A = ( 3/8+ -1/4+ 5/12) /7/8
1.tính A.-5/8-7/-12 B.3/4+(-5)/6-11/-12 C.1/6-1/36 D.15/48-(-5)/12 E.-1/7-1/8 F.-5/15-(-3)/25 G.3/4-(-5)/12-7/-24
a: \(=\dfrac{-5}{8}+\dfrac{7}{12}=\dfrac{-15}{24}+\dfrac{14}{24}=\dfrac{-1}{24}\)
b: \(=\dfrac{3}{4}-\dfrac{5}{6}+\dfrac{11}{12}=\dfrac{9}{12}-\dfrac{10}{12}+\dfrac{11}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)
c: \(=\dfrac{6}{36}-\dfrac{1}{36}=\dfrac{5}{36}\)
d: \(=\dfrac{5}{12}+\dfrac{5}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)
e: \(=\dfrac{-8}{56}-\dfrac{7}{56}=\dfrac{-15}{56}\)
f: \(=\dfrac{-5}{15}+\dfrac{3}{25}=\dfrac{-25}{75}+\dfrac{9}{75}=\dfrac{-16}{75}\)
Bài 1: Thời gian giải một bài toán của 50 học sinh lớp 7 được ghi lại trong bảng sau:
10 | 3 | 4 | 7 | 8 | 11 | 12 | 4 | 7 | 8 |
12 | 4 | 7 | 8 | 10 | 12 | 8 | 7 | 10 | 12 |
6 | 6 | 8 | 8 | 12 | 11 | 10 | 12 | 11 | 10 |
6 | 7 | 10 | 5 | 8 | 7 | 8 | 9 | 7 | 9 |
6 | 7 | 6 | 9 | 7 | 5 | 12 | 4 | 5 | 12 |
a)Dấu hiệu cần tìm hiểu ở đây là gì? Số các giá trị của dấu hiệu?
b)Lập bảng tần số và tính số trung bình cộng. Tìm mốt của dấu hiệu.
c)Rút ra nhận xét.
a: Dấu hiệu là thời gian giải bài
Số các giá trị là 10
b:
Mốt là 7 và 8
c: Phần lớn làm xong trong 7 hoặc 8 phút
tính :
a) 4/5 + 2/3 + 1/9
b) 3/7 + 11/14 + 19/28
c) 1/2 + 1/7 + -1/5
d) 7/8 + 5/16 + -3/4
e) 1/4 + 5/12 + -1/13
g) 2/3 + 3/8 + -5/12
\(a,\dfrac{4}{5}+\dfrac{2}{3}+\dfrac{1}{9}=\dfrac{12}{15}+\dfrac{10}{15}+\dfrac{1}{9}=\dfrac{22}{15}+\dfrac{1}{9}=\dfrac{66}{45}+\dfrac{5}{45}=\dfrac{71}{45}\)
\(b,\dfrac{3}{7}+\dfrac{11}{14}+\dfrac{19}{28}=\dfrac{12}{28}+\dfrac{22}{28}+\dfrac{19}{28}=\dfrac{53}{28}\)
\(c,\dfrac{1}{2}+\dfrac{1}{7}+\dfrac{-1}{5}=\dfrac{7}{14}+\dfrac{2}{14}+\dfrac{-1}{5}=\dfrac{9}{14}+\dfrac{-1}{5}=\dfrac{45}{70}+\dfrac{-14}{70}=\dfrac{31}{70}\)
\(d,\dfrac{7}{8}+\dfrac{5}{16}+\dfrac{-3}{4}=\dfrac{14}{16}+\dfrac{5}{16}+\dfrac{-12}{16}=\dfrac{7}{16}\)
\(e,\dfrac{1}{4}+\dfrac{5}{12}+\dfrac{-1}{13}=\dfrac{3}{12}+\dfrac{5}{12}+\dfrac{-1}{13}=\dfrac{8}{12}+\dfrac{-1}{13}=\dfrac{2}{3}+\dfrac{-1}{13}=\dfrac{26}{39}+\dfrac{-3}{39}=\dfrac{23}{39}\)
\(g,\dfrac{2}{3}+\dfrac{3}{8}+\dfrac{-5}{12}=\dfrac{16}{24}+\dfrac{9}{24}+\dfrac{-5}{12}=\dfrac{25}{24}+\dfrac{-5}{12}=\dfrac{25}{24}+\dfrac{-10}{24}=\dfrac{15}{24}\)
Tính A) 3/7+4/9+4/7+7/11
B) 1/8+1/12+3/8+5/12
\(A=\frac{3}{7}+\frac{4}{9}+\frac{4}{7}+\frac{7}{11}\)
\(A=1+\frac{4}{9}+\frac{7}{11}\)
