\(a)n_{H_2}=\dfrac{6,72}{22,4}=0,3mol\\ 2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\\ 0,2\leftarrow-0,3\leftarrow-0,1\leftarrow---0,3\)

\(a=m_{Al}=0,2.27=5,4g\\ b)m_{Al_2\left(SO_4\right)_3}=0,1.342=34,2g\\ c)C_{\%H_2SO_4}=\dfrac{0,3.98}{100}\cdot100=29,4\%\)

a)nH2​​=22,46,72​=0,3mol2Al+3H2​SO4​→Al2​(SO4​)3​+3H2​0,2←−0,3←−0,1←−−−0,3

�=���=0,2.27=5,4��)���2(��4)3=0,1.342=34,2��)�%�2��4=0,3.98100⋅100=29,4%a=mAl​=0,2.27=5,4gb)mAl2​(SO4​)3​​=0,1.342=34,2gc)C%H2​SO4​​=1000,3.98​⋅100=29,4%

\(Pt: 2Al+3H_2SO_4 \rightarrow Al_2(SO_4)_3 + 3H_2\)

\(a.n_{H_2}=\dfrac{6,72}{22,4}=0,3\left(mol\right)\)

Theo pt: \(n_{Al}=\dfrac{2}{3}n_{H_2}=0,2\left(mol\right)\)

\(\Rightarrow m_{Al}=a=0,2.27=5,4\left(g\right)\)

\(b.n_{Al_2\left(SO_4\right)_3}=\dfrac{1}{3}n_{H_2}=0,1\left(mol\right)\)

\(\Rightarrow m_{Al_2\left(SO_4\right)_3}=0,1.342=34,2g\)

\(c.\)Theo pt: \(n_{H_2SO_4}=n_{H_2}=0,3\left(mol\right)\)

\(\Rightarrow m_{H_2SO_4}=0,3.98=29,4g\)

\(C_{\%}H_2SO_4=\dfrac{29,4}{100}.100\%=29,4\%\)

a) \(Pt:Fe+H_2SO_4\rightarrow FeSO_4+H_2\)

b) \(n_{Fe}=\dfrac{0,56}{56}=0,01mol\)

Theo pt: \(n_{FeSO_4}=n_{Fe}=0,01mol\)

\(\Rightarrow m_{FeSO_4}=0,01.152=1,52g\)

Theo pt: \(n_{H_2}=n_{Fe}=0,01mol\)

\(\Rightarrow V_{H_2}=0,01.22,4=0,224lít\)

c) \(Theopt:nH_2SO_4=n_{Fe}=0,01mol\)

\(\Rightarrow m_{H_2SO_4}=0,01.98=0,98g\)

\(\Rightarrow m_{ddH_2SO_4}=\dfrac{0,98.100}{19,6}=5g\)

Bài 1:

H2 + O2 → H2O

N2O5 + H2O → HNO3

Bài 4:

Fe2(SO3)3: Sắt III sunfat 

Mg(OH)2: Magie hidroxit

H3PO4: axit photphoric

Ba(HSO4)2: Bari Bisunfat 

Bài 1 : 

\(a.2H_2+O_2\underrightarrow{^{t^0}}2H_2O\)

\(b.N_2O_5+H_2O\rightarrow2HNO_3\)

Bài 2 : 

\(n_{Al}=\dfrac{5.4}{27}=0.2\left(mol\right)\)

\(2Al+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2\)

\(0.2............0.3...........0.1..............0.3\)

\(m_{H_2SO_4}=0.3\cdot98=29.4\left(g\right)\)

\(m_{Al_2\left(SO_4\right)_3}=0.1\cdot342=34.2\left(g\right)\)

\(m_{H_2}=0.3\cdot2=0.6\left(g\right)\)

\(V_{H_2}=0.3\cdot22.4=6.72\left(l\right)\)

Bài 3 : 

\(n_{A\left(OH\right)_n}=0.2\cdot1=0.2\left(mol\right)\)

\(2A+2nH_2O\rightarrow2A\left(OH\right)_n+nH_2\)

\(0.2........................0.2\)

\(M_A=\dfrac{8}{0.2}=40\left(\dfrac{g}{mol}\right)\)

\(A:Canxi\:\)

