\(x\cdot3:x+2\cdot6:4+x:0,5+0,25+x\cdot1=35\)

=>\(3+3+2x+0,25+x=35\)

=>3x+6,25=35

=>3x=35-6,25=28,75

=>\(x=\dfrac{28.75}{3}=\dfrac{115}{12}\)

địt mẹ mày đừng dùng olm như cặc

câu trả lời : anbatukam

\(x\times3\) : \(x\) + 2 \(\times\) 6 : 4 + \(x\) : 0,5 + 0,25 + \(x\) \(\times\) 1 = 35

        3 + 3 + \(x\) x 2 + 0,25 + \(x\) = 35

   (3 + 3 + 0,25) + (\(x\times2\) + \(x\)) = 35 

                 6,25 + \(x\) \(\times\) (2 + 1) = 35

                 6,25 + \(x\) \(\times\) 3         = 35

                            \(x\times\) 3           = 35 - 6,25

                            \(x\times\) 3          = 28,75

                              \(x\)             = 28,75 : 3

                               \(x\)            = \(\dfrac{115}{12}\)

1, (0,25 - \(x\)) : - \(\dfrac{3}{5}\) = - \(\dfrac{3}{4}\)

    0,25 - \(x\)           = - \(\dfrac{3}{4}\) x (- \(\dfrac{3}{5}\))

     0,25 - \(x\)           = \(\dfrac{9}{20}\)

                \(x\)          = 0,25 - 0,45 

                \(x\)          = - 0,2 

2, - \(\dfrac{3}{8}\)\(x\) - 0,75 = - 1\(\dfrac{1}{2}\)

    - \(\dfrac{3}{8}\)\(x\) - 0,75  = -1,5

       \(\dfrac{3}{8}\)\(x\)             = - 0,75 + 1,5

       \(\dfrac{3}{8}\)\(x\)            =  0,75

          \(x\)            = 0,75 : \(\dfrac{3}{8}\)

          \(x\)           =   2

3, \(\dfrac{3}{5}\)\(x\) + \(\dfrac{2}{3}\) = 2\(\dfrac{2}{3}\)

     \(\dfrac{3}{5}\)\(x\) + \(\dfrac{2}{3}\) = \(\dfrac{8}{3}\)

     \(\dfrac{3}{5}\)\(x\)        = \(\dfrac{8}{3}\) - \(\dfrac{2}{3}\)

      \(\dfrac{3}{5}\)\(x\)       = 2

         \(x\)        = 2 : \(\dfrac{3}{5}\)

          \(x\)       = \(\dfrac{10}{3}\)

=15

4 × 25 × 0,25 × \(\dfrac{1}{5}\) × \(\dfrac{1}{2}\) × 6

= 100 × 0,25 × 0,2 × 0,5 x 6

= 25 × 0,1 × 6

= 2,5 × 6

= 15

1: \(\Leftrightarrow\dfrac{3x-1}{x+2}=4\)

=>4x+8=3x-1

=>x=-9

2: \(\Leftrightarrow\dfrac{5x-7}{2x-1}=4\)

=>8x-4=5x-7

=>3x=-3

=>x=-1

3: ĐKXD: x>=0

\(PT\Leftrightarrow\left(\sqrt{x}-2\right)\left(\sqrt{x}+3\right)=\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)\)

=>\(x+\sqrt{x}-6=x-1\)

=>căn x=-1+6=5

=>x=25

4: ĐKXĐ: x>=0

PT =>\(\left(\sqrt{x}-3\right)\left(\sqrt{x}+1\right)=\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)\)

=>x-2*căn x-3=x-4

=>-2căn x-3=-4

=>2căn x+3=4

=>2căn x=1

=>căn x=1/2

=>x=1/4

Đề là \(x_1\left(x_1^2-1\right)-x_1\left(8x_2^2+1\right)=5\) hay \(x_2\left(x_1^2-1\right)-x_1\left(8x_2^2+1\right)=5\) hay \(x_2\left(x_1^2-1\right)+x_1\left(8x_2^2-1\right)=5\)

Nhìn đề của bạn thấy nghi ngờ quá

\(\Delta=25-4\left(4-9m\right)>0\Rightarrow36m+9>0\Rightarrow m>-\frac{1}{4}\)

\(\left\{{}\begin{matrix}x_1+x_2=-5\\x_1x_2=4-9m\end{matrix}\right.\)

\(x_1\left(x_1^2-1\right)-x_2\left(8x_2^2-1\right)=5\)

\(\Leftrightarrow x_1^3-8x_2^3-\left(x_1+x_2\right)=5\)

\(\Leftrightarrow x_1^3-8x_2^3+5=5\)

\(\Leftrightarrow x_1^3-8x_2^3=0\Rightarrow x_1^3=\left(2x_2\right)^3\Rightarrow x_1=2x_2\)

Kết hợp Viet: \(\left\{{}\begin{matrix}x_1+x_2=-5\\x_1=2x_2\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}3x_2=-5\\x_1=2x_2\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x_2=-\frac{5}{3}\\x_1=-\frac{10}{3}\end{matrix}\right.\)

\(x_1x_2=4-9m\Rightarrow4-9m=\frac{50}{9}\Rightarrow m=-\frac{14}{81}\) (t/m)

1: \(\Leftrightarrow2x^2-10x-3x-2x^2=0\)

=>-13x=0

=>x=0

2: \(\Leftrightarrow5x-2x^2+2x^2-2x=13\)

=>3x=13

=>x=13/3

3: \(\Leftrightarrow4x^4-6x^3-4x^3+6x^3-2x^2=0\)

=>-2x^2=0

=>x=0

4: \(\Leftrightarrow5x^2-5x-5x^2+7x-10x+14=6\)

=>-8x=6-14=-8

=>x=1

`1)2x(x-5)-(3x+2x^2)=0`

`<=>2x^2-10x-3x-2x^2=0`

`<=>-13x=0`

`<=>x=0`

___________________________________________________

`2)x(5-2x)+2x(x-1)=13`

`<=>5x-2x^2+2x^2-2x=13`

`<=>3x=13<=>x=13/3`

___________________________________________________

`3)2x^3(2x-3)-x^2(4x^2-6x+2)=0`

`<=>4x^4-6x^3-4x^4+6x^3-2x^2=0`

`<=>x=0`

___________________________________________________

`4)5x(x-1)-(x+2)(5x-7)=0`

`<=>5x^2-5x-5x^2+7x-10x+14=0`

`<=>-8x=-14`

`<=>x=7/4`

___________________________________________________

`5)6x^2-(2x-3)(3x+2)=1`

`<=>6x^2-6x^2-4x+9x+6=1`

`<=>5x=-5<=>x=-1`

___________________________________________________

`6)2x(1-x)+5=9-2x^2`

`<=>2x-2x^2+5=9-2x^2`

`<=>2x=4<=>x=2`

a: =>3,6-x+0,5=3,5-0,75+x

=>4,1-x=x+2,75

=>-2x=-1,35

=>x=0,675

b: =>5x^2-5x+x-1=0

=>(x-1)(5x+1)=0

=>x=1 hoặc x=-1/5

c: \(\Leftrightarrow\left(\dfrac{2-x}{2008}+1\right)=\left(\dfrac{1-x}{2009}+1\right)+\left(1-\dfrac{x}{2010}\right)\)

=>\(2010-x=0\)

=>x=2010