\(A==\frac{76}{33}\)
\(B=\frac{1}{8}+\frac{1}{12}+\frac{3}{8}+\frac{5}{12}\)
\(B=\frac{1}{2}+\frac{1}{2}\)
\(B=\frac{1}{4}\)
a 5/6*7/12+5/12*5/6+1/6
b (8/15*3/4*5/4):7/8
\(\frac{5}{6}\cdot\frac{7}{12}+\frac{5}{12}\cdot\frac{5}{6}+\frac{1}{6}\)
\(=\frac{5}{6}\cdot\left(\frac{7}{12}+\frac{5}{12}\right)+\frac{1}{6}\)
\(=\frac{5}{6}\cdot1+\frac{1}{6}\)
\(=\frac{5}{6}+\frac{1}{6}\)
\(=1\)
\(\left(\frac{8}{15}\cdot\frac{3}{4}\cdot\frac{5}{4}\right):\frac{7}{8}\)
\(=\frac{4\cdot2\cdot3\cdot5}{3\cdot5\cdot4\cdot2\cdot2}:\frac{7}{8}\)
\(=\frac{1}{2}:\frac{7}{8}\)
\(=\frac{1}{2}\cdot\frac{8}{7}\)
\(=\frac{4}{7}\)
\(a,\frac{5}{6}.\frac{7}{12}+\frac{5}{12}\cdot\frac{5}{6}+\frac{1}{6}=\frac{5}{6}.\left(\frac{7}{12}+\frac{5}{12}\right)+\frac{1}{6}=\frac{5}{6}.1+\frac{1}{6}=\frac{5}{6}+\frac{1}{6}=\frac{6}{6}=1\)
\(b,\left(\frac{8}{15}.\frac{3}{4}.\frac{5}{4}\right):\frac{7}{8}=\left(\frac{8.3.5}{15.4.4}\right).\frac{8}{7}=\frac{2.4.3.5\cdot4\cdot2}{3.5.4.2.2\cdot7}=\frac{1.1.1.1.4.1}{1\cdot1\cdot1\cdot1\cdot1.7}=\frac{4}{7}\)
mk nha, ai tk mk mk tk lai
a.1/7.-3/8+-13/8
b.3/5.13/40-1/10.16/23
c.(-3/4+2/5):3/7+(3/5+1/4):3/7
d.7/8:(2/9-1/8)+7/8:(1/6-5/12)
e.(-2/3+3/7):4/5+(-1/3+4/7):4/5
Giúp mình với..
\(a.\frac{1}{7}\times\frac{-3}{8}+\frac{-13}{8}==\frac{-3}{56}+\frac{-13}{8}=\frac{-3}{56}+\frac{-91}{56}=\frac{-94}{56}=\frac{-47}{28}\)
\(b.\frac{3}{5}\times\frac{13}{40}-\frac{1}{10}\times\frac{16}{23}=\frac{39}{200}-\frac{8}{115}=\frac{577}{4600}\)
\(c.\left(\frac{-3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{1}{4}\right):\frac{3}{7}\)
\(=\left(\frac{-3}{4}+\frac{2}{5}\right)\times\frac{7}{3}+\left(\frac{3}{5}+\frac{1}{4}\right)\times\frac{7}{3}\)
\(=\frac{7}{3}\times\left(\frac{-3}{4}+\frac{2}{5}+\frac{3}{5}+\frac{1}{4}\right)\)
\(=\frac{7}{3}\times\left[\left(\frac{-3}{4}+\frac{1}{4}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\right]\)
\(=\frac{7}{3}\times\left(\frac{-2}{4}+1\right)\)
\(=\frac{7}{3}\times\frac{1}{2}\)
\(=\frac{7}{6}\)
\(d.\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}\right)+\frac{7}{8}:\left(\frac{1}{6}-\frac{5}{12}\right)\)
\(=\frac{7}{8}:\frac{7}{72}+\frac{7}{8}:\left(\frac{-1}{4}\right)\)
\(=\frac{7}{8}\times\frac{72}{7}+\frac{7}{8}\times-4\)
\(=\frac{7}{8}\times\left(\frac{72}{7}+\left(-4\right)\right)\)
\(=\frac{7}{8}\times\frac{44}{7}\)
\(=\frac{11}{2}\)
