\frac{7}{23}.\frac{10}{17}\\ =\frac{7}{23}(\frac{-11}{17}+\frac{4}{17}-\frac{10}{17})\\ =\frac{7}{23}.\frac{-17}{17}=\frac{-7}{23}\)

1 D

2 C

3 A

4 C

5 D

1. D

2. C 

3. A 

4. C

5. A

1.D

2.C 

3.A 

4.C

5.D

1. B

2. A

3. A

4. B 

5. C

6. B

7. B

8. D

9. C

10. D

nó vẫn dài quá ấy bạn, mik làm một bài trong đó thôi đã vật vã lắm r =((