Bài 4 : 

Fe₂(SO₄)₃ : Sắt (III) sunfat 

Mg(OH)₂ : Magie hidroxit

H₃PO₃: Axit photphoro

Ba(HSO₄)₂: Bari hidrosunfat

\(Zn+2HCl\rightarrow ZnCl_2+H_2\)

\(Zn+H_2SO_4\rightarrow ZnSO_4+H_2\)

\(3Zn+2H_3PO_4\rightarrow Zn_3\left(PO_4\right)_2+3H_2\)

1) Fe + H₂SO₄ --> FeSO₄ + H₂

2) Zn + 2HCl --> ZnCl₂ + H₂

3) 2Al + 3H₂SO₄ --> Al₂(SO₄)₃ + 3H₂

4) Zn + H₂SO₄ --> ZnSO₄ + H₂

5) Mg + 2HCl --> MgCl₂ + H₂

6) H₂ + CuO --t^o--> Cu + H₂O

7) 2H₂ + O₂ --t^o--> 2H₂O

`->` Đáp án + Giải thích:

1) Fe + H₂SO₄ --> FeSO₄ + H₂

2) Zn + 2HCl --> ZnCl₂ + H₂

3) 2Al + 3H₂SO₄ --> Al₂(SO₄)₃ + 3H₂

4) Zn + H₂SO₄ --> ZnSO₄ + H₂

5) Mg + 2HCl --> MgCl₂ + H₂

6) H₂ + CuO --t^o--> Cu + H₂O

7) 2H₂ + O₂ --t^o--> 2H₂O

1 ) Fe + H2SO4 ---> FeSO4 + H2 
2 ) Zn+2HCl ---> ZnCl2 + H2 
3 ) 2Al + 3H2SO4 l ---> Al2(SO4)3 +3H2
4) Zn + H2SO4 --> ZnSO4 +H2 
5) Mg + 2HCl --> MgCl2 + H2 
6 ) H2 +CuO -t---> Cu +H2O 
7 ) 2H2 + O2 -----> 2H2O

a)

\(BaCl_2+K_2SO_4\rightarrow BaSO_4+2KCl\\ BaCl_2+H_2SO_4\rightarrow BaSO_4+2HCl\)

b)

\(Ba\left(NO_3\right)_2+Na_2SO_4\rightarrow BaSO_4+2NaNO_3\\ CO_2+Ca\left(OH\right)_2\rightarrow CaCO_3+H_2O\)

Sửa đề : oxi -> Ca

n_Ca=m/M=24/40=0,6(mol)

PT: Ca +H₂SO₄ -> CaSO₄ +H₂

vậy: 0,6--->0,6-------->0,6--->0,6(mol)

=> V_H2=n.22,4=0,6.22,4=13,44(lít)

b) m_H2SO4=n.M=0,6.98=58,8(g)

c) m_CaSO4=n.M=0,6.136=81,6(g)

bạn ơi tại sao cho oxi t/d vói H2SO4 ma tạo ra CaSO4

Chắc đề là cho 24 (g) Ca thì làm như sau :

nCa=24/40=0,6(mol)

pt: Ca+H2SO4--->CaSO4+H2

Theo pt : nH2=nH2SO4=nCaSO4=nCa=0,6(mol)

=>VH2=0,6.22,4=13,44(l0

=>mH2SO4=0,6.98=58,8(g)

=>mcaSO4=0,6.136=81,6(g)

p/s: Chúc bạn học tốt ...^^

CH4+2 O2  ---to-->.......CO2+2H2O

4P + 5O2--to---->...2P2O5.....

SO3+H2O...-------> H2SO4

P2O5+3H2O->2H3PO4

2KMnO4 ---to----->......K2MNO4...+......MnO2..+..O2.....

2KClO3-------->..2KCl.......+...3.O2...

\(CH_4+2O_2\underrightarrow{t^o}CO_2+2H_2O\\ 4P+5O_2\underrightarrow{t^o}2P_2O_5\\ P_2O_5+3H_2O\rightarrow2H_3PO_4\\ 2KMnO_4\underrightarrow{t^o}K_2MnO_4+MnO_2+O_2\\ 2KCl\xrightarrow[xtMnO_2]{t^o}2KCl+3O_2\)