a, 2/9 - 7/9 x X = 1/3
b, 4/5 + 5/7 : X = 1/6
c,1/3 + 3/8 - 7/12
d, 3/14 + 5/8 - 1/2
e,1/4 - 2/3 - 11/8
g,1/4 + 5/12 - 1/13 - 7/8
giúp mình với mình cần gấp
2/5+2/3+3/4
2/6+3/12
5/6+1/3
1/3+5/12+5/6
5/8+4/7
1/5+5/35
5/8+3/4
1/6+1/3+1/12
1/6+5/24+2/3
7/3+8/7
2/5+1/6
1/7+1/4+6/7+3/4
giúp với
và ai giải được gọi cụ
\(\dfrac{2}{5}+\dfrac{2}{3}+\dfrac{2}{4}\)
= \(\dfrac{24}{60}\) + \(\dfrac{40}{60}\) + \(\dfrac{30}{60}\)
= \(\dfrac{64}{60}\) + \(\dfrac{30}{60}\)
= \(\dfrac{47}{30}\)
\(\dfrac{2}{6}+\dfrac{3}{12}\)
= \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\)
= \(\dfrac{7}{12}\)
\(\dfrac{5}{6}\) + \(\dfrac{1}{3}\)
= \(\dfrac{5}{6}\) + \(\dfrac{2}{6}\)
= \(\dfrac{7}{6}\)
9/10
17/36
7/6
19/12
67/56
12/35
11/8
7/12
25/24
73/21
17/30
2
ok chưa bạn!
\(\dfrac{1}{3}\) + \(\dfrac{5}{12}\) + \(\dfrac{5}{6}\)
= \(\dfrac{4}{12}\) + \(\dfrac{5}{12}\) + \(\dfrac{10}{12}\)
= \(\dfrac{9}{12}\) + \(\dfrac{10}{12}\)
= \(\dfrac{19}{12}\)
\(\dfrac{5}{8}\) + \(\dfrac{4}{7}\)
= \(\dfrac{35}{56}\) + \(\dfrac{32}{56}\)
= \(\dfrac{67}{56}\)
\(\dfrac{7}{3}\) + \(\dfrac{8}{7}\)
= \(\dfrac{49}{21}\) + \(\dfrac{24}{21}\)
= \(\dfrac{73}{21}\)
\(\dfrac{1}{5}+\dfrac{5}{35}\)
= \(\dfrac{7}{35}\) + \(\dfrac{5}{35}\)
= \(\dfrac{12}{35}\)
Đúng ghi Đ sai ghi S
a) 3/8+4/8=7/8 b) 4/7+3/5 =7/12
c) 5/8+3/5=49/40 d) 2/3+3/4=17/12
a. ( 19 5/8 : 7/12 - 13 1/4 : 7/12) . 4/5
b.( - 2/5 + 3/7) - (4/9 + 12/20 - 13/35) + 7/35
c. ( 4 5/57 - 3/ 4/51 + 8 13/29) - ( 3 5/57 - 6 16/29)
\(\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
\(=\left(\frac{157}{8}:\frac{7}{12}-\frac{53}{4}:\frac{7}{12}\right).\frac{4}{5}\)
\(=\left[\left(\frac{157}{8}-\frac{53}{4}\right):\frac{7}{12}\right].\frac{4}{5}\)
\(=\left[\frac{51}{8}:\frac{7}{12}\right].\frac{4}{5}\)
\(=\frac{153}{14}.\frac{4}{5}\)
\(=\frac{306}{35}\)
\(\left(\frac{-2}{5}+\frac{3}{7}\right)-\left(\frac{4}{9}+\frac{12}{20}-\frac{13}{35}\right)+\frac{7}{35}\)
\(=\frac{1}{35}-\frac{212}{315}+\frac{7}{35}\)
\(=\frac{1}{35}+\frac{-212}{315}+\frac{7}{35}\)
\(=\frac{9}{315}+\frac{-212}{315}+\frac{63}{315}\)
\(=\frac{-140}{315}=\frac{-4}{9}\)
\(\left(4\frac{5}{57}-3\frac{4}{51}+8\frac{13}{29}\right)-\left(3\frac{5}{57}-6\frac{16}{29}\right)\)
\(=\left(\frac{233}{57}-\frac{157}{51}+\frac{245}{29}\right)-\left(\frac{176}{57}-\frac{190}{29}\right)\)
\(=\frac{1941}{323}-\frac{-5726}{1653}\)
\(=\frac{14011}{1479}\)